/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Find the area under \(f(x)\) on ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the area under \(f(x)\) on the indicated interval. Round the area to two decimal places as necessary. $$f(x)=\left\\{\begin{array}{cl} 1.1 x, & 0 \leq x \leq 11 \\ 0, & \text { otherwise } \end{array} \text { on the interval } 5 \leq x \leq 10\right.$$

Short Answer

Expert verified
The area under the curve from \( x=5 \) to \( x=10 \) is 41.25.

Step by step solution

01

Identify the Function and Bounds

The function given is a piecewise function: \( f(x) = 1.1x \) when \( 0 \leq x \leq 11 \) and \( f(x) = 0 \) otherwise. We need to find the area under this function on the interval \( 5 \leq x \leq 10 \).
02

Set up the Integral

To find the area under \( f(x) \) from \( x=5 \) to \( x=10 \), we set up the definite integral \[ \int_{5}^{10} 1.1x \, dx \].
03

Integrate the Function

Calculate the integral of \( f(x) = 1.1x \). The antiderivative of \( 1.1x \) is \( 0.55x^2 \). So, we have \[ \int 1.1x \, dx = 0.55x^2 + C \].
04

Evaluate the Definite Integral

Use the Fundamental Theorem of Calculus to evaluate the integral from \( x=5 \) to \( x=10 \):\[ \left.0.55x^2\right|_{5}^{10} = 0.55(10^2) - 0.55(5^2) \].
05

Simplify and Calculate the Area

Calculate the expression from Step 4:\[ = 0.55(100) - 0.55(25) = 55 - 13.75 = 41.25 \].Thus, the area under the curve on the interval \( 5 \leq x \leq 10 \) is \( 41.25 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piecewise Function
A piecewise function is like a custom-built tool that changes its behavior depending on which part of its domain you are looking at. In this exercise, the function \( f(x) \) is defined as \( 1.1x \) for \( 0 \leq x \leq 11 \) and is zero elsewhere. This means that from \( x = 0 \) to \( x = 11 \), the function behaves like a simple linear equation. Beyond these bounds, whether smaller than 0 or greater than 11, the function simply returns zero. This technique allows for more flexibility in defining functions that can model real-world scenarios better by representing discontinuities or different conditions in different intervals.
Think of piecewise functions like different blocks of code that run depending on certain conditions. Each block or piece is a function defined over a specific interval. They are very useful in modeling situations where a single function cannot describe the behavior entirely.
Area Under a Curve
Finding the area under a curve is akin to summing up an infinite number of tiny rectangles beneath the curve. For this problem, the curve is \( f(x) = 1.1x \) over the interval \( 5 \leq x \leq 10 \). Calculating this area gives us a sense of the total 'accumulated' quantity represented by the function over that interval. This is important in fields such as physics and economics, where these calculations often represent quantities like distance or work.
In practical terms, areas under a curve can be viewed graphically. Imagine graphing \( f(x) \) as a slanting line from \( x = 0 \) to \( x = 11 \). On the segment from \( x = 5 \) to \( x = 10 \), the task is to compute the space between this line and the \( x \)-axis. The challenge in such problems is how the function behaves at the boundaries of the interval, which is where you need to pay careful attention.
Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus (FTC) bridges the concept of differentiation and integration; it tells us that integration is the inverse process of differentiation. When calculating a definite integral, as in the original exercise, we use the FTC to evaluate the integral across the interval \( 5 \leq x \leq 10 \). This theorem allows us to find the exact area under a curve by computing the antiderivative values at the interval's boundaries and subtracting them.
  • The FTC states that if \( F \) is an antiderivative of \( f \), then the integral of \( f \) from \( a \) to \( b \) is \( F(b) - F(a) \).
  • In our case, the antiderivative of \( 1.1x \) is \( 0.55x^2 \), evaluated from 5 to 10.
Using the FTC simplifies the task by avoiding the summation of multiple rectangles and provides a quicker, more accurate result.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the area under \(f(x)\) on the indicated interval. Round the area to two decimal places as necessary. $$f(x)=\left\\{\begin{array}{cl} 14-2 x, & 0 \leq x \leq 7 \\ 0, & \text { otherwise } \end{array} \text { on the interval } 1.5 \leq x \leq 2\right.$$

Make a table of function values using the given discrete domain values. Write the values as ordered pairs and then graph the function. $$F(x)=6-0.3 x^{2}, \quad x=0,1,2,3,4$$

Find the area under \(f(x)\) on the indicated interval. Round the area to two decimal places as necessary. $$f(x)=\left\\{\begin{array}{cl} 1+2.6 x, & 1 \leq x \leq 10 \\ 0, & \text { otherwise } \end{array} \text { on the interval } 4 \leq x \leq 6.7\right.$$

Consider the following scenario: A recent point for discussion has been an increase in the national minimum wage. Joe Roman of the Greater Cleveland Partnership claims that an increase in the minimum wage to \(\$ 15\) per hour in Cleveland would be the "most aggressive minimum wage increase in the country". The annual monthly minimum-wage earnings in the United States from 2007 to 2015 can be modeled by the function $$f(x)=419.9+41.2 x, \quad x=7,8, \ldots, 15$$ where \(x\) represents the number of years since 2000 and \(f(x)\) represents the monthly minimum-wage earning in dollars. Use this function to answer the following questions. Make a table of values for \(x\) and \(f(x)\) using the given domain values. Write the values as ordered pairs.

Determine the area under each constant function on the indicated interval. Then graph the result. $$P(x)=\left\\{\begin{array}{ll} \frac{1}{8}, & 0 \leq x \leq 8 \\ 0, & \text { otherwise } \end{array} \text { on the interval } 2 \leq x \leq 5\right.$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.