/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Find the exact value of the indi... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the exact value of the indicated function (no decimals). Note that since the degree sign is not used, the angle is assumed to be in radians. $$\csc \frac{\pi}{4}$$

Short Answer

Expert verified
\(\csc\left(\frac{\pi}{4}\right) = \sqrt{2}\)

Step by step solution

01

Understand what the cosecant function represents

The cosecant function, denoted as \(\csc\), is the reciprocal of the sine function. So, \(\csc(\theta) = \frac{1}{\sin(\theta)}\). Thus, to find \(\csc\left(\frac{\pi}{4}\right)\), we need to find the value of \(\sin\left(\frac{\pi}{4}\right)\) first.
02

Calculate the sine of the given angle

The sine of \(\frac{\pi}{4}\) is a known value which can be derived from the unit circle or special right triangles. In this case, a 45°-45°-90° triangle (or \(\frac{\pi}{4}\) radians for both acute angles) has side ratios of 1:1:\(\sqrt{2}\). Therefore, \(\sin\left(\frac{\pi}{4}\right) = \frac{opposite}{hypotenuse} = \frac{1}{\sqrt{2}}\) or, rationalized, \(\frac{\sqrt{2}}{2}\).
03

Determine the cosecant of the angle

Using the reciprocal identity, we find \(\csc\left(\frac{\pi}{4}\right) = \frac{1}{\sin\left(\frac{\pi}{4}\right)} = \frac{1}{\frac{\sqrt{2}}{2}}\). To simplify this, multiply both numerator and denominator by \(\sqrt{2}\) to rationalize the denominator. This gives us \(\frac{\sqrt{2}}{1} = \sqrt{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reciprocal Trigonometric Functions
Trigonometry, the branch of mathematics dealing with the relationships of angles and sides in triangles, introduces several functions used to describe these relationships. Among these are the cosecant (csc), secant (sec), and cotangent (cot) functions, known as the reciprocal trigonometric functions. They are called so because they are the reciprocals of the more commonly used functions: sine (sin), cosine (cos), and tangent (tan) respectively.

For any angle \( \theta \), the relationships are defined as follows:
  • \( \csc(\theta) = \frac{1}{\sin(\theta)} \)
  • \( \sec(\theta) = \frac{1}{\cos(\theta)} \)
  • \( \cot(\theta) = \frac{1}{\tan(\theta)} \)
To understand how these functions work, imagine flipping the sine wave upside down. Where the sine has a peak, the cosecant has a trough, and vice versa. Just as the sine function represents a particular ratio in right triangles, so does the cosecant, except it deals with the hypotenuse over the opposite side. It is crucial when working with these functions to remember their domain restrictions since they are undefined whenever their corresponding 'regular' trigonometric function is zero.
Unit Circle
The unit circle is a fundamental concept not only in trigonometry but in all of mathematics because it provides a geometric representation of trigonometric functions. It is a circle with a radius of one unit, centered at the origin (0,0) of a Cartesian coordinate system. Each point on the circle correlates with an angle measured from the positive x-axis, going counter-clockwise.

Unit Circle and Trigonometric Functions

For any given angle \( \theta \), you can draw a radius from the origin to the point on the circle that represents \( \theta \). The sine of \( \theta \) corresponds to the y-coordinate of this point, while the cosine corresponds to the x-coordinate. Because the radius is one unit, these coordinates also represent the lengths of the sides in a right triangle formed by dropping a perpendicular from the point to the x-axis. Using this visualization, the sine and cosine—and thus the secant and cosecant—can be easily determined for angles commonly used in mathematics, such as \( \frac{\pi}{4} \), \( \frac{\pi}{2} \), and \( \pi \).
Special Right Triangles
Special right triangles are specific triangles that have exact, predictable ratios between their sides. There are two primary types of special right triangles: the 45°-45°-90° triangle, and the 30°-60°-90° triangle.

45°-45°-90° Triangle

The 45°-45°-90° triangle, also known as an isosceles right triangle, has side lengths in a particular ratio: 1:1:\(\sqrt{2}\). This means that for a triangle with the smaller two sides each being 1 unit, the hypotenuse will be \(\sqrt{2}\) units in length. These ratios allow for easy computation of trigonometric functions for angles of 45° (or \(\frac{\pi}{4}\) radians). As shown in Step 2 of the provided solution, this makes the sine of a 45° angle equal to \(\frac{1}{\sqrt{2}}\).

30°-60°-90° Triangle

The ratios for a 30°-60°-90° triangle are different: 1:\(\sqrt{3}\):2. It means that in a triangle where the smallest side is 1 unit, the side opposite the 60° angle will be \(\sqrt{3}\) units, and the hypotenuse will be 2 units. The understanding of these ratios is crucial when working with trigonometry problems involving these standardized angles.
Radians
Radians are an alternate unit of measuring angles, used extensively in mathematics and sciences. Unlike degrees, which are based on dividing a circle into 360 equal parts, radians are based on the distance along the circumference of the circle. One radian is the angle made at the center of a circle by an arc whose length is equal to the radius of the circle.

The entire circumference of a unit circle is \(2\pi\) radians, which is equivalent to 360°. This means that \(\frac{\pi}{4}\) radians, as mentioned in our initial exercise, is the radian equivalent of 45°. When it comes to conversion, the formulas are:
  • To convert from degrees to radians: \(\text{radians} = \text{degrees} \times \frac{\pi}{180}\)
  • To convert from radians to degrees: \(\text{degrees} = \text{radians} \times \frac{180}{\pi}\)
Understanding radians allows for a deeper appreciation of trigonometry and analysis, especially when examining periodic functions like sine and cosine, as they naturally fit into the radian measure of angles.

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Most popular questions from this chapter

Find the exact radian measure of the angle (no decimals). $$180^{\circ}$$

For Problems \(5-8,\) find the exact degree measure of the angle that subtends the given arc length of a unit circle. \(\frac{\pi}{6}\) units

Ona Nyland owns an island several hundred feet from the shore of a lake. Figure \(3-7 \mathrm{j}\) shows a vertical cross section through the shore, lake, and island. The island was formed millions of years ago by stresses that caused the earth's surface to warp into the sinusoidal pattern shown. The highest point on the shore is at \(x=-150\) feet. From measurements on and near the shore (solid part of the graph), topographers find that an equation of the sinusoid is $$y=-70+100 \cos \frac{\pi}{600}(x+150)$$ where \(x\) and \(y\) are in feet. Ona consults you to make predictions about the rest of the graph (dotted). a. What is the highest the island goes above the water level in the lake? How far from the \(y\) -axis is this high point? Show how you got your answers. b. What is the deepest the sinusoid goes below the water level in the lake? How far from the \(y\) -axis is this low point? Show how you got your answers. c. Over the centuries silt has filled the bottom of the lake so that the water is only 40 feet deep. That is, the silt line is at \(y=-40\) feet. Plot the graph. Use a friendly window for \(x\) and a window with a suitable range for \(y\) Then find graphically the range of \(x\) -values between which Ona would expect to find silt if she goes scuba diving in the lake. d. If Ona drills an offshore well at \(x=700\) feet, through how much silt would she drill before she reaches the sinusoid? Describe how you got your answer. e. The sinusoid appears to go through the origin. Does it actually do this, or does it just miss? Justify your answer. f. Find algebraically the range of \(x\) -values between which the island is at or above the water level. How wide is the island, from the water on one side to the water on the other?

Arc Length and Angle Problem: As a result of the definition of radians, you can calculate the arc length as the product of the angle in radians and the radius of the circle. Figure \(3-4 \mathrm{g}\) (above) shows arcs of three circles subtended by a central angle of 1.3 radians. The circles have radii of \(1,2,\) and 3 centimeters. (IMAGE CANNOT COPY) a. How long would the arc of the 1 -cm circle be if you measured it with a flexible ruler? b. Find how long the ares are on the 2 -cm circle and on the 3 -cm circle using the properties of similar geometrical figures. c. On a circle of radius \(r\) meters, how long would an arc be that is subtended by an angle of 1.3 radians? d. How could you find quickly the length \(a\) of an arc of a circle of radius \(r\) meters that is subtended by a central angle of measure \(\theta\) radians? Write a formula for the arc length.

For Problems \(1-4,\) find the exact arc length of a unit circle subtended by the given angle (no decimals). $$90^{\circ}$$

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