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For Problems \(11-20\) a. Identify the conic section. b. Calculate four radii and the eccentricity. c. Plot the graph. Sketch the result. $$-\left(\frac{x+1}{3}\right)^{2}+\left(\frac{y-2}{16}\right)^{2}=1$$

Short Answer

Expert verified
The conic section is an ellipse with a minor radius of 3 units and a major radius of 16 units. The eccentricity is approximately 0.9856.

Step by step solution

01

Identify the conic section

To identify the conic section, check the signs and coefficients of the squared terms. The given equation is in the standard form of an ellipse, since one squared term is subtracted and the other is added, and both are set equal to 1.
02

Calculate the radii

For the ellipse given by \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\) or \(\frac{(x-h)^2}{b^2} - \frac{(y-k)^2}{a^2} = 1\) , where \(a\) is associated with the horizontal or vertical radius and \(b\) is the other radius. Here, \(a^2 = 9\) and \(b^2 = 256\), so \(a = 3\) and \(b = 16\). Because \(b^2 > a^2\), \(b\) is the major radius and \(a\) is the minor radius.
03

Calculate the eccentricity

The eccentricity \(e\) of an ellipse is given by \(e = \sqrt{1 - \frac{a^2}{b^2}}\), where \(a\) and \(b\) are the lengths of the semi-major and semi-minor axes, respectively. Plugging the values from Step 2, we get \(e = \sqrt{1 - \frac{9}{256}}\), which simplifies to \(e = \sqrt{\frac{247}{256}} \approx 0.9856\).
04

Plot the graph

Draw the ellipse centered at \(\text{(-1, 2)}\), the vertices along the y-axis will be at \(\text{(-1, 2 + 16)}\) and \(\text{(-1, 2 - 16)}\), and those along the x-axis will be at \(\text{(-1 + 3, 2)}\) and \(\text{(-1 - 3, 2)}\). Sketch the ellipse by drawing a smooth curve connecting these points to form an oval shape.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conic Sections
Conic sections are the curves obtained by intersecting a right circular cone with a plane. The angle at which the plane intersects the cone determines the type of conic section formed. There are four main types: circles, ellipses, parabolas, and hyperbolas.

For instance, when the intersecting plane's angle is parallel to the slope of the cone, an ellipse is formed. Our exercise focuses on an ellipse, identified by its standard equation where one squared term is subtracted from the other, and the equation equals one. This equation showcases symmetry and the balanced proportions of distances in an ellipse, making it unique among conic sections.

An understanding of this concept is crucial to identifying and solving problems related to elliptical shapes in geometric contexts and various applications, such as planetary orbits in astronomy and design curves in engineering.
Graphing Ellipses
Graphing an ellipse involves understanding its standard form equation \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \) and identifying its key features, such as the center \(h, k\), radii \(a\) and \(b\), and vertices. Ellipses have two sets of vertices - the major vertices along the major axis and the minor vertices along the minor radius.

To sketch the graph, you determine the center and plot the vertices using the values of \(a\) and \(b\). Then, you draw a smooth, symmetric curve through these points, ensuring the ellipse outlines the general shape predicted by its equation. In our exercise, we graph an ellipse centered at \(\text{-1, 2}\) with vertices determined by the calculated radii. Recognizing these elements is essential for accurately graphing ellipses, which can represent real-world phenomena like the range of vision in lights or sound.
Eccentricity of an Ellipse
Eccentricity is a measure that describes the deviation of an ellipse from being a circle. It is denoted by the letter \(e\) and has a value between 0 and 1 for an ellipse. A perfect circle has an eccentricity of 0, while an eccentricity closer to 1 indicates a more elongated ellipse.

The formula to compute the eccentricity is \(e = \sqrt{1 - \frac{a^2}{b^2}}\), where \(a\) and \(b\) are the lengths of the semi-major and semi-minor axes, respectively. In our exercise, the eccentricity is approximately 0.9856, showing that the ellipse is quite elongated, as the value is near 1. Understanding eccentricity offers insights into the ellipse's shape and has practical implications in understanding orbits in astrophysics and designing lenses in optics.

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Most popular questions from this chapter

Sketch the quadric surface. Paraboloid formed by rotating the part of the graph of \(y=9-x^{2}\) that lies in the first quadrant about the \(y\) -axis.

Find the parametric equations of the conic section described. Plot the graph on your grapher and sketch the result. Ellipse with center \((6,-2),\) eccentricity \(0.8,\) and major radius 5 at an angle of \(70^{\circ}\) to the \(x\) -axis. Use a window with an \(x\) -range of [-10,10] and equal scales on the two axes.

For Problems \(21-32\) a. Draw a sketch showing the given information. Sketch the conic section. b. Find the particular equation (Cartesian or parametric). c. Plot the graph on your grapher. Does your sketch in part a agree with the plot? Focus \((2,-3),\) directrix \(y=0,\) eccentricity \(e=\frac{1}{2}\) Identify the conic section.

a. Name the conic section simply by looking at the Cartesian equation. b. Sketch the graph. c. Transform the given equation to an equation of the form $$ A x^{2}+B x y+C y^{2}+D x+E y+F=0 $$ d. Plot the Cartesian equation using the result of part c. Does it agree with part b? $$\left(\frac{x-3}{2}\right)^{2}+\left(\frac{y-1}{4}\right)^{2}=1$$

Here are four conic section equations that differ only in the coefficient of the \(x y\) -term. Identify each conic with the help of the discriminant. Plot all four graphs on the same screen. What graphical feature do you notice is the same for all four? How can you tell algebraically that your graphical observation is correct? a. \(x^{2}+y^{2}-10 x-8 y+16=0\) b. \(x^{2}+x y+y^{2}-10 x-8 y+16=0\) c. \(x^{2}+2 x y+y^{2}-10 x-8 y+16=0\) d. \(x^{2}+4 x y+y^{2}-10 x-8 y+16=0\)

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