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Shortcuts for Projections Problem: Show that these formulas give the scalar and vector projections of \(\vec{a}\) on \(\vec{b}\) The scalar projection of \(\vec{a}\) on \(\vec{b}\) is given by \(p=\frac{\vec{a} \cdot \vec{b}}{|\vec{b}|}\) The vector projection of \(\vec{a}\) on \(\vec{b}\) is given by \(\vec{p}=\frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^{2}} \vec{b}\)

Short Answer

Expert verified
The scalar and vector projections formulas are derived using the vector dot product and vector magnitude, resulting in \(p\) as the scalar projection and \(\vec{p}\) as the vector projection of \(\vec{a}\) on \(\vec{b}\).

Step by step solution

01

Set Up The Problem

Understand that the problem involves finding the scalar and vector projections of one vector onto another. The scalar projection is a measure of how much one vector extends in the direction of another vector, and the vector projection is the vector that represents that extension.
02

Review Vector Dot Product

Recall that the dot product of two vectors \(\vec{a} \cdot \vec{b}\) gives a scalar value and it is calculated by multiplying corresponding components of the two vectors and then summing those products.
03

Review Vector Magnitude

Recall that the magnitude of a vector \(\vec{b}\) is denoted by \( |\vec{b}| \) and is calculated by taking the square root of the sum of the squares of its components.
04

Compute Scalar Projection

Using the formula \( p = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|} \), calculate the scalar projection by dividing the dot product of \(\vec{a}\) and \(\vec{b}\) by the magnitude of \(\vec{b}\).
05

Compute Vector Projection

Using the formula \( \vec{p} = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^{2}} \vec{b} \), calculate the vector projection by multiplying the scalar projection by the unit vector in the direction of \(\vec{b}\), which is \(\vec{b} / |\vec{b}|\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scalar Projection Formula
The scalar projection formula is a critical component when studying vectors in a geometric context. In simple terms, it measures how far a given vector, let's say \( \vec{a} \), extends along the direction of another vector \( \vec{b} \). It's essentially the 'shadow' or 'footprint' of one vector onto another when the light source is perpendicular to the second vector.

To calculate the scalar projection, represented by \( p \), you use the formula \( p = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|} \). Here, the dot product \( \vec{a} \cdot \vec{b} \) quantifies how much the direction of \( \vec{a} \) aligns with \( \vec{b} \) by considering their lengths and the angle between them. This result is then divided by the magnitude of \( \vec{b} \) to adjust for its length, leaving you with the length of the 'shadow' we mentioned.

Remember to view the scalar projection as a way to gauge the influence of one vector along the direction of another, which has practical usage in physics for understanding forces or in computer graphics for calculating light intensities.
Vector Dot Product
The vector dot product, also known as the inner product or scalar product, is a fundamental operation in vector algebra. It's used to determine the magnitude of one vector in the direction of another. To find the dot product of two vectors \( \vec{a} \) and \( \vec{b} \), you multiply their corresponding components and then add these products together, mathematically expressed as \( \vec{a} \cdot \vec{b} = a_xb_x + a_yb_y + a_zb_z \) for three-dimensional vectors.

One crucial property of the dot product is that it can tell you about the angle between the two vectors. If the dot product is positive, the vectors are oriented in the same general direction. If it's zero, the vectors are perpendicular, and if it's negative, they are pointing in generally opposite directions.

This operation is not just a mathematical convenience but a powerful tool in physics for work and energy calculations as well as in computer science for rendering 3D models, where it helps in determining how light reflects off surfaces.
Vector Magnitude
Understanding vector magnitude is akin to gauging the 'size' or 'length' of a vector. The magnitude of a vector \( \vec{b} \) is denoted by \( |\vec{b}| \), and it's calculated by finding the square root of the sum of the squares of its components. For a two-dimensional vector with components \( b_x \) and \( b_y \) this is expressed as \( |\vec{b}| = \sqrt{b_x^2 + b_y^2} \).

In the physical world, the magnitude of a vector can represent speed, force, or other quantities depending on the context. It's measured in units that depend on what the vector itself represents. For instance, if a vector describes a force, its magnitude will be in Newtons.

Always remember that the magnitude provides essential information about the vector's 'strength' without considering its direction, which differentiates it from variables like velocity that provide both magnitude and direction information.
Vector Projection Formula
While a scalar projection gives you the length of a vector's shadow on another vector, the vector projection formula gives you the actual vector lying along the second vector that represents this projection. The formula is given by \( \vec{p} = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^2} \vec{b} \).

To compute this, you first perform the dot product of \( \vec{a} \) and \( \vec{b} \), and divide it by the square of the magnitude of \( \vec{b} \). This scalar quantity is then multiplied with the vector \( \vec{b} \) itself. The vector \( \vec{b} \) is usually normalized first, meaning it's been reduced to a unit vector in the same direction as \( \vec{b} \) but with a magnitude of 1. This projection is akin to casting the entirety of \( \vec{a} \) onto the line of \( \vec{b} \) so you can see its full influence in that specific direction.

The vector projection is used in many fields, including physics where it can, for example, show the specific direction a force is applied in relation to another direction, or in engineering for resolving components of vectors along particular axes.

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Most popular questions from this chapter

Prove the properties of vectors that follow. A sketch may help. Express the vectors as the sum of their components, and prove the properties algebraically. a. Vector addition is commutative. b. Vector addition is associative. c. Vector subtraction is not commutative. d. Multiplication by a scalar distributes over vector addition. e. The set of vectors is closed under addition. (Why is it necessary for there to be a zero vector in order for this closure property to be true?)

Sketch the vector and show its direction angles. $$\vec{v}=5 \vec{i}+4 \vec{j}+9 \vec{k}$$

Elmer is going to build a tree house in his backyard for the children to play in. The yard is level. He uses one corner of the yard as the origin of a three-dimensional coordinate system. The \(x\) - and \(y\) -axes run along the ground, and the \(z\) -axis is vertical. He finds that the tree house will be at the point \((x, y, z)=(30,55,17),\) where the dimensions are in feet. Answer parts a-f. (IMAGE CANNOT COPY) a. Sketch the coordinate axes and the point (30,55,17) b. Write the position vector \(\vec{h}\) to the tree house. How high is the tree house above the ground? How far is the tree house from the origin? c. A wire is to be stretched from the tree house to the point (10,0,8) at the top corner of the back door so that the children can slide messages down it. Write a vector representing the displacement from the tree house to the point on the back door. d. How long will the wire in part c need to be? e. The children slide a message down the wire. It gets stuck when it is only \(30 \%\) of the way from the tree house to the back door. Write a vector representing the displacement from the tree house to the stuck message. How far along the wire did the message go before it got stuck? f. Write the position vector of the stuck message. How high above the ground is the stuck message?

Find two normal vectors to the plane, pointing in opposite directions. $$4 x-7 y+2 z=9$$

Find the direction cosines of When find a vector equation of the line parallel to ? containing the given point. $$\nabla=2 \vec{i}-3 \vec{j}+4 \vec{k}, P_{0}=(1,-8,-5)$$

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