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91Ó°ÊÓ

Writing the Terms of a Sequence In Exercises \(7-22,\) write the first five terms of the sequence. (Assume that \(n\) begins with \(1 .\) ) $$ a_{n}=(-2)^{n} $$

Short Answer

Expert verified
The first five terms of the sequence are -2, 4, -8, 16, -32.

Step by step solution

01

Identify the sequence formula

We have the sequence formula \(a_{n}=(-2)^{n}\) that gives the value of any term in the sequence, depending on the term number \(n\). Here \(n\) is the position number in the sequence.
02

Generate the first term

Substitute \(n = 1\) into the sequence formula: \(a_{1}=(-2)^{1} = -2\). So the first term of the sequence is -2.
03

Generate the second term

Substitute \(n = 2\) into the sequence formula: \(a_{2}=(-2)^{2} = 4\). So the second term of the sequence is 4.
04

Generate the third term

Substitute \(n = 3\) into the sequence formula: \(a_{3}=(-2)^{3} = -8\). So the third term of the sequence is -8.
05

Generate the fourth term

Substitute \(n = 4\) into the sequence formula: \(a_{4}=(-2)^{4} = 16\). So the fourth term of the sequence is 16.
06

Generate the fifth term

Substitute \(n = 5\) into the sequence formula: \(a_{5}=(-2)^{5} = -32\). So the fifth term of the sequence is -32.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence Formula
Understanding the sequence formula is crucial for working with all types of sequences, including arithmetic and geometric ones. A sequence formula, such as the one provided in the exercise \(a_n=(-2)^n\), explicitly outlines how to find any term in the sequence based on its position, usually denoted as \(n\).

In this particular case, the sequence is not arithmetic (where each term is obtained by adding a constant to the previous term) but rather an example of an exponential sequence, because each term is found by raising a base number to the power of its position.

To use the sequence formula, you simply substitute the position number you are interested in into the formula. For example, to find the 10th term of the sequence provided, you would calculate \(a_{10}=(-2)^{10}\). This straightforward method allows for quick generation of any term in the sequence.
Exponential Sequences
Exponential sequences are fascinating and differ significantly from arithmetic sequences. Each term in an exponential sequence is the result of raising a fixed base to a power that represents the term's position within the sequence.

For example, the sequence provided in the exercise \(a_n=(-2)^n\) shows an exponential pattern. In exponential sequences, the changes between terms are multiplicative, not additive as in arithmetic sequences. This can lead to rapid increases or decreases in the values of the sequence's terms, especially when the base is greater than 1, or in this case, a negative number raised to successive powers.

Due to this multiplicative nature, exponential sequences often model real-life scenarios where growth or decay accelerates over time, such as population growth or radioactive decay.
Generating Sequence Terms
To generate sequence terms successfully, you need to carefully follow the sequence formula and apply it systematically, term by term. Let's break down the process as it was applied to our exercise's sequence, \(a_n=(-2)^n\).

The first step is to start at \(n=1\) for the first term. As you continue, you increment \(n\) by 1 for each subsequent term. This technique can be used to generate as many terms as required, or even to determine a specific term's value without generating all preceding terms.

It's important to note that for exponential sequences, you must pay close attention to the signs resulting from raising the base to even and odd powers, as this can significantly affect the outcome. For instance, \( (-2)^n \) yields alternating signs because an even exponent results in a positive product, while an odd exponent results in a negative product.

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Most popular questions from this chapter

Probability In Exercises \(85-88,\) consider \(n\) independent trials of an experiment in which each trial has two possible outcomes: "success" or "failure.". The probability of a success on each trial is \(p,\) and the probability of a failure is \(q=1-p .\) In this context, the term \(_{n} C_{k} p^{k} q^{n-k}\) in the expansion of \((p+q)^{n}\) gives the probability of \(k\) successes in the \(n\) trials of the experiment. The probability of a baseball player getting a hit during any given time at bat is \(\frac{1}{4}\) . To find the probability that the player gets three hits during the next 10 times at bat, evaluate the term $$_{10} C_{3}\left(\frac{1}{4}\right)^{3}\left(\frac{3}{4}\right)^{7}$$ in the expansion of \(\left(\frac{1}{4}+\frac{3}{4}\right)^{10}\)

Finding a Formula for a Sum In Exercises \(41-44\) , use mathematical induction to find a formula for the sum of the first \(n\) terms of the sequence. $$\frac{1}{4}, \frac{1}{12}, \frac{1}{24}, \frac{1}{40}, \ldots, \frac{1}{2 n(n+1)}, \dots$$

Arithmetic Mean In Exercises \(101-103,\) use the following definition of the arithmetic mean \(\overline{x}\) of a set of \(n\) measurements \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\) $$ \overline{x}=\frac{1}{n} \sum_{i=1}^{n} x_{i} $$ Proof Prove that $$\sum_{i=1}^{n}\left(x_{i}-\overline{x}\right)=0$$

Approximation In Exercises \(79-82,\) use the Binomial Theorem to approximate the quantity accurate to three decimal places. For example, in Exercise \(79,\) use the expansion \((1.02)^{8}=(1+0.02)^{8}\) $$=1+8(0.02)+28(0.02)^{2}+\cdots+(0.02)^{8}$$ $$(1.98)^{9}$$

You are given the probability that an event will happen. Find the probability the event will not happen. \(P(E)=\frac{1}{4}\)

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