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Sum of a Finite Geometric Sequence, find the sum of the finite geometric sequence. $$ \sum_{n=1}^{8} 5\left(-\frac{5}{2}\right)^{n-1} $$

Short Answer

Expert verified
The sum of the finite geometric sequence is \(-\frac{78125}{2}\).

Step by step solution

01

Identify the sequence parameters

In our case, the first term (a) is 5, the common ratio (r) is \(-\frac{5}{2}\), and the total number of terms (n) is 8.
02

Apply the geometric sequence sum formula

The formula to find the sum of a finite geometric sequence is \(S = \frac{a(r^{n} - 1)}{r - 1}\). Substituting our values: \(S = \frac{5\left(-\frac{5}{2}\right)^{8} - 1}{-\frac{5}{2} - 1}\).
03

Simplify the equation

After solving for the above equation, we find, \(S = -\frac{78125}{2}\).

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