/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Write all permutations of the le... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write all permutations of the letters A, B, C, and D when letters B and C must remain between A and D.

Short Answer

Expert verified
The four permutations that satisfy the given conditions are ABCD, ACBD, DBCA, and DCBA.

Step by step solution

01

Understand the Constraints

The problem states that the letters B and C must always be between A and D. So, it implies that A is at one end while D is at the other. The letters B and C have to be in the middle in any possible permutation.
02

Find the Permutations

Now, there are several ways to arrange the letters B and C between A and D. As there are only two letters, either B comes first and then C, or C comes first and then B. This gives us two options. And since A and D can also swap places, this leads to \(2 \times 2 = 4\) permutations in total.
03

Write Down All Permutations

The four permutations are: ABCD, ACBD, DBCA, and DCBA.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutation Constraints
Understanding permutation constraints is critical when dealing with combinatorial problems. In permutations, order matters, and specific rules or limitations can drastically alter the result. In our exercise, the constraint is that letters B and C must remain between A and D, which means A and D are essentially 'bookends' for the arrangement, while B and C take variable positions within those bounds.

Due to these constraints, we can’t freely permute all four letters; instead, we need to consider the allowable permutations of B and C and the fact that A and D can also switch places. This manifests in a reduced number of total permutations. Constraints like these are common in permutation problems and they require a keen understanding of how to apply the fundamental counting principle while adhering to the given limitations.
Arrangements of Letters
The concept of arranging letters involves creating different sequences or orders for a given set of characters. When no constraints are applied, the total number of permutations of n distinct objects is given by the factorial of n, denoted as n!. However, when constraints are present, such as in our exercise where B and C must be between A and D, the total number of permutations is affected.

Under such constraints, we need to look at the positions where each letter can possibly go. Here, we have two internal positions for B and C, which they can occupy in two different ways (BC or CB). Because B and C are distinct, each arrangement is unique. Coupling this with the possibility of A and D switching places gives us a multiplication factor, leading to the four distinct permutations we derived in the solution.
Combinatorics in Precalculus
Combinatorics is the branch of mathematics focused on counting, both in terms of the number of configurations (like our letter arrangements) and the properties of these configurations. In precalculus, basic combinatorial concepts are introduced, such as permutations and combinations, which are crucial for solving probability and statistics problems, among others.

Understanding constraints plays a significant role in combinatorial problems, as it often dictates the approach to finding a solution. Students learn to manage these constraints and use principles such as the multiplication rule, which says that if one event can occur in m ways and another independent event can occur in n ways, then the total number of ways the events can occur is m times n. This principle was applied in our exercise to determine the number of valid letter arrangements given the specific constraints.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Proving a Property In Exercises \(31-40,\) use mathematical induction to prove the property for all positive integers \(n .\) $$\text{ A }{\text factor}\text{ of }\left(n^{4}-n+4\right) \text { is } 2$$

Probability In Exercises \(85-88,\) consider \(n\) independent trials of an experiment in which each trial has two possible outcomes: "success" or "failure.". The probability of a success on each trial is \(p,\) and the probability of a failure is \(q=1-p .\) In this context, the term \(_{n} C_{k} p^{k} q^{n-k}\) in the expansion of \((p+q)^{n}\) gives the probability of \(k\) successes in the \(n\) trials of the experiment. To find the probability that the sales representative in Exercise 87 makes four sales when the probability of a sale with any one customer is \(\frac{1}{2},\) evaluate the term 8 $$_{4}\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{4}$$ in the expansion of \(\left(\frac{1}{2}+\frac{1}{2}\right)^{8}\)

Graphical Reasoning In Exercises 83 and \(84,\) use a graphing utility to graph \(f\) and \(g\) in the same viewing window. What is the relationship between the two graphs? Use the Binomial Theorem to write the polynomial function \(g\) in standard form. $$f(x)=-x^{4}+4 x^{2}-1, \quad g(x)=f(x-3)$$

Finding a Sum In Exercises \(45-54\) , find the sum using the formulas for the sums of powers of integers. $$\sum_{n=1}^{10} n^{3}$$

Finding a Formula for a Sum In Exercises \(41-44\) , use mathematical induction to find a formula for the sum of the first \(n\) terms of the sequence. $$\frac{1}{4}, \frac{1}{12}, \frac{1}{24}, \frac{1}{40}, \ldots, \frac{1}{2 n(n+1)}, \dots$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.