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Find the probability for the experiment of tossing a six-sided die twice. The sum is less than 11.

Short Answer

Expert verified
The probability that the sum of outcomes when a six-sided die is tossed twice is less than 11 is \(\frac{5}{6}\).

Step by step solution

01

Determining the total number of outcomes

When tossing a six-sided die, there are obviously 6 different outcomes. When you toss it twice, the total number of possible outcomes is therefore \(6 \times 6 = 36\), since for each outcome on the first toss, there are 6 possible outcomes on the second toss.
02

Determining outcomes that sum to less than 11

We need to find all combinations of outcomes that can sum to less than 11. This includes combinations that sum to 2 to 10. Counting all possibilities, there are 30 combinations: (1, 1) through (5, 6), and including (6, 1) through (6, 4).
03

Calculate the probability

The probability is calculated as the ratio of the number of favourable outcomes to the total number of outcomes. This gives us, \(\frac{30}{36} = \frac{5}{6}\).

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