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Expanding an Expression In Exercises \(19-40,\) use the Binomial Theorem to expand and simplify the expression. $$(y-4)^{3}$$

Short Answer

Expert verified
The expanded form of the expression \((y-4)^3\) is \(y^{3} - 12y^{2} + 48y - 64\).

Step by step solution

01

Understand the Binomial Theorem

The Binomial Theorem states that for any real numbers a and b, and any natural number n, the following holds true: \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k} \] Here, \(\binom{n}{k}\) denotes the binomial coefficient and is calculated as \( \frac{n!}{k!(n-k)!} \), where '!' denotes factorial.
02

Apply the Binomial Theorem to the Expression

Now, let's apply the binomial theorem to the given expression \((y-4)^3\). Here, a=y, b=-4 and n=3. So according to the theorem, the expression expands as: \[ (y-4)^3 = \sum_{k=0}^{3} \binom{3}{k} y^{3-k} (-4)^{k} \]
03

Calculate Each Term

Now, we calculate each term in the sum: - For k=0, the term is \(\binom{3}{0} y^{3} (-4)^{0} = y^{3}\)- For k=1, the term is \(\binom{3}{1} y^{2} (-4)^{1} = -12y^{2}\)- For k=2, the term is \(\binom{3}{2} y^{1} (-4)^{2} = 48y\)- For k=3, the term is \(\binom{3}{3} y^{0} (-4)^{3} = -64\)
04

Combine All Terms

Adding all of these terms together, we find the expanded form of the expression: \((y-4)^3 = y^{3} - 12y^{2} + 48y - 64\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Expansion
The binomial expansion is a way to express a power of a binomial as a sum of terms. These terms are derived using the Binomial Theorem, which is a well-established formula that expands algebraic expressions of the form \((a + b)^n\). This technique is particularly useful in algebra when you need to expand expressions without directly calculating powers step by step.

The basic idea is to take any binomial expression, such as \((a + b)^n\), and expand it into multiple terms. Each term consists of a product of powers of \(a\) and \(b\), multiplied by a specific coefficient called the binomial coefficient. The expanded form helps simplify calculations and can reveal insights about the nature of the expression.
  • Expansion saves time by providing a methodical approach.
  • It assists in simplifying complicated expressions.
  • Each term is generated based on defined rules, making the process repeatable.
Factorial
Factorials are a fundamental part of binomial expansion, especially when it comes to calculating the binomial coefficients. A factorial, denoted by \(!\), is a product of all positive integers less than or equal to a given number. For example, \(n! = n \times (n-1) \times (n-2) \times \ldots \times 1\). The factorial of zero, \(0!\), is defined to be 1.

Factorials grow rapidly as the number increases, making them substantial when calculating terms in a binomial expansion. They handle permutations and are crucial for determining binomial coefficients, providing a means to calculate each term's weight in the expansion formula.
  • Factorials help in determining the size of permutations.
  • They play a key role in statistics and probability based calculations.
  • Understanding factorials is essential for mastering binomial expansions.
Binomial Coefficient
The binomial coefficient is a central part of calculating each term in a binomial expansion. It is represented as \(\binom{n}{k}\) and serves as a multiplier for each term in the expansion. The value of \(\binom{n}{k}\) is calculated using the formula:\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]

This formula ensures that each term has the correct weight based on its position. The binomial coefficient provides insights into permutations and combinations, helping to determine how each arrangement of terms contributes to the overall expansion.
  • It shows the number of ways to choose \(k\) elements from a total of \(n\) elements, which is crucial in combinations.
  • It is symmetric, meaning \(\binom{n}{k} = \binom{n}{n-k}\).
  • A deeper understanding of binomial coefficients enhances one's ability to tackle combinatorial problems effectively.

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Most popular questions from this chapter

Determine whether the statement is true or false. Justify your answer. Rolling a number less than 3 on a normal six-sided die has a probability of \(\frac{1}{3}\) . The complement of this event is to roll a number greater than \(3,\) and its probability is \(\frac{1}{2}\) .

Find a formula for the sum of the angles (in degrees) of a regular polygon. Then use mathematical induction to prove this formula for a general \(n\) -sided polygon. Equilateral triangle \(\left(180^{\circ}\right)\) Square \(\left(360^{\circ}\right)\) Regular pentagon \(\left(540^{\circ}\right)\)

The sample spaces are large and you should use the counting principles discussed in Section 9.6. ATM personal identification number (PIN) codes typically consist of four-digit sequences of numbers. Find the probability that if you forget your PIN, then you can guess the correct sequence (a) at random and (b) when you recall the first two digits.

Probability In Exercises \(85-88,\) consider \(n\) independent trials of an experiment in which each trial has two possible outcomes: "success" or "failure.". The probability of a success on each trial is \(p,\) and the probability of a failure is \(q=1-p .\) In this context, the term \(_{n} C_{k} p^{k} q^{n-k}\) in the expansion of \((p+q)^{n}\) gives the probability of \(k\) successes in the \(n\) trials of the experiment. You toss a fair coin seven times. To find the probability of obtaining four heads, evaluate the term $$_{7} C_{4}\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{3}$$ in the expansion of \(\left(\frac{1}{2}+\frac{1}{2}\right)^{7}\)

Finding a Linear or Quadratic Model In Exercises \(55-60\) , decide whether the sequence can be represented perfectly by a linear or a quadratic model. If so, then find the model. $$0,6,16,30,48,70, \dots$$

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