/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 In Exercises 33-46, sketch the g... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 33-46, sketch the graph (and label the vertices) of the solution set of the system of inequalities. $$\left\\{\begin{aligned} 4 x^{2}+y & \geq 2 \\ x & \leq 1 \\ y & \leq 1 \end{aligned}\right.$$

Short Answer

Expert verified
The solution set of the given system of inequalities is a bounded region right to the y-axis, below the line y=1, left to the line x=1, and above the parabola \(4x^{2}+y = 2\).

Step by step solution

01

Graph the Linear Inequalities

Start by graphing the linear inequalities \(x\leq1\) and \(y\leq1\). These are straight lines parallel to the axes, and the area of solution is to the left of the line \(x=1\) and below the line \(y=1\).
02

Graph the Quadratic Inequality

To graph the quadratic inequality \(4x^{2}+y \geq 2\), first set it as an equation \(4x^{2}+y = 2\) which is a parabola. The graph of the parabola opens upwards with its vertex at the origin (0,2). For the inequality \(4x^{2}+y \geq 2\) the solution set is above the graph of the parabola.
03

Combine the Inequalities

The overall solution set is the region where all three inequalities overlap. Exactly, considering the bounds imposed by \(x \leq 1\) and \(y \leq 1\) and the overall solution area is a bounded region in the first quadrant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Inequalities
Linear inequalities represent a linear relationship that is not equated but rather expressed as greater than, less than, or equal to. In our exercise, the inequalities involved are \(x \leq 1\) and \(y \leq 1\). This means that we are looking for all the points that lie to the left of the line you get if \(x\) always equals 1, as well as all points below the line where \(y\) is always 1. To graph these, you draw straight lines along the respective values on their axes.
  • These inequalities divide the coordinate plane into two parts.
  • The line for \(x \leq 1\) is vertical.
  • The line for \(y \leq 1\) is horizontal.
The region representing the solution is to the left and below these lines. These lines act as borders or edges which constrain the solution set on the graph.
Quadratic Inequalities
Quadratic inequalities, unlike linear ones, involve an equation where the highest-degree term is squared, as in \(4x^2 + y \geq 2\). You start by dealing with the equality portion, \(4x^2 + y = 2\), which forms a parabola.
  • This parabola opens upwards as the term is \(x^2\).
  • The vertex, the highest or lowest point depending on its direction, is at \((0, 2)\).
In this inequality, we are interested in the region above this parabola because of the \(\geq\) sign. Therefore, when graphing, identify the areas above the curve to indicate solutions to \(4x^2 + y \geq 2\).
Solution Set
The solution set is essentially the subset of points or coordinates that satisfy all the given inequalities at once. For the current system, it’s where the areas of \(x \leq 1\), \(y \leq 1\), and \(4x^2 + y \geq 2\) intersect.
  • To find this, observe the intersections of the shaded regions from each inequality on a graph.
  • Start by shading the areas for the linear inequalities.
  • Then, shade the area above the parabola derived from the quadratic inequality.
The overlap of all these shaded regions provides the complete solution set. This intersection is typically found in the bounds of all conditions, resulting in a distinct geometric shape in the plane, usually a bounded region.
Vertices of Inequalities
Vertices in the context of inequalities refer to the corner points of the solution set. These are critical in identifying the actual extent and area of the solution space in graphical representations. For this system, you need to identify where the boundary lines intersect each other or the parabola.
  • The point \((1, 1)\) is formed by the intersection of the lines \(x \leq 1\) and \(y \leq 1\).
  • Check intersections between \(4x^2+y=2\) and \(x=1\), and \(y=1\), if there are any.
These vertices are essential since they define the limit of the shaded region. They mark transitions between boundary conditions and help ensure that the graph reflects all constraints accurately.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Geometry The perimeter of a triangle is 180 feet. The longest side of the triangle is 9 feet shorter than twice the shortest side. The sum of the lengths of the two shorter sides is 30 feet more than the length of the longest side. Find the lengths of the sides of the triangle.

Describing an Unusual Characteristic, the linear programming problem has an unusual characteristic. Sketch a graph of the solution region for the problem and describe the unusual characteristic. Find the minimum and maximum values of the objective function (if possible) and where they occur. $$ \begin{array}{c}{\text { Objective function: }} \\ {z=3 x+4 y} \\ {\text { Constraints: }} \\ {x \geq 0} \\ {y \geq 0} \\ {x+y \leq 1} \\ {2 x+y \leq 4}\end{array} $$

Fitting a Line to Data To find the least squares regression line \(y=a x+b\) for a set of points \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right), \ldots,\left(x_{n}, y_{n}\right)\) you can solve the following system for \(a\) and \(b\) . $$ \left\\{\begin{array}{c}{n b+\left(\sum_{i=1}^{n} x_{i}\right) a=\left(\sum_{i=1}^{n} y_{i}\right)} \\ {\left(\sum_{i=1}^{n} x_{i}\right) b+\left(\sum_{i=1}^{n} x_{i}^{2}\right) a=\left(\sum_{i=1}^{n} x_{i} y_{i}\right)}\end{array}\right. $$ In Exercises 55 and \(56,\) the sums have been evaluated. Solve the given system for \(a\) and \(b\) to find the least squares regression line for the points. Use a graphing utility to confirm the result. $$ \left\\{\begin{aligned} 5 b+10 a &=20.2 \\ 10 b+30 a &=50.1 \end{aligned}\right. $$

Truck Scheduling A small company that manufactures two models of exercise machines has an order for 15 units of the standard model and 16 units of the deluxe model. The company has trucks of two different sizes that can haul the products, as shown in the table. $$\begin{array}{|c|c|c|}\hline \text { Truck } & {\text { Standard }} & {\text { Deluxe }} \\ \hline \text { Large } & {6} & {3} \\ \hline \text { Medium } & {4} & {6} \\ \hline\end{array}$$ Find and graph a system of inequalities describing the numbers of trucks of each size that are needed to deliver the order.

Geometry In Exercises 65 and \(66,\) find the dimensions of the rectangle meeting the specified conditions. The perimeter is 56 meters and the length is 4 meters greater than the width.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.