Chapter 6: Problem 7
A vector that has a magnitude of 1 is called a___________
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Chapter 6: Problem 7
A vector that has a magnitude of 1 is called a___________
These are the key concepts you need to understand to accurately answer the question.
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Einding the Component Form of a Vector In Exercises \(75-78\) , find the component form of the sum of u and v with direction angles \(\theta_{\text { u }}\) and \(\theta_{v}\) . $$\begin{array}{ll}{\text { Magnitude }} & {\text { Angle }} \\\ {\|\mathbf{u}\|=50} & {\theta_{\mathrm{u}}=30^{\circ}} \\ {\|\mathbf{v}\|=30} & {\theta_{x}=110^{\circ}}\end{array}$$
Decomposing a Vector into Components In Exercises \(59-62,\) find the projection of \(u\) onto \(v .\) Then write \(u\) as the sum of two orthogonal vectors, one of which is \(\mathbf{p r o j}_{\mathbf{v}} \mathbf{u}\). $$\mathbf{u}=\langle 0,3\rangle$$ $$\mathbf{v}=\langle 2,15\rangle$$
Finding the Component Form of a Vector In Exercises \(67-74\) , find the component form of \(v\) given its magnitude and the angle it makes with the positive \(x\) -axis. Sketch y. \begin{array}{ll}{\text { Magnitude }} & {\text { Angle }} \\\ {\|\mathbf{v}\|=2} & {\mathbf{v} \text { in the direction } \mathbf{i}+3 \mathbf{j}}\end{array}
Einding the Component Form of a Vector In Exercises \(75-78\) , find the component form of the sum of u and v with direction angles \(\theta_{\text { u }}\) and \(\theta_{v}\) . $$\begin{array}{ll}{\text { Magnitude }} & {\text { Angle }} \\\ {\|\mathbf{u}\|=5} & {\theta_{\mathrm{u}}=0^{\circ}} \\ {\|\mathbf{v}\|=5} & {\theta_{\mathrm{v}}=90^{\circ}}\end{array}$$
Finding the Direction Angle of a Vector In Exercises \(63-66\) , find the magnitude and direction angle of the vector v. $$\mathbf{v}=3\left(\cos 60^{\circ} \mathbf{i}+\sin 60^{\circ} \mathbf{j}\right)$$
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