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Rewriting a Logarithm In Exercises \(7-10\) , rewrite the logarithm as a ratio of (a) common logarithms and (b) natural logarithms. $$\log _{1 / 5} x$$

Short Answer

Expert verified
The given logarithm \(\log _{1 / 5} x\) can be rewritten as a ratio of common logarithms: \(- \frac{\log_{10} x}{\log_{10}5}\), and a ratio of natural logarithms: \(- \frac{ln x}{ln 5}\).

Step by step solution

01

Rewrite the logarithm as a ratio of common logarithms

We will apply the change of base formula to rewrite \(\log _{1 / 5} x\) as a ratio of \(log_{10}\) also known as common logarithms. Using the formula \(\log_b a = \frac{\log_c a }{\log_c b}\), where \(b = 1/5, a = x\) and \(c = 10\), we have \(\log _{1 / 5} x = \frac{\log_{10} x}{ \log_{10} (1/5)}\).
02

Simplify the logarithm

Now, simplify the logarithm. Remember that \(\log_{10}(1 / 5) = - \log_{10}(5)\). The equation becomes \(\log _{1 / 5} x = - \frac{\log_{10} x}{\log_{10}5}\).
03

Rewrite the logarithm as a ratio of natural logarithms

Similarly, apply the change of base formula to rewrite \(\log _{1 / 5} x\) as a ratio of natural logarithms \(ln\). Using the same formula \(\log_b a = \frac{\log_c a }{\log_c b}\) where \(b = 1/5, a = x\) and now \(c = e\), the result is \(\log _{1 / 5} x = \frac{ln x}{ln(1/5)}\).
04

Simplify the logarithm

The last step is to simplify the logarithm. Note that \(ln(1 / 5) = -ln(5)\), and so \(\log _{1 / 5} x = - \frac{ln x}{ln 5}.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Logarithms
Logarithms are a cornerstone of precalculus mathematics, and common logarithms play a pivotal role in simplifying complex equations. A common logarithm uses 10 as its base and is denoted as \( \log x \). When the base is not written, it's understood to be 10, so \( \log x \) is read as the logarithm of x to the base 10.

Common logarithms convert multiplicative relationships into additive ones, making it simpler to solve equations involving growth rates and other exponential relationships. With the change of base formula, you can rewrite any logarithm, such as \( \log_{1 / 5} x \), in terms of common logarithms: \( \log_{1 / 5} x = \frac{\log x}{\log (1 / 5)} \). This technique forms the foundation for understanding more complex logarithmic functions and their applications.
Natural Logarithms
Natural logarithms are another critical type of logarithm in mathematics, particularly useful for dealing with continuous growth processes, such as those found in biology and economics. They use Euler's number (\( e \) ≈ 2.71828), a fundamental constant in mathematics, as the base and are represented by \( \ln x \).

One of the unique properties of natural logarithms is their appearance in calculus, especially in differentiation and integration of exponential functions. By transforming a logarithm to the natural base using the change of base formula, \( \log_{1 / 5} x \), can be expressed as \( \log_{1 / 5} x = \frac{\ln x}{\ln (1 / 5)} \). This indicates that natural logarithms are not only a concept to learn but an indispensable tool for advancing in higher mathematics.
Logarithmic Simplification
Logarithmic simplification is a practical skill that includes various techniques to make logarithmic expressions easier to work with. The ability to recognize and apply properties of logarithms—such as product, quotient, and power rules—greatly enhances one's capability to handle complex calculations.

For instance, when faced with a logarithmic term like \(\log_{10}(1 / 5)\), knowing that this is equivalent to \( -\log_{10}(5) \) due to the quotient rule (\( \log_b(\frac{a}{b}) = \log_b(a) - \log_b(b) \)) simplifies the expression considerably. This simplification process not only aids in solving logarithmic equations but also prompts a deeper understanding of how logarithms behave and interact with other mathematical operations.
Precalculus Mathematics
Precalculus mathematics serves as the gateway to higher-level concepts in calculus, statistics, and beyond. It involves a wide array of topics including functions, sequences, trigonometry, and of course, logarithms. Mastering precalculus is about understanding the relationships and applications of these concepts rather than just memorizing formulas.

In the context of logarithms and the change of base formula, precalculus prepares students to handle various types of exponential and logarithmic models. It lays the groundwork for analyzing real-world phenomena and equips students with the tools necessary for more advanced studies in mathematics, engineering, and the sciences. With a strong foundation in precalculus, students can confidently approach and solve complex mathematical problems.

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Most popular questions from this chapter

Using Properties of Logarithms In Exercises \(21-36\) , find the exact value of the logarithmic expression without using a calculator. (If this is not possible, then state the reason.) $$\log _{6} \sqrt[3]{6}$$

Expanding a Logarithmic Expression In Exercises \(37-58\) , use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.) $$\log _{10} \frac{y}{2}$$

Using Properties of Logarithms In Exercises \(21-36\) , find the exact value of the logarithmic expression without using a calculator. (If this is not possible, then state the reason.) $$\log _{3}(-27)$$

Comparing Models A cup of water at an initial temperature of \(78^{\circ} \mathrm{C}\) is placed in a room at a constant temperature of \(21^{\circ} \mathrm{C} .\) The temperature of the water is measured every 5 minutes during a half-hour period. The results are recorded as ordered pairs of the form \((t, T),\) where \(t\) is the time (in minutes) and \(T\) is the temperature (in degrees Celsius). $$ \begin{array}{l}{\left(0,78.0^{\circ}\right),\left(5,66.0^{\circ}\right),\left(10,57.5^{\circ}\right),\left(15,51.2^{\circ}\right)} \\\ {\left(20,46.3^{\circ}\right),\left(25,42.4^{\circ}\right),\left(30,39.6^{\circ}\right)}\end{array} $$ (a) The graph of the model for the data should be asymptotic with the graph of the temperature of the room. Subtract the room temperature from each of the temperatures in the ordered pairs. Use a graphing utility to plot the data points \((t, T)\) and \((t, T-21)\) . (b) An exponential model for the data \((t, T-21)\) is given by \(T-21=54.4(0.964)^{t} .\) Solve for \(T\) and graph the model. Compare the result with the plot of the original data. (c) Take the natural logarithms of the revised temperatures. Use the graphing utility to plot the points \((t, \ln (T-21))\) and observe that the points appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. This rasulting line has the form \(\ln (T-21)=a t+b\) . Solve for \(T,\) and verify that the result is equivalent to the model in part (b). (d) Fit a rational model to the data. Take the reciprocals of the \(y\) -coordinates of the revised data points to generate the points $$ \left(t, \frac{1}{T-21}\right) $$ Use the graphing utility to graph these points and observe that they appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. The resulting line has the form $$ \frac{1}{T-21}=a t+b $$ Solve for \(T,\) and use the graphing utility to graph the rational function and the original data points. (e) Why did taking the logarithms of the temperatures lead to a linear scatter plot? Why did taking the reciprocals of the temperatures lead to a linear scatter plot?

Using Properties of Logarithms In Exercises \(59-66,\) approximate the logarithm using the properties of logarithms, given \(\log _{b} 2 \approx 0.3562, \log _{b} 3 \approx 0.5646,\) and \(\log _{b} 5 \approx 0.8271\) $$\log _{b} \frac{2}{3}$$

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