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Using Properties of Logarithms In Exercises \(21-36\) , find the exact value of the logarithmic expression without using a calculator. (If this is not possible, then state the reason.) $$\log _{4} 2+\log _{4} 32$$

Short Answer

Expert verified
The exact value of the logarithmic expression \(\log _{4} 2+ \log _{4} 32\) is 3.

Step by step solution

01

Apply the product property of logarithms

The product property of logarithms states that the sum of the logs equals the log of the product. Thus, we can combine \(\log _{4} 2+ \log _{4} 32\) to become \(\log _{4} (2 \times 32)\).
02

Simplify the product

Multiply 2 by 32 to get 64. Substituting this back into the equation gives us \(\log _{4} 64\).
03

Calculate the log base 4 of 64

Using the special log property if \(a^m = b\), then \(\log_a b = m\), we find that \(4^3 = 64\). Consequently, \(\log _{4} 64 = 3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Expressions
Logarithmic expressions represent the power to which a number, called the base, must be raised to produce a given number. Understanding these expressions is crucial for solving various mathematical problems, especially in algebra and calculus. To comprehend a logarithmic expression like \( \log_b a \), you should know that it asks the question: 'To what exponent must the base \( b \) be raised to get \( a \) as the result?'.

Take for example \( \log_4 2 \). This expression seeks to find the exponent that makes 4 become 2, which is not immediately obvious since 2 is not a power of 4. However, by using properties of logarithms, it can still be calculated. If the base and the number are the same, the answer is always 1, because any number raised to the power of 1 is itself. On the other hand, if the number is a clear power of the base, like \( 4^3 = 64 \), then \( \log_4 64 \) simply is 3. But not all logarithmic expressions result in integers, and we may end up with fractions or irrational numbers.
Product Property of Logarithms
The product property of logarithms is a powerful tool that simplifies complex logarithmic calculations. It states that the log of a product is the sum of the logs: \(\log_b (mn) = \log_b m + \log_b n \). This allows for the breakdown of tricky logarithmic terms into more manageable pieces.

In practice, when you encounter a logarithmic expression such as \(\log_4 2 + \log_4 32 \), you can use this property to combine them into a single logarithm, \( \log_4 (2 \times 32) \), hence reducing the problem into finding the logarithm of a single number. This property not only simplifies the calculations but also sometimes allows for solving otherwise unsolvable problems by hand. When the numbers inside the log function are not perfect powers of the base, like the example \( 2 \times 32 \), this property becomes particularly valuable. Using this property encourages a more straightforward approach to the calculation, by focusing on a single logarithmic value.
Logarithm Calculation without a Calculator
It can seem daunting to calculate logarithms without a calculator, but understanding certain base principles might simplify the process. Notably, the relationship \( a^m = b \Rightarrow \log_a b = m \) is the most direct way to find logarithms of numbers that are whole powers of the base.

Here's how you can apply this to calculate \(\log_4 64 \) without a calculator:
  • First, recognize that 64 is a power of 4: \(4^3 = 64 \).
  • Now apply the relationship: Since \( 4^3 = 64 \), it means \( \log_4 64 = 3 \).
This process requires familiarity with powers of numbers and, sometimes, might involve a bit of trial and error or estimation. After all, logarithms are essentially exponents, so getting comfortable with exponential relations is key. To get better at manual logarithm calculations, practice with powers of various numbers to realize how they relate to their logarithms.

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Most popular questions from this chapter

Using Properties of Logarithms In Exercises \(21-36,\) find the exact value of the logarithmic expression without using a calculator. (If this is not possible, then state the reason.) $$\ln \frac{1}{\sqrt{e}}$$

Expanding a Logarithmic Expression In Exercises \(37-58,\) use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.) $$\log _{2} x^{4} \sqrt{\frac{y}{z^{3}}}$$

Comparing Models A cup of water at an initial temperature of \(78^{\circ} \mathrm{C}\) is placed in a room at a constant temperature of \(21^{\circ} \mathrm{C} .\) The temperature of the water is measured every 5 minutes during a half-hour period. The results are recorded as ordered pairs of the form \((t, T),\) where \(t\) is the time (in minutes) and \(T\) is the temperature (in degrees Celsius). $$ \begin{array}{l}{\left(0,78.0^{\circ}\right),\left(5,66.0^{\circ}\right),\left(10,57.5^{\circ}\right),\left(15,51.2^{\circ}\right)} \\\ {\left(20,46.3^{\circ}\right),\left(25,42.4^{\circ}\right),\left(30,39.6^{\circ}\right)}\end{array} $$ (a) The graph of the model for the data should be asymptotic with the graph of the temperature of the room. Subtract the room temperature from each of the temperatures in the ordered pairs. Use a graphing utility to plot the data points \((t, T)\) and \((t, T-21)\) . (b) An exponential model for the data \((t, T-21)\) is given by \(T-21=54.4(0.964)^{t} .\) Solve for \(T\) and graph the model. Compare the result with the plot of the original data. (c) Take the natural logarithms of the revised temperatures. Use the graphing utility to plot the points \((t, \ln (T-21))\) and observe that the points appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. This rasulting line has the form \(\ln (T-21)=a t+b\) . Solve for \(T,\) and verify that the result is equivalent to the model in part (b). (d) Fit a rational model to the data. Take the reciprocals of the \(y\) -coordinates of the revised data points to generate the points $$ \left(t, \frac{1}{T-21}\right) $$ Use the graphing utility to graph these points and observe that they appear to be linear. Use the regression feature of the graphing utility to fit a line to these data. The resulting line has the form $$ \frac{1}{T-21}=a t+b $$ Solve for \(T,\) and use the graphing utility to graph the rational function and the original data points. (e) Why did taking the logarithms of the temperatures lead to a linear scatter plot? Why did taking the reciprocals of the temperatures lead to a linear scatter plot?

Using Properties of Logarithms In Exercises \(15-20\) , use the properties of logarithms to rewrite and simplify the logarithmic expression. $$\ln \left(5 e^{6}\right)$$

Let \(f(x)=\log _{a} x \quad\) and \(g(x)=a^{x},\) where \(a>1 .\) (a) Let \(a=1.2\) and use a graphing utility to graph the two functions in the same viewing window. What do you observe? Approximate any points of intersection of the two graphs. (b) Determine the value(s) of \(a\) for which the two graphs have one point of intersection. (c) Determine the value(s) of \(a\) for which the two graphs have two points of intersection.

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