/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 Complex Solutions of a Quadratic... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Complex Solutions of a Quadratic Equation. Use the Quadratic Formula to solve the quadratic equation $$4 x^{2}+16 x+17=0$$

Short Answer

Expert verified
The solutions to the given quadratic equation are \(x = -2 + 0.5i\) and \(x = -2 - 0.5i\).

Step by step solution

01

Plug in coefficients to the Quadratic formula

Firstly, identify the coefficients a, b and c in the quadratic equation \(4x^{2} + 16x + 17 = 0\). Here, a = 4, b = 16 and c = 17. So, plug in these values to the quadratic equation formula, we get \(x = [-16 ± sqrt((16)^{2} - 4*4*17)] / (2*4)\).
02

Calculate the Discriminant

Next, calculate the discriminant, which is \(b^{2} - 4ac = (16)^{2} - 4*4*17 = 256 - 272 = -16\). Since the discriminant is less than 0, the roots will be complex numbers.
03

Solve for x

Finally, solve the equation for x. We get \(x = [-16 ± sqrt(-16)] / 8\). As sqrt(-16) = 4i (where i is the imaginary unit), we have \(x = [-16 ± 4i] / 8\), which simplifies to \(x = -2 ± 0.5i\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
In mathematics, complex numbers extend the idea of the one-dimensional number line to the two-dimensional complex plane. This means they go beyond real numbers, which include all the numbers you generally count and measure with.
Complex numbers are written in the form of \(a + bi\), where
  • \(a\) is the real part
  • \(b\) is the imaginary part
  • \(i\) is the imaginary unit, satisfying the equation \(i^2=-1\)
Let’s consider the equation from the exercise: \(4x^{2} + 16x + 17 = 0\). This shows a situation where the solutions are not real numbers, since the discriminant came out to be negative. This means both roots of the equation include the imaginary unit \(i\) and are expressed in a complex form: \(-2 \pm 0.5i\). Thus, embracing complex numbers makes it possible to solve equations that seem unsolvable using only real numbers.
Discriminant
The discriminant of a quadratic equation is a part of the Quadratic Formula and is crucial in determining the nature of the equation’s roots.
For a quadratic equation \(ax^2 + bx + c = 0\), the discriminant is given by the formula \(b^2 - 4ac\).
Depending upon the value of the discriminant:
  • If it is positive, the quadratic equation has two distinct real roots.
  • If it is zero, there is exactly one real root.
  • If it is negative, as in this exercise's case, the equation has complex roots.
In the given problem, with values \(a = 4\), \(b = 16\), and \(c = 17\), plugging into the discriminant formula gives us \(-16\), which confirms the roots are complex. Understanding how the discriminant outlines the root type is essential, helping us anticipate the nature of the solutions without solving the entire equation.
Roots of Quadratic Equations
The roots of a quadratic equation are the solutions for the value of \(x\) that satisfy the equation \(ax^2 + bx + c = 0\). These roots can be found using the Quadratic Formula, \(x = \frac{{-b \pm \sqrt{b^2 - 4ac}}}{2a}\).
The process generally involves calculating the discriminant first to determine the type of roots you are dealing with.
In our exercise:
  • We found the roots using \(-16\) as our discriminant value.
  • This gave complex roots \(-2 \pm 0.5i\) because the discriminant was negative.
These roots indicate that the parabola represented by the quadratic equation does not intersect the x-axis in the real plane. Instead, the solutions reflect a situation in the complex plane.
Understanding how to find and interpret these roots, including their type, is fundamental in solving quadratic equations, as it provides insight into the behavior of the quadratic's graph and its intersection points.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Finding the Domain of an Expression In Exercises \(61-66\) , find the domain of the expression. Use a graphing utility to verify your result. $$\sqrt{\frac{x}{x^{2}-9}}$$

IQ Scores The IQ scores for a sample of a class of returning adult students at a small northeastern college roughly follow the normal distribution $$y=0.0266 e^{-(x-100)^{2} / 450}, \quad 70 \leq x \leq 115$$ where \(x\) is the IQ score. (a) Use a graphing utility to graph the function. (b) From the graph in part (a), estimate the average number of hours per week a student uses the tutoring center.

Solving an Inequality In Exercises \(67-72,\) solve the inequality. (Round your answers to two decimal places.)$$-1.3 x^{2}+3.78>2.12$$

Rational and Irrational Zeros, match the cubic function with the numbers of rational and irrational zeros. (a) Rational zeros: \(0 ;\) irrational zeros: 1 (b) Rational zeros: \(3 ;\) irrational zeros: 0 (c) Rational zeros: \(1 ;\) irrational zeros: 2 (d) Rational zeros: \(1 ;\) irrational zeros: 0 $$f(x)=x^{3}-x$$

Forensics At \(8 : 30\) A.M., a coroner went to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the person's temperature twice. At \(9 : 00\) A.M. the temperature was \(85.7^{\circ} \mathrm{F},\) and at \(11 : 00\) A.M. thetemperature was \(82.8^{\circ} \mathrm{F}\) . From these two temperatures, the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula $$t=-10 \ln \frac{T-70}{98.6-70}$$ where \(t\) is the time in hours elapsed since the person died and \(T\) is the temperature (in degrees Fahrenheit) of the person's body. (This formula comes from a general cooling principle called Newton's Law of Cooling.It uses the assumptions that the person had a normal body temperature of \(98.6^{\circ} \mathrm{F}\) at death and that the room temperature was a constant \(70^{\circ} \mathrm{F} .\) ) Use the formula to estimate the time of death of the person.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.