Chapter 1: Problem 94
It is possible for an odd function to have the interval \([0, \infty)\) as its domain.
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Chapter 1: Problem 94
It is possible for an odd function to have the interval \([0, \infty)\) as its domain.
These are the key concepts you need to understand to accurately answer the question.
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Salary You are a sales representative for a clothing manufacturer. You are paid an annual salary, plus a bonus of 3\(\%\) of your sales over \(\$ 500,000 .\) Consider the two functions \(f(x)=x-500,000\) and \(g(x)=0.03 x\) When \(x\) is greater than \(\$ 500,000,\) which of the following represents your bonus? Explain your reasoning. $$\begin{array}{l}{\text { (a) } f(g(x))} \\ {\text { (b) } g(f(x))}\end{array}$$
Identify any interepts and test for symmetry. Then sketch the graph of the equation. \(y=\sqrt{1-x}\)
Restricting the Domain In Exercises \(73-82,\) restrict the domain of the function \(f\) so that the function is one-to-one and has an inverse function. Then find the inverse function \(f^{-1} .\) State the domains and ranges of \(f\) and \(f^{-1} .\) Explain your results. (There are many correct answers.) $$f(x)=\frac{1}{2} x^{2}-1$$
Maximum Volume An open box of maximum volume is to be made from a square piece of material 24 centimeters on a side by cutting equal squares from the corners and turning up the sides (see figure). (a) The table shows the volumes \(V\) (in cubic centimeters) of the box for various heights \(x\) (in centimeters). Use the table to estimate the maximum volume. $$ \begin{array}{|c|c|c|c|c|c|c|}\hline \text { Height, } & {1} & {2} & {3} & {4} & {5} & {6} \\ \hline \text { Volume, } V & {484} & {800} & {972} & {1024} & {980} & {864} \\ \hline\end{array} $$ (b) Plot the points \((x, V)\) from the table in part (a). Does the relation defined by the ordered pairs represent \(V\) as a function of \(x ?\) (c) Given that \(V\) is a function of \(x,\) write the function and determine its domain.
Finding the Coordinates of a Point In Exercises 7 and 8 , find the coordinates of the point. The point is located three units to the left of the \(y\) -axis and four units above the \(x\) -axis.
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