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Composition with lnverses In Exercises \(89-92\) , use the functions \(f(x)=x+4\) and \(g(x)=2 x-5\) to find the specified function. $$g^{-1} \circ f^{-1}$$

Short Answer

Expert verified
The composition of the inverse functions is \(g^{-1} \circ f^{-1} = (x+1)/2\).

Step by step solution

01

Find the Inverse of \(f(x)\)

The function \(f(x) = x + 4\) is a simple linear equation. To find its inverse, simply solve for \(x\): \[f^{-1}(x) = x - 4\]
02

Find the Inverse of \(g(x)\)

Again, the function \(g(x) = 2x - 5\) is a simple linear equation. To find its inverse, simply solve for \(x\): \[g^{-1}(x) = (x + 5)/2\]
03

Find the Composition of \(g^{-1} \circ f^{-1}\)

To compose \(g^{-1}(x)\) and \(f^{-1}(x)\), you substitute \(f^{-1}(x)\) into \(g^{-1}(x)\): \[g^{-1}(f^{-1}(x)) =((x-4)+5)/2\] So, \[g^{-1} \circ f^{-1} =((x-4)+5)/2 = (x+1)/2\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Functions
Understanding inverse functions is like learning how to rewind a story to its beginning. An inverse function essentially reverses the action of the original function. When you have a function that takes an input and gives you an output, the inverse function takes the output back to the original input.

Let's look through our magical math lens at a function, say, \( f(x) = x + 4 \). To find its inverse, which we denote as \( f^{-1}(x) \), you 'rewind' by undoing whatever the original function did. In our case, the original function added 4, so to find the inverse, you do the opposite - you subtract 4, resulting in \( f^{-1}(x) = x - 4 \).

Here's the kicker: for any function and its inverse, if you feed the output of the original function into its inverse, you'll get the original input back. So, if you put \( f(x) \) into \( f^{-1}(x) \), you'll get \( x \) itself! It's like a mathematically guaranteed boomerang.
Function Composition
Picture function composition as a relay race, where each runner hands off the baton to the next. In math, composing two functions is like having one function pass its output to another function as the input. It's a two-step process, where the output of the first function becomes the input of the second.

Let's riff on our exercise: we have the inverse functions \( f^{-1}(x) \) and \( g^{-1}(x) \). To compose them, we're essentially feeding the output of \( f^{-1}(x) \) straight into \( g^{-1}(x) \). For example, if \( f^{-1}(x) = x - 4 \), and you want to compose it with \( g^{-1}(x) = (x + 5)/2 \), you simply take \( x - 4 \), and plug it in place of \( x \) in the second function. You end up with \( g^{-1}(f^{-1}(x)) = ((x-4)+5)/2 \), which simplifies to \( (x+1)/2 \).

It's crucial to proceed in the correct order and perform each 'handoff' accurately, otherwise, you'll end up computing something entirely different!
Linear Equations
Linear equations are the straight-line relationships between x and y, found everywhere from predicting economics to building bridges. They are usually written in the form \( y = mx + b \), where \( m \) represents the slope and \( b \) the y-intercept.

In our example, the functions \( f(x) \) and \( g(x) \) are both linear. \( f(x) = x + 4 \) means that for every unit increase in \( x \), \( y \) increases by one unit, and starts off when \( x = 0 \) at 4. Similarly, \( g(x) = 2x - 5 \) indicates a steeper slope: for every unit increase in \( x \), \( y \) increases by two units, starting at -5.

In the territory of linear equations, finding inverses is a smooth sail. Rearrange the equation to solve for \( x \), and there you have it: the recipe to rewind your linear story. It's the beauty of linearity—simple, predictable, and reversible. The ease of working with linear equations makes the exploration of inverse functions and function composition accessible, even enjoyable for students diving into the world of functions.

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