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Finding a Mathematical Model In Exercises \(41-50\) , find a mathematical model for the verbal statement. V varies directly as the cube of \(e\) .

Short Answer

Expert verified
The mathematical model representing the verbal expression 'V varies directly as the cube of e' is \(V = ke^3\).

Step by step solution

01

Understanding the concept of direct variation

Direct variation describes a simple relationship between two variables. If a variable y varies directly as x, it means that when x increases, y increases by the same factor. In other words, y is directly proportional to x, and this can be written as \(y = kx\), where \(k\) is called the constant of variation.
02

Formulating the mathematical model

In this exercise, V varies directly as the cube of e. To create a mathematical model representing this, take the variable 'e', cube it (since the problem states 'the cube of e'), and multiply it by a constant, say 'k'. So, the mathematical model in this case can be described as \(V = ke^3\). This equation states that the value of 'V' is directly proportional to the cube of 'e'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Models
Mathematical models are like blueprints for understanding real-world situations mathematically. These models use mathematical language to describe patterns, trends, and relationships between variables. In essence, a mathematical model is an equation or set of equations that represents phenomena, allowing us to make predictions and understand how different factors interact.

For example, predicting the growth of a plant over time might involve a mathematical model that relates the height of the plant to the days since it was planted. The model could provide a way to estimate the plant's height on any future day, given its current rate of growth. Mathematical models are vital in fields ranging from physics and engineering to economics and social sciences, serving as tools for simulation, analysis, and decision-making.

Using mathematical models, we can also illustrate concepts like direct variation. In the case of direct variation, the mathematical model helps us visualize and calculate how changes in one variable directly influence the other. To achieve this, we need a constant of variation, which brings us to our next core concept.
Constant of Variation
The constant of variation, often represented as 'k' in equations, is a key part of understanding direct variation. It's the 'multiplier' that defines the strength or rate of the linear relationship between two variables that vary directly. Consider it the proportionality factor that remains, well, constant, as other variables change.

In our original exercise, we determined that 'V' varies directly as the cube of 'e'. The mathematical model for this relationship includes the constant of variation 'k', as expressed in the equation \(V = ke^3\). This constant is what links 'V' and 'e' in a clear, predictable manner. If 'k' is known, and you are given a value of 'e', you can immediately predict 'V' with precision. Conversely, if you know 'V' and 'e', you can determine 'k' – which could be useful for comparing similar relationships across different contexts or scenarios.
Proportional Relationships
Proportional relationships are a foundational concept in algebra and represent a direct variation between two quantities where they increase or decrease at the same rate. If you think of one variable racing against another, with proportional relationships, they'd be moving in lockstep; if one doubles, so does the other.

In these relationships, if you were to plot the variables on a graph, they would fall on a straight line that passes through the origin, illustrating a consistent ratio between them. This ratio also equates to the constant of variation 'k' in the equation for direct variation. In the context of our problem, as 'e' changes, 'V' changes in proportion to the cube of 'e', maintaining a consistent ratio determined by 'k'. This reveals that even as quantities themselves grow large or small, their fundamental relationship, described by the direct variation equation, remains unchanged and predictable.

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Most popular questions from this chapter

Sales The following are the slopes of lines representing annual sales \(y\) in terms of time \(x\) in years. Use the slopes to interpret any change in annual sales for a one-year increase in time. $$\begin{array}{l}{\text { (a) The line has a slope of } m=135 \text { . }} \\\ {\text { (b) The line has a slope of } m=0 \text { . }} \\ {\text { (c) The line has a slope of } m=-40}\end{array}$$

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Think About It Consider the functions \(f(x)=x+2\) and \(f^{-1}(x)=x-2 .\) Evaluate \(f\left(f^{-1}(x)\right)\) and \(f^{-1}(f(x))\) for the indicated values of \(x .\) What can you conclude about the functions?

The number of lumens (time rate of flow of light) \(L\) from a fluorescent lamp can be approximated by the model $$L=-0.294 x^{2}+97.744 x-664.875, \quad 20 \leq x \leq 90$$ where \(x\) is the wattage of the lamp. (a) Use a graphing utility to graph the function. (b) Use the graph from part (a) to estimate the wattage necessary to obtain 2000 lumens.

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