/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Plotting, Distance, and Midpoint... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Plotting, Distance, and Midpoint, (a) plot the points, (b) find the distance between the points, and (c) find the midpoint of the line segment joining the points. $$ (6,-3),(6,5) $$

Short Answer

Expert verified
The distance between the points is 8 and the midpoint is (6,1).

Step by step solution

01

Plot the points on a graph

The points are (6,-3) and (6,5). Plot these points on the same graph. As both points have the same x-coordinate, they lie on the same vertical line.
02

Calculate the distance

The distance between two points \((x1, y1)\) and \((x2, y2)\) is calculated by \(\sqrt{(x2 - x1)^2 + (y2 - y1)^2}\). Here, \(x1 = x2 = 6\), \(y1 = -3\) and \(y2 = 5\). Plugging these into the formula, the distance becomes \(\sqrt{(6 - 6)^2 + (5 - (-3))^2} = 8\).
03

Find the midpoint

The midpoint between two points \((x1, y1)\) and \((x2, y2)\) is \(((x1 + x2) / 2 , (y1 + y2) / 2)\). Here, \(x1 = x2 = 6\), \(y1 = -3\) and \(y2 = 5\). Plugging these into the formula, the midpoint is \(((6 + 6) / 2 , (-3 + 5) / 2) = (6,1)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Plotting Points
Plotting points on a graph is an essential skill in coordinate geometry. It's like marking spots on a map. To plot a point, you need an ordered pair \((x, y)\) which tells you where to place the dot on a grid. The first number, \(x\), is the horizontal position (left or right), while the second number, \(y\), is the vertical position (up or down). For example, let’s take the points \((6, -3)\) and \((6, 5)\). Both have the same \(x\)-coordinate, which means they sit on the same vertical line at \(x = 6\). You simply move up or down to reach the correct \(y\)-value for each point. Plotting these tells us a lot quickly. Since the \(x\)-coordinates match, you already know they form a vertical line.
Distance Formula
Calculating the distance between two points on a graph helps determine how far apart they are. This can be visualized as the length of a straight line connecting them. We use the distance formula:\[ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]This formula comes from the Pythagorean theorem, combining the change in \(x\) and \(y\). Here’s how it works with points \((6, -3)\) and \((6, 5)\):
  • Both \(x_1\) and \(x_2\) are 6, so \((x_2 - x_1)^2\) is zero.
  • The change in \(y\) is \(5 - (-3) = 8\).
  • The distance becomes \(\sqrt{0 + 8^2 } = 8\).
So, the distance between these two points is 8 units, a reflection of their separation along the vertical line.
Midpoint Formula
The midpoint of a line segment gives the central point between two ends. It’s like finding the middle point on a ruler to have equal sides. We use:\[ \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]This formula averages the \(x\) and \(y\) coordinates, helping locate the midpoint accurately. With points \((6, -3)\) and \((6, 5)\):
  • \(x_1\) and \(x_2\) are both 6, so \(\frac{6 + 6}{2} = 6\).
  • For \(y\), calculate \(\frac{-3 + 5}{2}\) which is 1.
This gives a midpoint of \((6, 1)\). It’s directly between the two original points on the vertical path, showing balance and symmetry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Parallel and Perpendicular Lines, determine whether the lines \(L_{1}\) and \(L_{2}\) passing through the pairs of points are parallel, perpendicular, or neither. $$\begin{array}{l}{L_{1} :(0,-1),(5,9)} \\ {L_{2} :(0,3),(4,1)}\end{array}$$

Finding a Relationship for Equidistance, find a relationship between \(x\) and \(y\) such that \((x, y)\) is equidistant (the same distance) from the two points. $$(6,5),(1,-8)$$

Graphical Reasoning Graph each of the functions with a graphing utility. Determine whether the function is even, odd, or neither. $$\begin{array}{ll}{f(x)=x^{2}-x^{4}} & {g(x)=2 x^{3}+1} \\ {h(x)=x^{5}-2 x^{3}+x} & {j(x)=2-x^{6}-x^{8}} \\ {k(x)=x^{5}-2 x^{4}+x-2} & {p(x)=x^{9}+3 x^{5}-x^{3}+x}\end{array}$$ What do you notice about the equations of functions that are odd? What do you notice about the equations of functions that are even? Can you describe a way to identify a function as odd or even by inspecting the equation? Can you describe a way to identify a function as neither odd nor even by inspecting the equation?

Finding Parallel and Perpendicular, write equations of the lines through the given point (a) parallel to and (b) perpendicular to the given line. $$4 x-2 y=3, \quad(2,1)$$

From the top of a mountain road, a surveyor takes several horizontal measurements \(x\) and several vertical measurements \(y\) as shown in the table \((x\) and \(y\) are measured in feet). $$\begin{array}{|c|c|c|c|c|}\hline x & {300} & {600} & {900} & {1200} \\\ \hline y & {-25} & {-50} & {-75} & {-100} \\ \hline\end{array}$$ $$\begin{array}{|c|c|c|c|}\hline x & {1500} & {1800} & {2100} \\ \hline y & {-125} & {-150} & {-175} \\ \hline\end{array}$$ $$\begin{array}{l}{\text { (a) Sketch a scatter plot of the data. }} \\\ {\text { (b) Use a straightedge to sketch the line that you }} \\ {\text { think best fits the data. }} \\ {\text { (c) Find an equation for the line you sketched in }} \\ {\text { part (b). }}\end{array}$$ $$ \begin{array}{l}{\text { (d) Interpret the meaning of the slope of the line in }} \\ {\text { part (c) in the context of the problem. }} \\ {\text { (e) The surveyor needs to put up a road sign that }} \\ {\text { indicates the steepness of the road. For instance, }} \\ {\text { a surveyor would put up a sign that states "8% }}\end{array}$$ $$ \begin{array}{l}{\text { grade" on a road with a downhill grade that has }} \\\ {\text { a slope of }-\frac{8 .}{100 .} \text { . What should the sign state for }} \\ {\text { the road in this problem? }}\end{array}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.