/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 find the zeros of the function a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

find the zeros of the function algebraically. \(f(x)=9 x^{4}-25 x^{2}\)

Short Answer

Expert verified
The function has three zeros at \(x = 0, x = -5/3\) and \(x = 5/3\).

Step by step solution

01

Reformulate the function

First, rewrite the function \(f(x)=9x^{4}-25x^{2}\) in terms of \(x^{2}\) where \(X = x^2\). Therefore, the equation becomes \(9X^{2}-25X=0\)
02

Finding Roots of Quadratic Equation

Next, solve the quadratic equation from Step 1 by setting it to zero and solving for \(X\). First, factor out an \(X\), so you get \(X(9X - 25) = 0\). Now, set each factor equal to zero and solve for \(X\). This will give you the roots: \(X = 0\) and \(X = 25/9\)
03

Substitute X and find all values for x

Now recall that \(X = x^2\). For \(X = 0\), \(x^2 = 0\) and that gives \(x = 0\). For \(X = 25/9\), \(x^2 = 25/9\) and that gives \(x= -5/3, x = +5/3\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
In the realm of algebra, a quadratic equation is any equation that can be manipulated into the standard form 'ax² + bx + c = 0', where 'a', 'b', and 'c' are constants, and 'a' is not zero. The quadratic equation is foundational in mathematics because it is one of the simplest polynomial equations to solve. This type of equation typically has two solutions or "roots" which represent the points where the graph of the quadratic function intersects the x-axis.

To find these roots algebraically, you can use several methods:
  • Factoring, which involves expressing the quadratic as a product of its linear factors.
  • The Quadratic Formula, given by \[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a},\]which provides a solution for any quadratic equation.
  • Completing the Square, which makes the quadratic expression a perfect square trinomial, simplifying the solving process.
Understanding how to manipulate and solve quadratic equations is vital when working with polynomial functions, especially when aiming to find their zeros or intercepts, as shown in the given exercise.
Factoring
Factoring is a technique used to break down equations into simpler components. It's like reverse distributing, where you express a polynomial as a product of its simplest factors. For quadratic equations, this means finding two linear expressions that multiply together to give the original quadratic expression. This approach was utilized in the exercise to solve the polynomial function algebraically.

In the example of \[ f(x)=9x^{4}-25x^{2}, \]we performed factoring by initially rewriting it in terms of a new variable, \(X = x^2\). The equation transformed into a quadratic form \[ 9X^{2}-25X = 0. \]Here, we factor out the common term \(X\), resulting in \[ X(9X - 25) = 0. \]This indicates that the polynomial may be broken into two factors, implying that each can be zero, thus determining the roots \(X = 0\) and \(X = \frac{25}{9}\). This highlights the power of factoring in simplifying the problem of finding polynomial zeros.
Algebraic Manipulation
Algebraic Manipulation involves rewriting expressions or equations in algebra to isolate variables, simplify expressions, or solve equations. This might involve operations such as addition, subtraction, multiplication, division, or even substitution, as demonstrated in the example exercise.

In the exercise given,\[ f(x)=9x^{4}-25x^{2}, \]algebraic manipulation was a key step. By substituting \(X = x^2\), the problem was simplified into a more familiar quadratic form, which could then be easily factored and solved. This step of substitution is a powerful technique because it can transform a complex polynomial into a solvable equation by temporarily changing the variable.

After solving for \(X\), further manipulation was needed. Re-substituting \(X = x^2\) yielded equations:
  • \(x^2 = 0\), giving \(x = 0\).
  • \(x^2 = \frac{25}{9}\), providing \(x = \pm \frac{5}{3}\).
Through algebraic manipulation, you can find the zeros of polynomial equations, fully utilizing your problem-solving skills in algebra.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

From the top of a mountain road, a surveyor takes several horizontal measurements \(x\) and several vertical measurements \(y\) as shown in the table \((x\) and \(y\) are measured in feet). $$\begin{array}{|c|c|c|c|c|}\hline x & {300} & {600} & {900} & {1200} \\\ \hline y & {-25} & {-50} & {-75} & {-100} \\ \hline\end{array}$$ $$\begin{array}{|c|c|c|c|}\hline x & {1500} & {1800} & {2100} \\ \hline y & {-125} & {-150} & {-175} \\ \hline\end{array}$$ $$\begin{array}{l}{\text { (a) Sketch a scatter plot of the data. }} \\\ {\text { (b) Use a straightedge to sketch the line that you }} \\ {\text { think best fits the data. }} \\ {\text { (c) Find an equation for the line you sketched in }} \\ {\text { part (b). }}\end{array}$$ $$ \begin{array}{l}{\text { (d) Interpret the meaning of the slope of the line in }} \\ {\text { part (c) in the context of the problem. }} \\ {\text { (e) The surveyor needs to put up a road sign that }} \\ {\text { indicates the steepness of the road. For instance, }} \\ {\text { a surveyor would put up a sign that states "8% }}\end{array}$$ $$ \begin{array}{l}{\text { grade" on a road with a downhill grade that has }} \\\ {\text { a slope of }-\frac{8 .}{100 .} \text { . What should the sign state for }} \\ {\text { the road in this problem? }}\end{array}$$

Finding Parallel and Perpendicular, write equations of the lines through the given point (a) parallel to and (b) perpendicular to the given line. $$x-4=0, \quad(3,-2)$$

Finding Parallel and Perpendicular, write equations of the lines through the given point (a) parallel to and (b) perpendicular to the given line. $$3 x+4 y=7, \quad\left(-\frac{2}{3}, \frac{7}{8}\right)$$

Evaluating a Difference Quotient In Exercises \(77-84\) , find the difference quotient and simplify your answer. $$f(x)=x^{2 / 3}+1, \quad \frac{f(x)-f(8)}{x-8}, \quad x \neq 8$$

Comparing Slopes Use a graphing utility to compare the slopes of the lines \(y=m x\) , where \(m=0.5,1,2,\) and \(4 .\) Which line rises most quickly?Now, let \(m=-0.5,-1,-2,\) and \(-4 .\) Which line falls most quickly? Use a square setting to obtain a true geometric perspective. What can you conclude about the slope and the "rate" at which the line rises or falls?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.