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Think About It Is it possible for two lines with positive slopes to be perpendicular? Explain.

Short Answer

Expert verified
No, it is not possible for two lines with positive slopes to be perpendicular.

Step by step solution

01

Understanding the concept of perpendicularity

Perpendicular lines are a pair of lines that intersect at a right angle (90 degrees). If the lines are expressed in the slope-intercept form, \(y = mx + c\), where \(m\) is the slope and \(c\) is the y-intercept, then two lines are perpendicular if the product of their slopes is -1. This implies one line has a negative slope while the other has a positive slope.
02

Evaluating the possibility of having two positive slopes

Having established that the product of the slopes of two perpendicular lines is -1, it becomes clear that if both lines have positive slopes, their product cannot be -1 since the product of two positive numbers cannot be negative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
The slope-intercept form is a popular way to express the equation of a line. It looks like this: \(y = mx + c\), where:
  • \(m\) represents the slope of the line.
  • \(c\) denotes the y-intercept, which is where the line crosses the y-axis.
This form is very handy for quickly identifying how the line behaves. The slope \(m\) indicates the steepness of the line. A positive slope means the line ascends from left to right. Meanwhile, the y-intercept \(c\) gives us the exact point where the line meets the y-axis. This is extremely helpful for graphing lines, predicting values, and understanding linear relationships in algebraic contexts.
Remember, to check if two lines are perpendicular, you'll need to look at the slopes. In slope-intercept form, this is quite straightforward.
Positive Slopes
Lines with positive slopes have a distinctive upward tilt as they move from left to right on a graph. This tells us that as the x-values increase, y-values also increase.
This is a sign of a positive relationship between variables in many real-world contexts. If two lines both have positive slopes, they indicate a common direction or trend.
However, consider this when thinking about perpendicular lines:
  • The slope of one line must negate or "flip" the slope of another for them to be perpendicular.
  • If two slopes are both positive, their multiplication will never result in a negative product.
Thus, two lines with positive slopes cannot be perpendicular to each other. This is because the rule requires the product of the two slopes to be -1, which isn't possible if both are positive numbers.
Right Angle Intersection
Right angle intersections occur between perpendicular lines. Such lines meet to form a 90-degree angle. It is a crucial concept in geometry and algebra because it implies a specific mathematical relationship between their slopes.
In mathematical terms, for two lines to intersect at a right angle:
  • The product of their slopes has to be -1.
  • This means one slope must be the negative reciprocal of the other.
A simple way to visualize it is thinking about the letter "T." The horizontal and vertical parts meet perpendicularly, forming right angles.
For this right angle intersection to occur, at least one of the lines needs a negative slope if the other is positive, adhering to the aforementioned slope-product rule of -1.
Thus, two positively sloped lines cannot form such an intersection, since their product cannot satisfy the condition of being -1. This is a fundamental aspect of understanding linear relationships and is crucial when analyzing geometrical figures.

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Most popular questions from this chapter

True or False? In Exercises \(71-74\) , determine whether the statement is true or false. Justify your answer. Predicting Graphical Relationships Use a graphing utility to graph \(f, g\) , and \(h\) in the same viewing window. Before looking at the graphs, try to predict how the graphs of \(g\) and \(h\) relate to the graph of \(f .\) (a) $$f(x)=x^{2}, \quad g(x)=(x-4)^{2}h(x)=(x-4)^{2}+3 h(x)=(x-4)^{2}+3$$ (b) $$f(x)=x^{2}, g(x)=(x+1)^{2} h(x)=(x+1)^{2}-2 $$ (c) $$f(x)=x^{2}, \quad g(x)=(x+4)^{2} h(x)=(x+4)^{2}+2$$

Describing Profits Management originally predicted that the profits from the sales of a new product would be approximated by the graph of the function \(f\) shown. The actual profits are shown by the function \(g\) along with a verbal description. Use the concepts of transformations of graphs to write \(g\) in terms of \(f .\) (a) The profits were only three-fourths as large as expected. (b) The profits were consistently \(\$ 10,000\) greater than predicted. (c) There was a two-year delay in the introduction of the product. After sales began, profits grew as expected.

Comparing Slopes Use a graphing utility to compare the slopes of the lines \(y=m x\) , where \(m=0.5,1,2,\) and \(4 .\) Which line rises most quickly?Now, let \(m=-0.5,-1,-2,\) and \(-4 .\) Which line falls most quickly? Use a square setting to obtain a true geometric perspective. What can you conclude about the slope and the "rate" at which the line rises or falls?

Mathematical models that involve both direct and inverse variation are said to have _________ variation.

Finding a Relationship for Equidistance, find a relationship between \(x\) and \(y\) such that \((x, y)\) is equidistant (the same distance) from the two points. $$\left(-\frac{1}{2},-4\right),\left(\frac{7}{2}, \frac{5}{4}\right)$$

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