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In Exercises 51 - 56, evaluate \( _nC_r \) using the formula from this section. \( _5C_2 \)

Short Answer

Expert verified
The value of \( _5C_2 \) is 10.

Step by step solution

01

Calculating Factorials

Firstly, factorials need to be calculated. The factorial of a number is calculated by multiplying that number and all numbers below it down to 1. In this case, the factorials for n, r and (n-r) have to be calculated. For \( n = 5 \), \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \). For \( r = 2 \), \( 2! = 2 \times 1 = 2 \). For \( n - r = 5 - 2 = 3 \), \( 3! = 3 \times 2 \times 1 = 6 \).
02

Applying the Formula

Next, these factorial values are to be substituted into the original binomial coefficient formula to get the result. So, \( _5C_2 = \dfrac{5!}{2!(5-2)!} = \dfrac{120}{2 \times 6} = \dfrac{120}{12} = 10 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
Binomial coefficients are a key concept in combinatorics. They represent the number of ways to choose a subset of items from a larger set, without considering the order of selection. For any binomial coefficient, it's expressed as \( _nC_r \) or \( \binom{n}{r} \). Here, \( n \) is the total number of items to choose from, and \( r \) is the number of items to select.

The formula used to calculate this is given by:
  • \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \)
This formula essentially calculates the permutations of the selected items, divided by the permutations of the items not selected to prevent double-counting. By using this formula, we can find the number of possible ways to choose \( r \) items from \( n \) items, which is vital in determining probabilities and combinations in statistics and probability theory.
Factorials
Factorials are a fundamental part of various equations and are widely used in mathematics. A factorial, denoted as \( n! \), is the product of all positive integers less than or equal to \( n \). For example, 5 factorial or \( 5! \) is calculated as \( 5 \times 4 \times 3 \times 2 \times 1 = 120 \).

Factorials are crucial when calculating permutations and combinations because they help simplify the process of counting arrangements of items. In the calculation used for binomial coefficients, the factorials allow us to normalize the total permutations, ensuring that we only count the necessary arrangements or selections. This simplicity is why factorials are indispensable in combinatorial mathematics.
Permutations
Permutations refer to the arrangement of a set where the order does matter. When you calculate permutations, you're determining how many different ways you can order a set of items. This is crucial when the sequence is important, unlike combinations where the order is irrelevant.

The formula to determine permutations is:
  • \( P(n, r) = \frac{n!}{(n-r)!} \)
This formula finds the number of ways to arrange \( r \) items selected from \( n \) available items. Permutations are used in a variety of fields, including computer science, cryptography, and operations research. While the calculation of permutations looks similar to the binomial coefficient, they serve different purposes depending on whether or not the order of selection is important. Understanding the difference between permutations and combinations is vital, especially in solving complex problems involving arrangements and selections in probability theory.

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Most popular questions from this chapter

In Exercises 53 - 60, the sample spaces are large and you should use the counting principles discussed in Section 9.6. A shipment of \( 12 \) microwave ovens contains three defective units. A vending company has ordered four of these units, and because each is identically packaged, the selection will be random. What are the probabilities that (a) all four units are good,(b) exactly two units are good, and (c) at least two units are good?

A fire company keeps two rescue vehicles. Because of the demand on the vehicles and the chance of mechanical failure, the probability that a specific vehicle is available when needed is \( 90\% \). The availability of one vehicle is independent of the availability of the other. Find the probabilities that (a) both vehicles are available at a given time, (b) neither vehicle is available at a given time, and (c) at least one vehicle is available at a given time.

In Exercises 53 - 60, the sample spaces are large and you should use the counting principles discussed in Section 9.6. One card is selected at random from an ordinary deck of \( 52 \) playing cards. Find the probabilities that (a) the card is an even-numbered card,(b) the card is a heart or a diamond, and (c) the card is a nine or a face card.

A police department uses computer imaging to create digital photographs of alleged perpetrators from eyewitness accounts. One software package contains \( 195 \) hairlines, \( 99 \) sets of eyes and eyebrows, \( 89 \) noses, \( 105 \) mouths, and \( 74 \) chins and cheek structures. (a) Find the possible number of different faces that the software could create. (b) An eyewitness can clearly recall the hairline and eyes and eyebrows of a suspect. How many different faces can be produced with this information?

In Exercises 31 - 34, find the probability for the experiment of drawing two marbles (without replacement) from a bag containing one green, two yellow, and three red marbles. Both marbles are red.

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