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In Exercises 33 - 40, write the first five terms of the arithmetic sequence. \( a_1 = 5, d = 6 \)

Short Answer

Expert verified
The first five terms of the arithmetic sequence are 5, 11, 17, 23, 29

Step by step solution

01

Finding the First Term

The first term \(a_1\) of the arithmetic sequence is given as 5
02

Finding the Second Term

The second term of an arithmetic sequence is found by adding the common difference \(d\) to the first term \(a_1\). Therefore, the second term \(a_2\) is \(a_1 + d = 5 + 6 = 11\)
03

Finding the Third Term

The third term of the arithmetic sequence is found by adding the common difference \(d\) to the second term \(a_2\). Therefore, the third term \(a_3\) is \(a_2 + d = 11 + 6 = 17\)
04

Finding the Fourth Term

The fourth term of an arithmetic sequence is found by adding the common difference \(d\) to the third term \(a_3\). Therefore, the fourth term \(a_4\) is \(a_3 + d = 17 + 6 = 23\)
05

Finding the Fifth Term

The fifth term of an arithmetic sequence is found by adding the common difference \(d\) to the fourth term \(a_4\). Therefore, the fifth term \(a_5\) is \(a_4 + d = 23 + 6 = 29\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arithmetic Progression
An arithmetic progression, also called an arithmetic sequence, is a sequence of numbers in which the difference between any two consecutive terms is always the same. This constant difference is what characterizes an arithmetic progression. Such sequences are common in algebra and are easy to work with once you understand the basic principle.

The main properties of an arithmetic progression include:
  • A linear and consistent increase or decrease between terms.
  • The ability to express any term of the sequence using a formula.
  • Each term can be obtained by adding the common difference to the previous term, starting from the given initial term.
The general formula for the nth term in an arithmetic progression is:\[ a_n = a_1 + (n - 1) imes d \]where \(a_1\) is the first term, \(d\) is the common difference, and \(n\) represents the term number. Understanding these properties and this formula allows you to easily discover any term in the sequence, regardless of how far along it may be.
Common Difference
The common difference in an arithmetic sequence is a crucial component. It is the fixed amount that you add (or subtract if negative) to find the next term in the sequence. Understanding how this difference works is key to mastering arithmetic sequences.

The common difference \(d\) is calculated by subtracting the first term from the second term, giving:\[ d = a_{n+1} - a_n \]where \(a_n\) is any term and \(a_{n+1}\) is the subsequent term.

In the original problem, the common difference is given as 6. This means that each term increases by 6 to reach the next term. Knowing the common difference allows you to quickly find subsequent terms in the sequence.
Sequence Terms
Sequence terms are simply the individual elements that make up a sequence. In arithmetic sequences, each term can be calculated using an initial term and the common difference.

Let's look at the problem:
  • The first term \(a_1\) is 5.
  • The second term, \(a_2\), is calculated as \(a_1 + d = 5 + 6 = 11\).
  • The third term, \(a_3\), uses the second term: \(a_2 + d = 11 + 6 = 17\).
  • The fourth term, \(a_4\), follows likewise: \(a_3 + d = 17 + 6 = 23\).
  • Finally, the fifth term \(a_5\) is: \(a_4 + d = 23 + 6 = 29\).
In this sequence, each term builds directly upon the one before it, consistently moving forward by the common difference. By understanding how sequence terms work, you can efficiently determine each term in the sequence given the common difference and the initial term.

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Most popular questions from this chapter

Consider a group of people. (a) Explain why the following pattern gives the probabilities that the people have distinct birthdays. \( n = 2: \dfrac{365}{365} \cdot \dfrac{364}{365} = \dfrac{365 \cdot 364}{365^2} \) \( n = 3: \dfrac{365}{365} \cdot \dfrac{364}{365} \cdot \dfrac{363}{365} = \dfrac{365 \cdot 364 \cdot 363}{365^3} \) (b) Use the pattern in part (a) to write an expression for the probability that \( n = 4 \) people have distinct birthdays. (c) Let \( P_n \) be the probability that the \( n \) people have distinct birthdays. Verify that this probability can be obtained recursively by \( P_1 = 1 \) and \( P_n = \dfrac{365 - (n - 1)}{365} P_{n - 1} \). (d) Explain why \( Q_n = 1 - P_n \) gives the probability that at least two people in a group of \( n \) people have the same birthday. (e) Use the results of parts (c) and (d) to complete the table. (f) How many people must be in a group so that the probability of at least two of them having the same birthday is greater than \( \dfrac{1}{2} \)? Explain.

What is the relationship between \( _nC_r \) and \( _nC_{n - r} \)?

In Exercises 31 - 34, find the probability for the experiment of drawing two marbles (without replacement) from a bag containing one green, two yellow, and three red marbles. Both marbles are yellow.

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