/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 A customer can choose one of thr... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Problem 15

A customer can choose one of three amplifiers, one of two compact disc players, and one of five speaker models for an entertainment system. Determine the number of possible system configurations.

Short Answer

Expert verified
The number of possible system configurations is 30.

Step by step solution

01

Identify choices for each part

The problem states that the customer can choose from three amplifiers, two compact disc players, and five speaker models.
02

Apply the rule of counting

The rule of counting states that if there are n ways to do one thing, and m ways to do another, then there are n * m ways of doing both. So, in this case, the number of configurations is given by the product of the number of choices for each component. That means that the number of configurations equals to the number of amplifiers times the number of compact disc players times the number of speaker models.
03

Calculate the number of configurations

Substituting the numbers of choices into the formula from step 2 gives: (number of configurations) = (number of amplifiers) * (number of compact disc players) * (number of speaker models) = 3 * 2 * 5 = 30.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 25 - 30, find the probability for the experiment of tossing a six-sided die twice. The sum is \( 6 \).

In Exercises 39 - 42, you are given the probability that an event will not happen. Find the probability that the event will happen. \( P(E') = \dfrac{17}{35} \)

In Exercises 15 - 20, find the probability for the experiment of tossing a coin three times. Use the sample space \( S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} \). The probability of getting at least two heads

In Exercises 1 - 7, fill in the blanks. If \( P\left(E\right) = 0 \), then \( E \) is an ______ event, and if \( P\left(E\right) = 1 \), then \( E \) is a _______ event.

In Exercises 79 - 86, solve for \( n \). \( 4 \cdot _{n + 1} P_2 = _{n + 2}P_3 \)
See all solutions

Recommended explanations on Math Textbooks

Discrete Mathematics

Read Explanation

Applied Mathematics

Read Explanation

Mechanics Maths

Read Explanation

Probability and Statistics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

Logic and Functions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.