/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Two cheeseburgers and one small ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two cheeseburgers and one small order of French fries from a fast-food restaurant contain a total of \( 830 \) calories. Three cheeseburgers and two small orders of French fries contain a total of \( 1360 \) calories.Find the caloric content of each item.

Short Answer

Expert verified
Each cheeseburger has 300 calories, and each order of French fries has 230 calories.

Step by step solution

01

Define Variables

Let's denote the caloric content of a cheeseburger as \( x \) and the caloric content of a French fry order as \( y \). So, the goal is to solve for \( x \) and \( y \)
02

Formulate Equations from the Problem

The problem states: Two cheeseburgers and one small order of French fries contain a total of \( 830 \) calories. This can be written as an equation \( 2x + y = 830 \). Second statement: Three cheeseburgers and two small orders of French fries contain a total of \( 1360 \) calories. This can be written as the second equation \( 3x + 2y = 1360 \). Now, we have a system of two linear equations \( 2x + y = 830 \) and \( 3x + 2y = 1360 \).
03

Solve the Equations

In order to solve the system of equations, one might choose substitution or elimination method. However, in this case, the elimination method can be conveniently used. First, multiply the first equation by 2, this yields \( 4x + 2y = 1660 \). Now, subtract the second equation from the first multiplied equation \( 4x + 2y - (3x + 2y) = 1660 - 1360 \) to get \( x = 300 \). Now, we can substitute \( x \) into the first equation \( 2*300 + y = 830 \), and solve for \( y \) to get \( y = 230 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Caloric Content Problem
Understanding the caloric content problem involves dealing with real-life situations that can be described with mathematics, specifically with systems of linear equations. When we analyze nutrition information from food items, we often deal with caloric values, which represent the energy provided by consuming those items.

In our example, the problem revolves around finding the individual caloric content of a cheeseburger and a small order of French fries by using given information about their combined caloric values. To tackle this problem, we create equations that reflect the total calories of different combinations of these food items. This practical application not only enhances analytical skills but also illustrates how mathematics is relevant to everyday life, such as maintaining a balanced diet or making informed dietary choices.
Elimination Method
The elimination method is a robust tool for solving systems of linear equations, where you aim to solve for the unknown variables by eliminating at least one of them. This technique involves the strategic manipulation of the equations—adding, subtracting, or multiplying them—in such a way that one of the variables cancels out.

In our fast-food example, by multiplying the first equation by 2, we are able to align the coefficients of the variable 'y', making it possible to eliminate 'y' by subtracting the second equation from the first multiplied one. This strategic move simplifies our problem into a single-variable equation that can be easily solved. The elimination method is especially effective when equations are set up in a way that allows for quick and neat cancellation, and is a fundamental skill for algebra students to master.
Variable Definition
Proper variable definition is crucial for formulating and solving mathematical problems. Variables, often denoted by letters like 'x' and 'y', stand in for unknown values we are looking to find. In the example of the caloric content problem, we define 'x' to represent the calories in one cheeseburger and 'y' for the calories in one small order of French fries.

These variable definitions act as placeholders that allow us to translate given information into algebraic expressions and equations. By defining variables, we create a bridge between the quantitative data provided in the problem and the abstract mathematical processes we'll use to analyze and solve the problem.
Formulating Equations
Formulating equations is a method of expressing problems mathematically. It involves translating words and concepts into mathematical language using variables, constants, and arithmetic operations. In our caloric content problem, we translate the verbal statements about calories into two equations based on the defined variables.

The first verbal statement given is converted into the equation \( 2x + y = 830 \) and the second statement into \( 3x + 2y = 1360 \). It is imperative that each term in the equation corresponds accurately to the problem's details in order to ensure the correctness of the solution. Formulating equations is a fundamental skill that enables students to approach and solve a wide array of problems in mathematics and other disciplines.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A merchant plans to sell two models of MP3 players at prices of \(\$ 225\) and \(\$ 250\) . The \(\$ 225\) model yields a profit of \(\$ 30\) per unit and the \(\$ 250\) model yields a profit of \(\$ 31\) per unit. The merchant estimates that the total monthly demand will not exceed 275 units. The merchant does not want to invest more than \(\$ 63,000\) in inventory for these products. What is the optimal inventory level for each model? What is the optimal profit?

An investor has up to \(\$ 450,000\) to invest in two types of investments. Type A pays 6\(\%\) annually and type \(B\) pays 10\(\%\) annually. To have a well- balanced portfolio, the investor imposes the following conditions. At least one-half of the total portfolio is to be allocated to type A investments and at least one-fourth of the portfolio is to be allocated to type \(B\) investments. What is the optimal amount that should be invested in each type of investment? What is the optimal return?

A store sells two models of laptop computers. Because of the demand, the store stocks at least twice as many units of model \( A \) as of model \( B \). The costs to the store for the two models are \( \$800 \) and \( \$1200 \), respectively. The management does not want more than \( \$20,000 \) in computer inventory at any one time, and it wants at least four model \( A \) laptop computers and two model \( B \) laptop computers in inventory at all times. Find and graph a system of inequalities describing all possible inventory levels.

A warehouse supervisor is told to ship at least 50 packages of gravel that weigh 55 pounds each and at least 40 bags of stone that weigh 70 pounds each. The maximum weight capacity of the truck to be used is 7500 pounds. Find and graph a system of inequalities describing the numbers of bags of stone and gravel that can be shipped.

In Exercises 45-47, determine whether the statement is true or false. Justify your answer. When solving a linear programming problem, if the objective function has a maximum value at more than one vertex, you can assume that there are an infinite number of points that will produce the maximum value.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.