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In Exercises 11 - 20, solve the system by the method of substitution. Check your solution(s) graphically. \( \left\\{\begin{array}{l}y = -2x^2 + 2\\\y = 2\left(x^4 - 2x^2 +1\right)\end{array}\right. \)

Short Answer

Expert verified
The solution to the system of equations is \(x = 0, y = 2\), \(x = 1, y = 0\) and \(x = -1, y = 0\).

Step by step solution

01

Set the two equations equal to each other

Start by setting the two expressions for \(y\) equal to each other, which gives the equation \(-2x^2 + 2 = 2\left(x^4 - 2x^2+1\right)\).
02

Simplify the equation and solve for \(x\)

Solve the equation from step 1 by dividing the entire equation by 2 and collecting like terms on one side of the equation to get \(x^4 - x^2 = 0\)
03

Solve for \(x\)

The equation \(x^4 - x^2 = 0\) could be factored into \(x^2(x^2 - 1) = 0\). Solving this for \(x\) leads to three solutions: \(x = 0, x = 1, x = -1\).
04

Solve for \(y\)

Substituting each value of \(x\) into either of the initial equations. In this case, the simpler one to use is \(y = -2x^2 + 2\). This gives three corresponding \(y\)-values: \(y = 2\) when \(x = 0\), \(y = 0\) when \(x = -1\) and \(y = 0\) when \(x = 1\).
05

Check solutions graphically

Graph both equations on the same set of axes. The points of intersection will visually verify the solution. The graph will show that the curves intersect at the points (0,2), (1,0), and (-1,0).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The substitution method is a popular approach for solving systems of equations. It involves solving one of the equations for one variable and then substituting that expression into the other equations. This method can be particularly useful when one of the equations is already solved for a variable, making it straightforward to replace that variable in the other equations.
In our exercise, we have a system of two equations:
  • Equation 1: \( y = -2x^2 + 2 \)
  • Equation 2: \( y = 2(x^4 - 2x^2 + 1) \)
We start by equating the expressions for \( y \) from both equations, leading to a new equation: \[ -2x^2 + 2 = 2(x^4 - 2x^2 + 1) \]This simplifies solving the system by focusing on one variable at a time and making the problem more manageable by eliminating one variable through substitution.
Graphical Solution
The graphical solution provides a visual way to verify solutions for a system of equations. By plotting each equation on a graph, you can identify the points at which the graphs intersect. These intersection points represent the solutions to the system of equations where both equations are simultaneously satisfied.
In the exercise, after calculating potential solutions using algebraic methods, we equate and plot:
  • \( y = -2x^2 + 2 \)
  • \( y = 2(x^4 - 2x^2 + 1) \)
By graphing these equations, students can visually confirm the solutions obtained through substitution. The points of intersection, like (0,2), (1,0), and (-1,0), verify the accuracy of the calculated solutions. Observing the curves helps understand the relationship between the two functions beyond numerical solutions.
Polynomial Equations
Polynomial equations are algebraic expressions that include variables raised to a power and coefficients. They are of the form \( a_nx^n + a_{n-1}x^{n-1} + ... + a_1x + a_0 = 0 \), where \( n \) is a non-negative integer.
In the solved exercise, when we set the two expressions for \( y \) equal, we derived a polynomial equation:
\[ -2x^2 + 2 = 2(x^4 - 2x^2 + 1) \]This leads to:
\[ x^4 - x^2 = 0 \]This is crucial as solving polynomial equations often involves finding all roots (solutions) for the variable \( x \). The strategy typically lies in simplifying these expressions, either by factoring or applying well-known algebraic identities for higher degree polynomials.
Factoring
Factoring is a method used to solve polynomial equations that is essential when dealing with expressions involving quadratic, cubic, or higher powers.
The equation from our example, \( x^4 - x^2 = 0 \), can be factored by recognizing a common factor:
\[ x^2(x^2 - 1) = 0 \]This splits into simpler equations:
  • \( x^2 = 0 \)
  • \( x^2 - 1 = 0 \)
These can be further solved to find the specific values for \( x \):
  • \( x = 0 \)
  • \( x = 1 \) or \( x = -1 \), from solving \( x^2 - 1 = 0 \)
Factoring reduces complex equations to simpler forms that are more easily solvable, often revealing all possible solutions in a more accessible manner.

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Most popular questions from this chapter

In Exercises 21-32, use a graphing utility to graph the inequality. \( y \ge -20.74 + 2.66x \)

A person's maximum heart rate is \( 220 - x \), where \( x \) is the person's age in years for \( 20 \le x \le 70 \). When a person exercises, it is recommended that the person strive for a heart rate that is at least \( 50\% \) of the maximum and at most \( 75\% \) of the maximum. (a) Write a system of inequalities that describes the exercise target heart rate region. (b) Sketch a graph of the region in part (a). (c) Find two solutions to the system and interpret their meanings in the context of the problem.

In Exercises 29-34, the linear programming problem has an unusual characteristic. Sketch a graph of the solution region for the problem and describe the unusual characteristic. Find the minimum and maximum values of the objective function (if possible) and where they occur. Objective function: \( z = x + 2y \) Constraints: \( \hspace{1cm} x \ge 0 \) \( \hspace{1cm} y \ge 0 \) \( x + 2y \le 4 \) \( 2x + y \le 4 \)

In Exercises 21-24, find the minimum and maximum values of the objective function and where they occur, subject to the constraints \( x \ge 0, y \ge 0, 3x + y \le 15 \), and \( 4x + 3y \le 30 \) \( z = 5x + y \)

In Exercises 17-20, use a graphing utility to graph the region determined by the constraints. Then find the minimum and maximum values of the objective function and where they occur, subject to the constraints. Objective function: \( z = 3x + y \) Constraints: \( \hspace{1cm} x \ge 0 \) \( \hspace{1cm} y \ge 0 \) \( x + 4y \le 60 \) \( 3x + 2y \ge 48 \)

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