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In Exercises 67-82, use DeMoivre's Theorem to find the indicated power of the complex number. Write the result in standard form. \(4(1\ -\ \sqrt{3}i)^3\)

Short Answer

Expert verified
The cube of the given complex number is \(-8\).

Step by step solution

01

Write the Complex Number in Polar Form

A complex number \(a + bi\) can be represented in polar coordinates as \(r(\cos θ + i \sin θ)\), where \(r = \sqrt{a^2 + b^2}\) and \(θ = arctan(\frac{b}{a})\). Therefore, to write \(1 - \sqrt{3}i\) in polar form, we need to find r and θ, which are \(\sqrt{1^2 + (-\sqrt{3})^2} = 2\) and \(arctan(\frac{-\sqrt{3}}{1}) = -60°\) respectively. The polar form of \(1 - \sqrt{3}i\) is, thus, \(2(\cos (-60°) + i \sin(-60°))\).
02

Apply DeMoivre's Theorem

DeMoivre's Theorem describes the power of a complex number. It states \((r(\cos θ + i \sin θ))^n = r^n (\cos nθ + i \sin nθ)\). Replacing \(r = 2\), \(θ = -60°\), and \(n=3\), we get: \( (2^3)(\cos 3(-60°) + i \sin 3(-60°)) \) which simplifies to \(8( \cos(-180°) + i \sin(-180°))\).
03

Convert Back to Rectangular Form

Finally, convert the result back to rectangular form \(a + bi\). Using trigonometric values for the angles, it is found: \[8( \cos(-180°) + i \sin(-180°)) \rightarrow 8(-1 + 0i)\] which simplifies to \(-8\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
Complex numbers are an extension of the real numbers, and they provide a way to solve equations that do not have solutions within the real numbers alone. They consist of a real part and an imaginary part, often expressed as \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. The imaginary unit is represented as \(i\), where \(i^2 = -1\). This means that any real number can be considered a complex number with an imaginary part of zero.
  • **Real Part**: The component \(a\) in \(a + bi\).
  • **Imaginary Part**: The component \(b\) in \(a + bi\).
  • **Imaginary Unit (\

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