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In Exercises 37-46, use trigonometric identities to transform the left side of the equation into the right side \((0\ <\ \theta\ <\ \pi /2)\). (sec \(\theta\ +\) tan \(\theta\))(sec \(\theta\ -\) tan \(\theta\)) \(= 1\)

Short Answer

Expert verified
Therefore, the left side of the equation, when simplified, is equal to the right side of the equation, thereby proving the given identity.

Step by step solution

01

Write down the given equation

The given equation to solve is: \((sec \theta + tan \theta)(sec \theta - tan \theta) = 1\)
02

Expand the left side

First, remember that the product of two binomials is computed as the product of the first terms plus the product of the outer and inner terms, minus the product of the last terms. So, apply this formula to the equation: \((sec \theta + tan \theta)(sec \theta - tan \theta) = (sec^2 \theta - tan^2 \theta)\)
03

Use Trigonometric Identity

Use the Pythagorean identity of sec and tan, which is: \(1 + tan^2 \theta = sec^2 \theta\). Substitute \(tan^2 \theta = sec^2 \theta - 1\) into the expanded equation to replace \(tan^2 \theta\): \(sec^2 \theta - (sec^2 \theta - 1) = 1\)
04

Simplify the equation

Solve the equation for \(1\), which simplifies to \(sec^2 \theta - sec^2 \theta + 1 = 1\) This simplifies to \(1 = 1\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Identity
The Pythagorean identity is a fundamental relation in trigonometry. At its core, it connects the squares of the sine, cosine, and tangent functions to the number 1. Specifically, the identity states that for any angle \( \theta \), \( \sin^2(\theta) + \cos^2(\theta) = 1 \). However, there are different forms of the Pythagorean identity, derived from the reciprocal identities of sine and cosine, which are secant \( (\sec) \) and cosecant \( (\csc) \) respectively.

One of these forms involves the secant and tangent functions, as \( \sec^2(\theta) = 1 + \tan^2(\theta) \), which becomes essential when simplifying trigonometric expressions as seen in the exercise. By rearranging this identity, we can also express \( \tan^2(\theta) \) in terms of \( \sec^2(\theta) \) by subtracting one from both sides, resulting in \( \tan^2(\theta) = \sec^2(\theta) - 1 \). Understanding and applying these identities requires practice, but they serve as powerful tools for solving and simplifying a wide range of trigonometric equations.
Secant Function
The secant function, denoted as \( \sec(\theta) \), is one of the six fundamental trigonometric functions. It's the reciprocal of the cosine function, meaning \( \sec(\theta) = \frac{1}{\cos(\theta)} \). Unlike the cosine function, which oscillates between -1 and 1, the secant function can take any real value, excluding the range between -1 and 1. This happens because secant tends to approach infinity (\

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Most popular questions from this chapter

A point that moves on a coordinate line is said to be in simple ________ ________ if its distance from the origin at time \(t\) is given by either \(d = a\ \sin \omega t\) or \(d = a\ \cos \omega t\).

DATA ANALYSIS The number of hours \(H\) of daylight in Denver, Colorado on the 15th of each month are: \(1(9.67)\), \(2(10.72)\), \(3(11.92)\), \(4(13.25)\), \(5(14.37)\), \(6(14.97)\), \(7(14.72)\), \(8(13.77)\), \(9(12.48)\), \(10(11.18)\), \(11(10.00)\), \(12(9.38)\). The month is represented by \(t\), with \(t=1\) corresponding to January. A model for the data is given by \(H(t)\ =\ 12.13\ +\ 2.77\ sin[(\pi t/6)\ -\ 1.60]\). (a) Use a graphing utility to graph the data points and the model in the same viewing window. (b) What is the period of the model? Is it what you expected? Explain. (c) What is the amplitude of the model? What does it represent in the context of the problem? Explain.

HARMONIC MOTION In Exercises 53-56, find a model for simple harmonic motion satisfying the specified conditions. \(Displacement\ (t=0)\) 3 inches \(Amplitude\) 3 inches \(Period\) 1.5 seconds

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Use a graphing utility to graph \(f\) and \(g\) in the same viewing window to verify that the two functions are equal. Explain why they are equal. Identify any asymptotes of the graphs. $$ f(x)=\sin (\arctan 2 x), \quad g(x)=\frac{2 x}{\sqrt{1+4 x^{2}}} $$

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