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In Exercises 29 - 32, use a graphing utility to graph the exponential function. \( y = 2^{-x^2} \)

Short Answer

Expert verified
The graph of the given exponential function \(y = 2^{-x^2}\) is symmetrical about the y-axis, with the function intersecting the y-axis at the coordinate (0,1). The function approaches but never reaches y=0 as x moves in either the positive or negative direction.

Step by step solution

01

Input the function into the graphing tool

Open the chosen graphing utility tool (for example Desmos, GeoGebra, or a graphic calculator). Carefully input the given function \(y = 2^{-x^2}\) into the graphing tool's function field.
02

Observe and sketch the output

Observe the output graph on the tool's graph display. Sketch or plot the function's graph on a paper or in a digital medium for understanding and presentation.
03

Interpret the graph

Notice the fundamental shape and characteristics of the graph. The function is a transformed version of the basic exponential function \(y = 2^{-x}\), but squaring the variable x (making it \(x^2\)) results in a graph that is symmetrical about the y-axis. The function approaches a value of y = 0 as \(-x^2\) gets larger (in either the positive or negative direction), but it will never quite get there. Indeed, there are no x-values for which y equals zero. Furthermore, when x is 0, \(y = 2^{0}\), so y equals 1, thus, the function intersects the y axis at the coordinate (0,1).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Utility
A graphing utility is an invaluable tool for visualizing mathematical functions. It simplifies the complex task of graphing functions by hand and provides immediate graphical representations. To utilize a graphing utility effectively, you should first familiarize yourself with its interface and features.

Common functions include entering mathematical expressions, zooming, shifting the viewpoint, and changing the scale of axes which help in examining detailed behavior of functions. When inputting an exponential function like \(y = 2^{-x^2}\), ensure to understand the syntax required by your specific graphing utility, often involving correct use of parentheses and operator symbols.

Through this visualization, you’re able to quickly identify key characteristics such as intercepts, asymptotes, and intervals of increase or decrease. This tool is essential for students to confirm their understanding of how function transformations affect the graph's shape.
Exponential Function Graph
The graph of an exponential function typically displays rapid growth or decay. When graphing \(y = 2^{-x^2}\), you're dealing with an exponential decay because as \(x\) increases, \(y\) approaches zero. One common mistake is to misinterpret this function as \(y = 2^{-x}\) raised to the power of 2, which is different.

An exponential function graph is characterized by its unique J-shaped curve when graphed on a traditional xy-coordinate system. With a negative exponent, as in \(y = 2^{-x^2}\), the function experiences decay. Remember, the larger the value of \(x^2\), the smaller the value of \(y\), theoretically approaching but never reaching zero.
Function Transformation
Function transformation involves altering the basic graph of a function to produce a new graph. Several types can occur: vertical shifts, horizontal shifts, reflections, stretching, and shrinking.

In the case of the function \(y = 2^{-x^2}\), a noteworthy transformation is the exponent's alteration to \(x^2\). This specific transformation results in a reflection about the y-axis, creating a graph with symmetry. The squaring of \(x\) causes the function to take the same value for \(x\) and \(-x\), which modifies the graph's shape compared to the simpler exponential function \(y = 2^{-x}\). This results in a U-shaped graph (with the open side towards the x-axis), which is a notable deviation from the typical exponential growth or decay form.

Understanding these transformations helps in predicting how changes to the function's equation will visually affect the graph's shape and position.
Symmetry in Graphs
Graph symmetry indicates that one part of the graph is a mirror image of another part. In the context of the function \(y = 2^{-x^2}\), the symmetry is about the y-axis, known as y-axis symmetry. To test for this type of symmetry algebraically, replace \(x\) with \(-x\) in the equation and see if the original equation is obtained.

In this function, since \(x^2\) and \((-x)^2\) are equal, the value of \(y\) is the same for the positive and negative values of \(x\). You can visually confirm this symmetry by noting if the graph's left side mirrors its right side. Understanding symmetry can help simplify graph sketches and interpretations because you only need to plot points for half of the graph and replicate them on the opposite side adjusted for the axis of symmetry.

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Most popular questions from this chapter

In Exercises 81 - 112, solve the logarithmic equation algebraically. Approximate the result to three decimal places. \( \log\left(x + 4\right) - \log x = \log\left(x + 2\right) \)

At \( 8:30 \) A.M., a coroner was called to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the persons temperature twice. At \( 9:00 \) A.M. the temperature was \( 85.7^\circ F \) and at \( 11:00 \) A.M. the temperature was \( 82.8^\circ F \). From these two temperatures,the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula \( t = -10 ln \dfrac{T - 70}{98.6 - 70} where \) t \( is the time in hours elapsed since the person died and \) T \( is the temperature (in degrees Fahrenheit) of the persons body. (This formula is derived from a general cooling principle called Newtons Law of Cooling. It uses the assumptions that the person had a normal body temperature of \) 98.6^\circ F \( at death, and that the room temperature was a constant \) 70^\circ F $. ) Use the formula to estimate the time of death of the person.

In Exercises 113 - 116, use a graphing utility to graph and solve the equation. Approximate the result to three decimal places. Verify your result algebraically. \( 3 - \ln x = 0 \)

In Exercises 117 - 120, \( \$2500 \) is invested in an account at interest rate \( r \), compounded continuously. Find the time required for the amount to (a) double and (b) triple. \( r = 0.045 \)

In Exercises 81 - 112, solve the logarithmic equation algebraically. Approximate the result to three decimal places. \( -2 + 2 \ln 3x = 17 \)

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