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In Exercises 83 - 86, (a) find the interval(s) for \( b \) such that the equation has at least one real solution and (b) write a conjecture about the interval(s) based on the values of the coefficients. \( 2x^2 + bx + 5 = 0 \)

Short Answer

Expert verified
The interval for which the equation \( 2x^2 + bx + 5 = 0 \) has at least one real solution is \( -sqrt(40) <= b <= sqrt(40) \). Conjecture: The range of \( b \) for which a quadratic equation \( ax^2 + bx + c = 0 \) has at least one real solution is bound by the square root of \( 4ac \) when \( a \) and \( c \) are fixed.

Step by step solution

01

Calculate the Discriminant

The discriminant of a quadratic equation \( ax^2 + bx + c = 0 \) is given by \( D = b^2 - 4ac \). For this quadratic equation, \( a = 2, b = b \) and \( c = 5 \). Substituting these values we get \( D = b^2 - 4(2)(5) = b^2 - 40 \).
02

Find the Interval for Which the Discriminant is Nonnegative

For a quadratic equation to have at least one real solution, the discriminant must be greater than or equal to zero. So, solving for \( b \) in the inequality \( D >= 0 \) gives the solution \( b^2 - 40 >= 0 \). This inequality is equivalent to \( b^2 >= 40 \), and by taking square roots we get \( -sqrt(40) <= b <= sqrt(40) \).
03

Create a Conjecture

Since the coefficients \( a, c \) are fixed and \( b \) varies, we conjecture that for any quadratic equation with fixed \( a \) and \( c \), the interval(s) where the equation has at least one real solution depends on the magnitude of \( b \), i.e., the range of values \( b \) can take is bound by the square root of \( 4ac \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discriminant
When solving quadratic equations, the discriminant is a crucial concept. It helps determine the nature of the solutions to a quadratic equation. The discriminant is part of the quadratic formula, and it is symbolized by the letter \( D \), calculated as \( D = b^2 - 4ac \). In the context of the given equation \( 2x^2 + bx + 5 = 0 \), the discriminant becomes \( D = b^2 - 40 \).
Understanding the discriminant's value provides insight into the behavior of the solutions:
  • If \( D > 0 \), the equation has two distinct real solutions.
  • If \( D = 0 \), there is exactly one real solution, also known as a repeated or double root.
  • If \( D < 0 \), the equation does not have real solutions; instead, it has two complex conjugate solutions.
It is essential to determine the discriminant when solving quadratic equations, as it guides you whether or not real solutions exist for a given set of coefficients.
Real Solutions
Real solutions of a quadratic equation are the values of \( x \) that make the equation true. For a quadratic function \( ax^2 + bx + c = 0 \) to have at least one real solution, the discriminant \( D \) must be nonnegative, i.e., \( D \geq 0 \).
In our exercise, where the quadratic equation is given as \( 2x^2 + bx + 5 = 0 \), we aim to find \( b \) values such that the equation has real solutions. Analyzing the discriminant \( b^2 - 40 \), we focus on the inequality \( b^2 \geq 40 \).
  • Solving this inequality, we find that \( b^2 = 40 \) gives the boundary values.
  • Taking the square root provides \( -\sqrt{40} \leq b \leq \sqrt{40} \).
Thus, the interval for \( b \) is defined by these square root values, ensuring at least one real solution exists wherever the discriminant is zero or positive.
Coefficient Analysis
Analyzing the coefficients in a quadratic equation \( ax^2 + bx + c = 0 \) allows one to formulate conjectures about the nature of its solutions. The coefficients \( a, b, \) and \( c \) play distinct roles:
  • \( a \) is the leading coefficient; it determines the direction and steepness of the parabola.
  • \( b \) is the linear coefficient; it affects the location of the axis of symmetry and vertex horizontal displacement.
  • \( c \) is the constant term; it influences the vertical displacement (where the graph crosses the y-axis).
For the equation \( 2x^2 + bx + 5 = 0 \), \( a = 2 \) and \( c = 5 \) are fixed, leaving \( b \) to vary. This variability of \( b \) directly impacts the discriminant, \( D = b^2 - 40 \).
A key observation is that the value range for \( b \) dictates the possibility of real solutions. As concluded earlier, \( -\sqrt{40} \leq b \leq \sqrt{40} \) ensures at least one real solution. This insight into coefficient interaction provides groundwork for how small changes in \( b \) can significantly alter the solution set, thus underscoring the importance of understanding each coefficient's impact when analyzing quadratic equations.

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