/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 WRITING Explain how the central ... [FREE SOLUTION] | 91影视

91影视

WRITING Explain how the central rectangle of a hyperbola can be used to sketch its asymptotes.

Short Answer

Expert verified
The asymptotes of a hyperbola are theoretical lines that the curve of hyperbola approaches as it extends towards infinity without intersecting. The asymptotes coincide with the diagonals of the central rectangle of the hyperbola, making the central rectangle a crucial key in sketching asymptotes. One can simply sketch the asymptotes by drawing the diagonal lines of this rectangle.

Step by step solution

01

Explain the Central Rectangle in Hyperbola

The central rectangle in hyperbola, also known as the 'defining rectangle' or 'auxiliary rectangle', is a rectangle with sides parallel to coordinate axes. The rectangle is tangent to the hyperbola at its vertices. In terms of equation, if the hyperbola equation is in the standard form \( \frac{(x-h)^2} {a^2} - \frac{(y-k)^2} {b^2} = 1\) or \( \frac{(y-k)^2} {a^2} - \frac{(x-h)^2} {b^2}= 1\), the points \( (h \pm a, k)\) and \((h, k \pm b)\) form the vertices of this rectangle for the first and second formula respectively.
02

Determine the Asymptotes

The asymptotes of a hyperbola are the lines that the hyperbola approaches as it extends towards infinity. They are theoretical lines providing boundaries to the curve of the hyperbola but they never intersect with the hyperbola itself. For a hyperbola centered at (h,k) with horizontal transverse axis, the equations of the asymptotes are \( y = k \pm \frac{b}{a}(x - h)\), while for one with vertical transverse axis, the equations are \( y = k \pm \frac{a}{b}(x - h)\). These are also the diagonals of the central rectangle.
03

Draw the sketch of asymptotes using central rectangle

Using the central rectangle, drawing the asymptotes becomes an easy task. Simply draw diagonal lines passing through the corners of the central rectangle. These lines represent the asymptotes of the hyperbola. The hyperbola's arms will approach these lines without ever touching them as they extend towards infinity.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Rectangle
The central rectangle in a hyperbola, often termed the "defining rectangle," plays a crucial role in understanding the structure of the hyperbola. This rectangle has its sides aligned parallel to the coordinate axes, creating an easy reference for drawing or calculating properties of the hyperbola.

To find the central rectangle, use the vertices from the hyperbola's equation. For instance, for a hyperbola given by \[\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\] or \[\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1,\] the points \((h \pm a, k)\) and \((h, k \pm b)\) define the corners of the rectangle.

These vertices illustrate the intersection of the hyperbola with the rectangle, where the hyperbola 鈥渙pens outwards鈥 from the rectangle's center, \((h, k)\). The central rectangle is not just a geometric figure; it serves as a fundamental tool to sketch the hyperbola's asymptotes.
Standard Form Equation of Hyperbola
Hyperbolas are represented by a standard form equation, which is vital for identifying its geometric properties quickly. This standard form is given by either \[\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\] for a horizontal transverse axis, or \[\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1\] for a vertical transverse axis.

Here鈥檚 what each component means:
  • \((h, k)\) is the center of the hyperbola.
  • \(a\) and \(b\) dictate the distances from the center to the vertices and the co-vertices.
  • The terms \((x-h)^2/a^2\) and \((y-k)^2/b^2\) suggest an opposite relationship between the axes, indicative of a hyperbola.
Understanding this form makes it easier to visualize the hyperbola鈥檚 shape and to solve other properties, such as asymptotes and foci.
Transverse Axis
The transverse axis is a critical concept when discussing hyperbolas. Think of it as the "spine" of the hyperbola, pointing in the direction in which the hyperbola opens.

For a hyperbola in the form \[\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1,\] the transverse axis is horizontal. Conversely, for \[\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1,\] it鈥檚 vertical.

The orientation of this axis is important for determining the placement and form of the central rectangle, as well as the direction in which the hyperbola 'expands.'

The length of the transverse axis is calculated as \(2a\), because it spans from \((h-a, k)\) to \((h+a, k)\) for horizontal and \((h, k-a)\) to \((h, k+a)\) for vertical arrangements, encapsulating the primary span of the hyperbola.
Vertices of Hyperbola
Vertices of the hyperbola are its most pronounced points, where the hyperbola "peaks." These are where the curves make their closest approach to the center and typically define the shape's orientation along the transverse axis.

In the case of the horizontal transverse axis hyperbola, given by \[\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1,\] the vertices are located at the points \((h \pm a, k)\). Likewise, for a vertically oriented hyperbola, in the form \[\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1,\] the vertices are \((h, k \pm a)\).

Understanding where the vertices lie helps in sketching the hyperbola accurately. It also aids in constructing the central rectangle, as these vertices lie directly on its perimeter, crucial for accurately drawing asymptotes. The vertices are essential reference points from which the hyperbola's other attributes can be inferred and visualized.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 65-68, find an equation of the tangent line to the parabola at the given point, and find the \(x\)-intercept of the line. \(y=-2x^2, (-1, -2)\)

SOUND LOCATION You and a friend live 4 miles apart (on the same "east-west" street) and are talking on the phone. You hear a clap of thunder from lightning in a storm, and 18 seconds later your friend hears the thunder. Find an equation that gives the possible places where the lightning could have occurred. (Assume that the coordinate system is measured in feet and that sound travels at 1100 feet per second.)

SUSPENSION BRIDGE Each cable of the Golden Gate Bridge is suspended (in the shape of a parabola) between two towers that are 1280 meters apart. The top of each tower is 152 meters above the roadway. The cables touch the roadway midway between the towers. (a) Draw a sketch of the bridge. Locate the origin of a rectangular coordinate system at the center of the roadway. Label the coordinates of the known points. (b) Write an equation that models the cables. (c) Complete the table by finding the height \(y\) of the suspension cables over the roadway at a distance of \(x\) meters from the center of the bridge.

PROJECTILE MOTION Eliminate the parameter \(t\) from the parametric equations \(x = (v_0 \cos\ \theta)t \quad \quad\) and \(\quad \quad y=h+(v_0 \sin\ \theta)t-16t^2\) and for the motion of a projectile to show that the rectangular equation is \(y=-\dfrac{16\ \sec^2\ \theta}{v_{0}^{2}} x^{2} + (\tan\ \theta)x + h\).

The graph of a hyperbola has two disconnected parts called ________.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.