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In Exercises 51-56, sketch (if possible) the graph of the degenerate conic. \(x^2+2xy+y^2-1=0\)

Short Answer

Expert verified
The graph of the conic is a circle centered at the origin with a radius of 1.

Step by step solution

01

Rewrite the Equation

The given equation is not in any standard form for a conic. Hence, to visualize the graph of this particular equation, it would be very beneficial to convert it to a recognizable form. After completing the square, the equation remains the same as \(x^2+2xy+y^2-1=0\). Now this can be rewritten as \( (x+y)^2 = 1 \).
02

Identify the Conic

The equation \((x+y)^2=1\) is the formula for a circle centered around the origin with a radius of 1. The sign of both the x and the y variables are the same and thus it is a circle.
03

Sketch the Graph

Draw two axes, label them x and y. Now plot a circle centered at the origin (0,0) with radius 1. The degenerate conic is a circle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conic Sections
Conic sections are the curves obtained by intersecting a cone with a plane in different angles. They are fundamental objects in geometry and include:
  • Circles
  • Ellipses
  • Parabolas
  • Hyperbolas
Each type of conic section has its own standard equation. For example, a circle can be recognized by the form \(x^2 + y^2 = r^2\), where \(r \) is the radius.
However, equations aren't always presented in these standard forms. Sometimes they appear as more complex expressions as seen in the exercise. When certain conditions are met, these conics can also become "degenerate," which occurs when the conic section collapses into a simpler form—such as a point or a line. In the case of this exercise, we are dealing with a degenerate case, showing how even non-standard equations can represent common conic shapes like circles.
Graphing Equations
Graphing equations, especially those involving conic sections, requires understanding their equations and recognizing the form they represent. The goal is to convert complex equations into a simpler, recognizable form that can easily be sketched on a graph.
For the equation given in the exercise, \(x^2 + 2xy + y^2 - 1 = 0\), the complexity initially masks the geometric shape it represents.
  • The process involves analyzing the terms with \(x \) and \(y\) and manipulating them using algebraic methods.
  • By simplifying the equation via completing the square, it becomes possible to identify the conic section.
  • Ultimately, the equation becomes \( (x+y)^2 = 1\), revealing the underlying shape as a circle.
By adjusting and simplifying the equation, you can transform abstract equations into tangible shapes on a graph.
Completing the Square
Completing the square is a valuable algebraic technique used to simplify quadratic expressions. It's particularly useful in graphing equations to bring out recognizable forms, especially with conic sections.
  • The goal is to manipulate an equation into a perfect square trinomial, which is easily identifiable with specific conics.
  • In the exercise, the original equation \(x^2 + 2xy + y^2 - 1 = 0\) was rewritten as \( (x+y)^2 = 1\).
  • This is done by recognizing patterns within the equation and rearranging terms so that they fit the pattern of a square binomial.
Through this transformation, the equation unveils its true form, allowing you to visualize it as a simple geometric object, like a circle in this case. Completing the square is a key step in understanding and graphing complex algebraic equations related to geometric figures.

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Most popular questions from this chapter

In Exercises 15-28, identify the conic and sketch its graph. \(r=\dfrac{5}{1+\sin\ \theta}\)

Match the conic with its eccentricity. (a) \(e<1 \quad \quad \quad \quad \quad \) (b) \(e=1 \quad \quad \quad \quad \quad \) (c) \(e>1\) (i) \(\textrm{parabola} \quad \quad \quad \quad\) (ii) \(\textrm{hyperbola} \quad \quad \quad \quad\) (iii) \(\textrm{ellipse}\)

In Exercises 39-54, find a polar equation of the conic with its focus at the pole. \(\textit{Conic}\) Parabola \(\textit{Vertex or Vertices}\) \((1, -\pi/2)\)

CAPSTONE Write a brief paragraph that describes why some polar curves have equations that are simpler in polar form than in rectangular form. Besides a circle,give an example of a curve that is simpler in polar form than in rectangular form. Give an example of a curve that is simpler in rectangular form than in polar form.

SATELLITE TRACKING A satellite in a 100-mile-high circular orbit around Earth has a velocity of approximately \(17,500\) miles per hour. If this velocity is multiplied by \(\sqrt{2}\), the satellite will have the minimum velocity necessary to escape Earth's gravity and will follow a parabolic path with the center of Earth as the focus (see figure). (a) Find a polar equation of the parabolic path of the satellite (assume the radius of Earth is \(4000\) miles). (b) Use a graphing utility to graph the equation you found in part (a). (c) Find the distance between the surface of the Earth and the satellite when \(\theta\ =\ 30^{\circ}\). (d) Find the distance between the surface of Earth and the satellite when \(\theta\ =\ 60^{\circ}\).

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