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In Exercises 87-92, use the functions given by \(f(x) = \frac{1}{8}x - 3\) and \(g(x) = x^3\) to find the indicated value or function. \(g^{-1} \circ f^{-1}\)

Short Answer

Expert verified
\[ g^{-1} \circ f^{-1} = \sqrt[3]{8x + 24} \]

Step by step solution

01

Find the Inverse of f

The function \(f(x) = \frac{1}{8}x - 3\) is a linear function. To find the inverse, we replace \(f(x)\) with \(y\), then we switch \(x\) and \(y\) and then solve for \(y\):1. Start with \(y = \frac{1}{8}x - 3\)2. Swap \(x\) and \(y\) to get \(x = \frac{1}{8}y - 3\)3. Solve for \(y\) to get \(y = 8x + 24\)So, \(f^{-1}(x) = 8x + 24\)
02

Find the Inverse of g

The function \(g(x) = x^3\) is a basic cubic function. The inverse of a basic cubic function is a cube root function. \We could demonstrate this by replacing \(g(x)\) with \(y\), then we swap \(x\) and \(y\) and then solving for \(y\):1. Start with \(y = x^3\)2. Swap \(x\) and \(y\) to get \(x = y^3\)3. Solving for \(y\) gives \(y = \sqrt[3]{x}\)So, \(g^{-1}(x) = \sqrt[3]{x}\)
03

Calculate the Composite Function

Now we need to calculate the composite function \(g^{-1} \circ f^{-1}\). This means we have to replace every \(x\) in \(g^{-1}(x)\) with the function \(f^{-1}(x)\):\(g^{-1} \circ f^{-1} = g^{-1}(f^{-1}(x)) = \sqrt[3]{8x + 24}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Functions
Linear functions are one of the foundational building blocks in mathematics. They are called linear because they graph as a straight line in the Cartesian coordinate system. The general form of a linear function is given by \[ f(x) = mx + b \] where:
  • \( m \) is the slope, which determines the angle and direction of the line.
  • \( b \) is the y-intercept, where the line crosses the y-axis.
Whenever you want to find the inverse of a linear function, the process is straightforward due to its simple structure. Essentially, you swap the input and output variables and solve for the new output variable.
This step is crucial because it lets us "reverse" the process of the function, undoing its actions. An interesting property of linear functions is that they always have a linear inverse, keeping things simple yet elegant.
In our exercise, we find that the inverse of \( f(x) = \frac{1}{8}x - 3 \) is \( f^{-1}(x) = 8x + 24 \). This procedure showcases how changes or transformations in a linear function can be inverted similarly.
Cubic Functions
Cubic functions are polynomial functions of degree three. The standard form of a cubic function is \[ g(x) = ax^3 + bx^2 + cx + d \] where \( a, b, c, \) and \( d \) are constants, with \( a eq 0 \).
  • They can produce a variety of shapes when graphed, typically having one or two "turning points" where the direction of curvature changes.
  • The main characteristic of cubic functions is their ability to have one inflection point, where the function transitions from being concave to convex, or vice versa.
For basic forms like \( g(x) = x^3 \), calculating the inverse involves finding a function that, when composed with the original, yields the identity function. This means switching the roles of \( x \) and \( y \) and solving for the new function.
The inverse of a simple cubic, like in our example \( g(x) = x^3 \), is \( g^{-1}(x) = \sqrt[3]{x} \). This inverse represents the cube root function, effectively "undoing" the cubing process and showcasing the symmetry present in such operations.
Composite Functions
Composite functions are functions formed through the composition of two functions. The notation \( g \circ f \) represents a composite function, meaning \( g(f(x)) \). The process involves plugging the output of one function into the input of the other.
Composite functions can often be tricky, as they involve multitier transformations. Understanding them means grasping how each transformation affects the overall function output.
To find the composite inverse in the original problem, \( g^{-1} \circ f^{-1} \), we must scale up this concept to inverse functions.
  • This involves replacing every \( x \) in \( g^{-1}(x) \) with \( f^{-1}(x) \).
  • In other words, we solve \( g^{-1}(f^{-1}(x)) \), simplifying as needed.
In our specific exercise, this method simplifies to \( \sqrt[3]{8x + 24} \), indicating the sequential unraveling of the two inverse functions beginning with the inverse of \( f \), followed by the inverse of \( g \).
This step-by-step approach to solving composite inverses illuminates the intricate dance behaviors between mathematical functions.

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