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In Exercises 23-34, show that \(f\) and \(g\) are inverse functions (a) algebraically and (b) graphically. \(f(x) =\sqrt{x-4}\), \(g(x) = x^2 + 4\), \(x \geq 0\)

Short Answer

Expert verified
Based on the algebraic and graphical solutions, it was established that the functions \(f(x) = \sqrt{x - 4}\) and \(g(x) = x^2 + 4\) for \(x \geq 0\) are indeed inverse functions to each other.

Step by step solution

01

Algebraic Proof

Firstly, plug \(g(x)\) into \(f(x)\):\n1. Substitute \(g(x)\) into \(f\), to get \(f(g(x))\). \(g(x) = x^2+4\), so\(f(g(x)) = f(x^2+4) = \sqrt{(x^2+4)-4} = \sqrt{x^2} = x\). It's \(x\) because \(x \geq 0\) (given in exercise).\n2. Likewise, substitute \(f(x)\) into \(g(x)\), to get \(g(f(x))\). \(f(x) = \sqrt{x-4}\), so\(g(f(x)) = g(\sqrt{x-4}) = (\sqrt{x-4})^2 + 4 = x-4 + 4 = x\). Both results satisfy the condition \(f(g(x)) = x\) and \(g(f(x)) = x\), which imply \(f\) and \(g\) are inverses algebraically.
02

Graphical Proof

Sketch the graphs of \(f\) and \(g\) along with the identity function \(y=x\). Both the graphs of \(f\) and \(g\) should be reflecting about the identity line \(y=x\). This represents a graphical interpretation that \(f\) and \(g\) are indeed inverse functions of each other. To make this happen, you need to be skilled in graphing functions, knowing how to graph the square root function \(f(x) = \sqrt{x - 4}\) (a shift of base function \(\sqrt{x}\) to the right by 4) and the quadratic function \(g(x) = x^2 + 4\) (a shift of base function \(x^2\) upward by 4).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebraic Proof of Inverse Functions
Understanding the algebraic proof of inverse functions can initially seem daunting, but it's a fundamental concept within algebra that one should grasp.
Let's demystify this by exploring the relationship between two functions, traditionally denoted as \(f(x)\) and \(g(x)\). When we substitute \(g(x)\) into \(f(x)\), and if the result simplifies to the input value \(x\), we have shown that \(f(g(x)) = x\). Concurrently, if substituting \(f(x)\) into \(g(x)\) also yields \(x\), such that \(g(f(x)) = x\), this affirms that the functions are inverses of each other on the algebraic front.
These steps were aptly demonstrated in the exercise with the functions given as \(f(x) = \sqrt{x-4}\) and \(g(x) = x^2 + 4\), where the domain is restricted to \(x \geq 0\). This domain constraint is crucial because it ensures the square root yields a non-negative result in accordance with the principal square root definition.
Take note that the restriction also aligns with the function \(g(x)\), as squaring any real number results in a non-negative value, thereby fulfilling the original domain constraint.
Graphical Proof of Inverse Functions
The graphical proof is equally important in understanding inverse functions. It lends a visual representation to the abstract algebraic manipulations.
To graphically show that two functions are inverses, you need to plot both functions on the same set of axes. If the functions are indeed inverses, their graphs will be symmetric with respect to the line \(y=x\).
This symmetry happens because for any point \((a, b)\) on the graph of \(f(x)\), there should be a corresponding point \((b, a)\) on the graph of \(g(x)\). Thus, if you plotted both \(f(x)\) and \(g(x)\) in reference to the given exercise, you would observe this exact symmetry when drawing the plots on a graph. The resulting images would echo each other across the line \(y=x\), visually confirming their inverse relationship.
Understanding the Square Root Function
The square root function is a crucial concept in mathematics, rooted in its ability to reverse the action of squaring a number.
The basic form of a square root function is \(f(x) = \sqrt{x}\). However, this can be shifted horizontally or vertically to create various transformations.
For instance, the function \(f(x) = \sqrt{x - 4}\), like in the exercise, represents a horizontal shift of the basic square root function 4 units to the right. This change affects the domain of the function, since you can only take the square root of non-negative numbers, setting the new domain as \(x \geq 4\).
When sketching the square root function, it starts at the point corresponding to the horizontal shift (in this case, (4, 0)) and extends to the right in a gradually increasing curve. Knowing this characteristic shape helps in graphically determining inverse relationships.
Exploring the Quadratic Function
A quadratic function is a second-degree polynomial, typically written in the form \(f(x) = ax^2 + bx + c\). The basic graph of a quadratic function is a parabola that opens upwards or downwards depending on the sign of the leading coefficient \(a\).
The exercise provided showcases a specific example of a quadratic function shifted vertically: \(g(x) = x^2 + 4\). This function represents a parabola opening upwards with its vertex translated 4 units up the y-axis. It's important to note that for the function in the exercise, the coefficient of \(x^2\) is positive, reassuring that the parabola opens upwards.
The domain of any quadratic function is all real numbers, but when identifying an inverse, we must consider restrictions that ensure the function is one-to-one. In our case, the restriction \(x \geq 0\) ensures the parabola is half of a normal 'U' shape, enabling it to have an inverse. Recognizing these transformations and restrictions is essential for both graphing the function and understanding its inverse relationships.

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Most popular questions from this chapter

BEAM LOAD The maximum load that can be safely supported by a horizontal beam varies jointly as the width of the beam and the square of its depth, and inversely as the length of the beam. Determine the changes in the maximum safe load under the following conditions. (a) The width and length of the beam are doubled. (b) The width and depth of the beam are doubled. (c) All three of the dimensions are doubled. (d) The depth of the beam is halved.

SPORTS The lengths (in feet) of the winning men's discus throws in the Olympics from 1920 through 2008 are listed below. (Source: International Olympic Committee) 1920 146.6 1924 151.3 1928 155.3 1932 162.3 1936 165.6 1948 173.2 1952 180.5 1956 184.9 1960 194.2 1964 200.1 1968 212.5 1972 211.3 1976 221.5 1980 218.7 1984 218.5 1988 225.8 1992 213.7 1996 227.7 2000 227.3 2004 229.3 2008 225.8 (a) Sketch a scatter plot of the data. Let \(y\) represent the length of the winning discus throw (in feet) and let \(t=20\) represent 1920. (b) Use a straightedge to sketch the best-fitting line through the points and find an equation of the line. (c) Use the \(regression\) feature of a graphing utility to find the least squares regression line that fits the data. (d) Compare the linear model you found in part (b) with the linear model given by the graphing utility in part (c). (e) Use the models from parts (b) and (c) to estimate the winning men's discus throw in the year 2012.

In direct variation models of the form \(y = kr\), \(k\) is called the ________ of ________.

MEASUREMENT On a yardstick with scales in inches and centimeters, you notice that 13 inches is approximately the same length as 33 centimeters. Use this information to find a mathematical model that relates centimeters \(y\) to inches \(x\). Then use the model to find the numbers of centimeters in 10 inches and 20 inches.

Statisticians use a measure called ________ of________ ________ to find a model that approximates a set of data most accurately.

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