/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 In Exercise 15-24, determine the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercise 15-24, determine the quadrant(s) in which \( (x, y) \) is located so that the condition(s) is (are) satisfied. \( x > 4 \)

Short Answer

Expert verified
Under the condition x > 4, (x, y) is located in either Quadrant I or Quadrant IV.

Step by step solution

01

Understand the condition

The condition presented is x > 4. This means that the x coordinate must be any value that is greater than 4.
02

Identify the quadrant(s)

Given the condition that x > 4, y can be any value: positive or negative. Therefore, the possible quadrants for (x, y) to be located are Quadrant I (where x and y are both positive) and Quadrant IV (where x is positive, but y is negative).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordinate Plane
The coordinate plane is a two-dimensional surface on which we can plot points and navigate through different quadrants using pairs of numerical coordinates. Each point on this plane is defined by a pair of numbers
  • x-coordinate: This indicates horizontal movement, moving right if positive and left if negative.
  • y-coordinate: This represents vertical movement, moving up if positive and down if negative.
The plane is divided into four quadrants by the intersection of the x-axis and the y-axis (both coordinate axes): 1. **Quadrant I:** Both x and y are positive. 2. **Quadrant II:** x is negative, y is positive. 3. **Quadrant III:** Both x and y are negative. 4. **Quadrant IV:** x is positive, y is negative. Understanding these quadrants is crucial, especially when working with conditions such as inequalities involving x and y as seen in the exercise.
Inequalities
Inequalities describe the relationship between two expressions that are not necessarily equal and use symbols like <, >, ≤, and ≥ to express this relationship. They can determine the range of possible values for variables on a coordinate plane. For instance, the inequality \[ x > 4 \] tells us that x must be greater than four. This immediately rules out any points where x is less than or equal to four.Applying this to the coordinate plane:
  • This inequality means we only focus on those parts of the coordinate plane to the right of the vertical line x = 4.
  • Since y is not constrained in the inequality, it can be any positive or negative value.
So, we find that points fulfilling this inequality can be in the first or fourth quadrants because only these quadrants have positive x-values.
Precalculus
Precalculus lays the foundation for understanding concepts in calculus by focusing on functions, analytical geometry, and mathematical modeling. As it introduces students to various mathematical ideas including functions, trigonometry, and limits, it builds critical skills for solving complex calculus problems. When tackling exercises that ask us to determine quadrants for given conditions or inequalities, precalculus teaches us to:
  • Interpret and graph inequalities on the coordinate plane effectively.
  • Understand the behavior of functions in different quadrants.
  • Analyze how restrictions like \[ x > 4 \] limit points to specific quadrants through visualization and graphing.
By gaining proficiency in these areas, students develop the necessary skills for progressing to higher-level mathematics courses seamlessly.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

MUSIC The frequency of vibrations of a piano string varies directly as the square root of the tension on the string and inversely as the length of the string. The middle A string has a frequency of 440 vibrations per second. Find the frequency of a string that has 1.25 times as much tension and is 1.2 times as long.

MEASUREMENT On a yardstick with scales in inches and centimeters, you notice that 13 inches is approximately the same length as 33 centimeters. Use this information to find a mathematical model that relates centimeters \(y\) to inches \(x\). Then use the model to find the numbers of centimeters in 10 inches and 20 inches.

FLUID FLOW The velocity \(v\) of a fluid flowing in a conduit is inversely proportional to the cross-sectional area of the conduit. (Assume that the volume of the flow per unit of time is held constant.) Determine the change in the velocity of water flowing from a hose when a person places a finger over the end of the hose to decrease its cross-sectional area by 25%.

In Exercises 109-112, determine if the situation could be represented by a one-to-one function. If so, write a statement that describes the inverse function. The number of miles \(n\) a marathon runner has completed in terms of the time \(t\) in hours

BEAM LOAD The maximum load that can be safely supported by a horizontal beam varies jointly as the width of the beam and the square of its depth, and inversely as the length of the beam. Determine the changes in the maximum safe load under the following conditions. (a) The width and length of the beam are doubled. (b) The width and depth of the beam are doubled. (c) All three of the dimensions are doubled. (d) The depth of the beam is halved.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.