/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 In Exercises 17-22, use the Vert... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises 17-22, use the Vertical Line Test to determine whether \(y\) is a function of \(x\). To print an enlarged copy of the graph, go to the website \(www.mathgraphs.com\). \(y=\frac{1}{2}x^2\)

Short Answer

Expert verified
Yes, \(y=\frac{1}{2}x^2\) is a function of \(x\) as it passes the Vertical Line test. Meaning, any vertical line drawn intersects the graph at only one point.

Step by step solution

01

Identify the Equation

The given equation is \(y=\frac{1}{2}x^2\).
02

Understanding the Graph

This is a quadratic function and its graph will be a parabola opening upwards. For every \(x\) value, there will be exactly one \(y\) value in the graph.
03

Applying the Vertical Line Test

By drawing vertical lines through the graph of the equation, we can see that at any point, it intersects the graph only at a single point.
04

Conclusion

Based on the Vertical Line Test, the graph for the given equation \(y=\frac{1}{2}x^2\) represents a function because any vertical line would intersect the graph at exactly one point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Determination
Understanding whether a given relation is a function is fundamental in mathematics. The 'Vertical Line Test' is a quick visual method to determine if a graph represents a function. The test is performed by imagining or drawing vertical lines across the graph of a relation. If any vertical line intersects the graph at more than one point, then the relation is not a function. This is because, in functions, each input value or 'x' is associated with exactly one output value or 'y'. In the context of the exercise, when you apply the Vertical Line Test to the graph of
\( y = \frac{1}{2}x^2 \),
you'll notice that every vertical line will intersect the graph at only one point, indicating that 'y' is indeed a function of 'x'. This concept is crucial for students to grasp as it paves the way for understanding more complex function relationships and behaviors.
Quadratic Function
A quadratic function is a second-degree polynomial function of the form
\( f(x) = ax^2 + bx + c \)
where 'a', 'b', and 'c' are constants and 'a' is not zero. The shape of the graph of a quadratic function is known as a parabola. It can either open upwards, like a U, if 'a' is positive, or open downwards, like an upside-down U, if 'a' is negative. The given equation in the exercise,
\( y = \frac{1}{2}x^2 \),
clearly has the form of a quadratic function with 'a' being \( \frac{1}{2} \), 'b' and 'c' being zero, establishing it as a simple quadratic function without linear or constant terms. This function will produce a graph of a parabola opening upwards and its vertex at the origin.
Graph of a Function
The graph of a function represents all the possible pairs of input (x-values) and output (y-values) that satisfy the function's equation. For the quadratic function
\( y = \frac{1}{2}x^2 \),
the graph is a visual representation of how 'y' changes with each change in 'x'. It's important to recognize different parts of the graph, such as the vertex, axis of symmetry, and the direction in which the parabola opens. The vertex is the point where the graph changes direction. For this exercise, the graph of \( y = \frac{1}{2}x^2 \) has its vertex at the origin (0,0), indicating the lowest point on the graph since the parabola opens upwards. The axis of symmetry is the vertical line that passes through the vertex, and for this function, it is the y-axis. A well-drawn graph fosters comprehension and enables students to visualize and anticipate the behavior of functions.
Parabola
A parabola is the curve defined as the set of all points that are equidistant from a fixed point called the focus and a line called the directrix. In the case of the quadratic function
\( y = \frac{1}{2}x^2 \),
the parabola is a symmetrical graph where every point is shaped in an 'open-mouth' curve. The parabola that represents this function opens upward, which aligns with the positive coefficient of \( x^2 \). The symmetry of a parabola is an essential concept, as it reveals that for every 'x' value to the left of the vertex, there is a corresponding 'x' value to the right that will yield the same 'y' value. The apex of this particular parabola is at the coordinate origin, (0,0), where the minimum value of 'y' occurs when 'x' is 0. Understanding the properties of parabolas assists students in graphing quadratic functions and solving related real-world problems.

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Most popular questions from this chapter

TAXES Property tax is based on the assessed value of a property. A house that has an assessed value of \(\$150,000\) has a property tax of \(\$5520\). Find a mathematical model that gives the amount of property tax \(y\) in terms of the assessed value \(x\) of the property. Use the model to find the property tax on a house that has an assessed value of \(\$225,000\).

HOURLY WAGE Your wage is \(\$10.00\) per hour plus \(\$0.75\) for each unit produced per hour. So, your hourly wage \(y\) in terms of the number of units produced \(x\) is \(y = 10 + 0.75x\). (a) Find the inverse function. What does each variable represent in the inverse function? (b) Determine the number of units produced when your hourly wage is \(\$24.25\).

The direct variation model \(y = kr^n\) can be described as "\(y\) varies directly as the \(n\)th power of \(x\)," or "\(y\) is ________ ________ to the \(n\)th power of \(x\)."

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DATA ANALYSIS: LIGHT INTENSITY A light probe is located \(x\) centimeters from a light source, and the intensity \(y\) (in microwatts per square centimeter) of the light is measured. The results are shown as ordered pairs \((x, y)\). \((30, 0.1881)\) \((34, 0.1543)\) \((38, 0.1172)\) \((42, 0.0998)\) \((48, 0.0775)\) \((50, 0.0645)\) A model for the data is \(y = 262.76/x^{2.12}\) (a) Use a graphing utility to plot the data points and the model in the same viewing window. (b) Use the model to approximate the light intensity 25 centimeters from the light source.

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