Chapter 1: Problem 16
In Exercises 11-18, (a) write the linear function \(f\) such that it has the indicated function values and (b) sketch the graph of the function. \(f(-10) = 12\), \(f(16) = -1\)
Short Answer
Expert verified
The linear function is \(f(x) = -\frac{13}{26}x + 7\)
Step by step solution
01
Find the Slope
The slope 'm' of the function can be found using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Using the given points (-10, 12) and (16, -1) in this formula yields \(m = \frac{-1 - 12}{16 - (-10)} = -\frac{13}{26}\).
02
Find the Y-intercept
Next, substitute one of the given points and the found slope into the formula \(y = mx + b\) to solve for the y-intercept 'b'. Substituting (-10, 12) gives \(12 = -\frac{13}{26}*(-10) + b\), which implies that \(b = 12 - 5 = 7\).
03
Write the Function
With the slope and y-intercept calculated, the function can be written out as \(f(x) = -\frac{13}{26}x + 7\).
04
Sketching the Graph
To generate a sketch of this function, first plot the y-intercept (0,7). Then, since the slope is -13/26, for every 26 units the function moves to the right, it will move 13 units down. Place another point according to this movement and draw a line connecting these two points, extending beyond both. The complete line represents the function graph.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope Calculation
Understanding the slope of a linear function is key to graphing and analyzing the behavior of the line it represents. The slope is a measure of the steepness of the line and the direction in which the line moves. To calculate it, simply use the formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \), where \( (x_1, y_1) \) and \( (x_2, y_2) \) are two distinct points on the line.
For example, with the points \( (-10, 12) \) and \( (16, -1) \) provided in our exercise, we can compute the slope as follows:\[ m = \frac{(-1) - 12}{16 - (-10)} = -\frac{13}{26} \].
The negative sign tells us that the line is descending from left to right. A simple check to ensure understanding is to plot these points on a coordinate plane and visually assess the direction the line would take. This visualization aids in grasping the concept of slope deeply.
For example, with the points \( (-10, 12) \) and \( (16, -1) \) provided in our exercise, we can compute the slope as follows:\[ m = \frac{(-1) - 12}{16 - (-10)} = -\frac{13}{26} \].
The negative sign tells us that the line is descending from left to right. A simple check to ensure understanding is to plot these points on a coordinate plane and visually assess the direction the line would take. This visualization aids in grasping the concept of slope deeply.
Y-Intercept Determination
The y-intercept is where the graph of a linear function crosses the y-axis. This essentially means it's the value of \( y \) when \( x =0 \). After finding the slope, determining the y-intercept will allow us to write the linear equation fully.
To find the y-intercept, we can plug in either one of the given points and the calculated slope into the slope-intercept form of a linear equation \( y = mx + b \) and then solve for \( b \) (the y-intercept). From our example, using the point \( (-10, 12) \) and slope \( -\frac{13}{26} \) gives us:
\[ 12 = -\frac{13}{26} \times (-10) + b \], which simplifies to \( b = 7 \).
Therefore, our y-intercept is 7, which again can be visualized on a graph as the point where the line will cross the y-axis. It's important for students to recognize that the y-intercept is a key anchor point for graphing and for understanding the function's equation.
To find the y-intercept, we can plug in either one of the given points and the calculated slope into the slope-intercept form of a linear equation \( y = mx + b \) and then solve for \( b \) (the y-intercept). From our example, using the point \( (-10, 12) \) and slope \( -\frac{13}{26} \) gives us:
\[ 12 = -\frac{13}{26} \times (-10) + b \], which simplifies to \( b = 7 \).
Therefore, our y-intercept is 7, which again can be visualized on a graph as the point where the line will cross the y-axis. It's important for students to recognize that the y-intercept is a key anchor point for graphing and for understanding the function's equation.
Function Graph Sketching
Sketching the graph of a function is a visual representation and an essential skill for interpreting data and functions. It requires understanding both the slope and y-intercept that we previously determined.
To sketch the graph of the function \( f(x) = -\frac{13}{26}x + 7 \), start with the y-intercept (0,7) by placing a point on the y-axis at 7. Then, use the slope to determine the direction and steepness. For our negative slope of \( -\frac{13}{26} \), we recognize for every 26 units moved horizontally to the right, the line will drop 13 units vertically. This will give a second point which can be used to draw the line.
By connecting these two points and extending the line on both sides, we'd have a sketch of our linear function. It's beneficial for students to practice this process with various slopes and y-intercepts to get comfortable with graphing lines. In addition, using a ruler or graphing tool can help ensure accuracy in the drawing, reinforcing the connection between the algebraic and geometric representations of a function.
To sketch the graph of the function \( f(x) = -\frac{13}{26}x + 7 \), start with the y-intercept (0,7) by placing a point on the y-axis at 7. Then, use the slope to determine the direction and steepness. For our negative slope of \( -\frac{13}{26} \), we recognize for every 26 units moved horizontally to the right, the line will drop 13 units vertically. This will give a second point which can be used to draw the line.
By connecting these two points and extending the line on both sides, we'd have a sketch of our linear function. It's beneficial for students to practice this process with various slopes and y-intercepts to get comfortable with graphing lines. In addition, using a ruler or graphing tool can help ensure accuracy in the drawing, reinforcing the connection between the algebraic and geometric representations of a function.