Chapter 8: Problem 5
Sketch the curve that has the given set of parametric equations. $$ x=\sqrt{t}, y=5-t, \quad t \geq 0 $$
Short Answer
Expert verified
The curve is a downward-opening parabola with vertex at (0, 5), starting from x=0.
Step by step solution
01
Understanding the Parametric Equations
We are given that the parametric equations are \( x = \sqrt{t} \) and \( y = 5 - t \) with \( t \geq 0 \). This means that the parameter \( t \) represents time, and as \( t \) increases, \( x \) and \( y \) change accordingly.
02
Eliminate the Parameter
To sketch the curve, we commonly eliminate the parameter \( t \). We start with the equation for \( x \): \( x = \sqrt{t} \). Squaring both sides, we get \( t = x^2 \). Substitute this expression for \( t \) into the equation for \( y \): \( y = 5 - x^2 \).
03
Identify the Curve
The resulting equation \( y = 5 - x^2 \) is a quadratic equation representing a parabola that opens downwards. The vertex of this parabola is at the point \( (0, 5) \).
04
Determine Domain and Range
Since \( t \geq 0 \), and \( x = \sqrt{t} \), \( x \) is always non-negative (\( x \geq 0 \)). The range of \( y = 5 - x^2 \) is determined by the maximum value of \( y \), which is 5 at \( x = 0 \). Therefore, \( y \) decreases as \( x \) increases.
05
Sketch the Curve
On the coordinate plane, plot the point where the curve starts, at \( (0, 5) \). As \( x \) increases from 0, \( y \) will decrease following the parabola \( y = 5 - x^2 \). The curve is in the first and second quadrants, extending downward from the vertex at \( (0, 5) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curve Sketching
Curve sketching is a graphical technique used to draw the curve based on given equations. With parametric equations, like in this exercise, each coordinate \((x, y)\) on the plane is defined by a separate function of a parameter \( t \). These parametric functions describe how the \( x \) and \( y \) coordinates change as \( t \) varies.
In the given example, where \( x = \sqrt{t} \) and \( y = 5 - t \), we start by eliminating the parameter. Rewriting the equations helps in determining a clear relation between \( x \) and \( y \). Once we eliminate the parameter, the problem becomes simpler, turning into a problem of recognizing known types of equations, like a quadratic equation.
Here are some tips for effective curve sketching with parametric equations:
In the given example, where \( x = \sqrt{t} \) and \( y = 5 - t \), we start by eliminating the parameter. Rewriting the equations helps in determining a clear relation between \( x \) and \( y \). Once we eliminate the parameter, the problem becomes simpler, turning into a problem of recognizing known types of equations, like a quadratic equation.
Here are some tips for effective curve sketching with parametric equations:
- Identify how each parameter \( t \) affects \( x \) and \( y \). You are essentially watching how the curve evolves as \( t \) changes.
- Think about the geometry: As \( t \) increases, consider how the shape and direction of the curve develop.
- Once the parameter is removed, see if the resulting equation reminds you of any common graphs.
Quadratic Equation
A quadratic equation is a second-degree polynomial, typically described by the form \( y = ax^2 + bx + c \). In many cases, quadratic equations describe parabolas, which is also the result in this exercise.
The parabola from this problem is described by the equation \( y = 5 - x^2 \). This is a transformation of the basic form \( y = x^2 \), but inverted due to the negative sign. Each quadratic equation unfolds into a specific shape, with its opening determined by the sign of \( a \) (negative here, resulting in a downward-opening parabola).
Key properties to remember with quadratic equations:
The parabola from this problem is described by the equation \( y = 5 - x^2 \). This is a transformation of the basic form \( y = x^2 \), but inverted due to the negative sign. Each quadratic equation unfolds into a specific shape, with its opening determined by the sign of \( a \) (negative here, resulting in a downward-opening parabola).
Key properties to remember with quadratic equations:
- The coefficient \( a \) (positive or negative) dictates whether the parabola opens up or down.
- The vertex form of the equation \( y = a(x-h)^2 + k \) reveals the vertex \( (h, k) \), which is the highest or lowest point on the curve.
- In \( y = 5 - x^2 \), the vertex is \( (0, 5) \), showcasing the maximum point of the parabola.
Parabola
A parabola is a symmetrical, U-shaped curve that can open upwards or downwards on a graph. Parabolas are the graphical representation of quadratic equations.
In this exercise, after transforming the parametric equations to \( y = 5 - x^2 \), we realize the curve is a downward-opening parabola with its vertex at \( (0, 5) \). This is because of the negative sign in front of \( x^2 \), and the vertex represents the maximum point in the curve.
Some important features of parabolas include:
In this exercise, after transforming the parametric equations to \( y = 5 - x^2 \), we realize the curve is a downward-opening parabola with its vertex at \( (0, 5) \). This is because of the negative sign in front of \( x^2 \), and the vertex represents the maximum point in the curve.
Some important features of parabolas include:
- The direction (up or down) is determined by whether the \( x^2 \) term is positive or negative.
- The axis of symmetry is a vertical line through the vertex. In this problem, the axis of symmetry is the \( y \)-axis itself.
- A parabola continues indefinitely in its opening direction, broadening the further from the vertex it gets.