Chapter 8: Problem 3
Sketch the curve that has the given set of parametric equations. $$ x=t-1, y=2 t-1,-1 \leq t \leq 5 $$
Short Answer
Expert verified
The sketch forms a line, \( y = 2x + 1 \), from \( (-2,-3) \) to \( (4,9) \).
Step by step solution
01
Understand the Parametric Equations
The parametric equations given are \( x = t - 1 \) and \( y = 2t - 1 \). These equations express both \( x \) and \( y \) in terms of the parameter \( t \).
02
Eliminate the Parameter
To eliminate the parameter \( t \), solve the equation \( x = t - 1 \) for \( t \), giving \( t = x + 1 \). Substitute this into the equation for \( y \) to get \( y = 2(x + 1) - 1 \). Thus, \( y = 2x + 2 - 1 \), simplifying to \( y = 2x + 1 \). This is the equation of a line.
03
Determine the Range
The parameter \( t \) is given by the interval \(-1 \leq t \leq 5\). Based on this, calculate the range for \( x \): when \( t = -1 \), \( x = -1 - 1 = -2 \); when \( t = 5 \), \( x = 5 - 1 = 4 \). Thus, \( -2 \leq x \leq 4 \).
04
Plot the Graph Using Points
Use several values of \( t \) to find specific points: For \( t = -1, x = -2, y = -3 \), point is (-2,-3); for \( t = 0, x = -1, y = -1 \), point is (-1,-1); for \( t = 2, x = 1, y = 3 \), point is (1,3); for \( t = 5, x = 4, y = 9 \), point is (4,9).
05
Sketch the Line
Draw a line through the points (-2,-3), (-1,-1), (1,3), and (4,9). This line is \( y = 2x + 1 \) with \( x \) ranging from -2 to 4.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eliminating Parameters
Eliminating parameters is a technique used to convert parametric equations into a single equation in terms of just one variable, usually expressed as "y" in terms of "x". In our exercise, we start with parametric equations, where both the x and y coordinates of points on a curve are expressed in terms of a third variable "t", called the parameter.
To eliminate "t", we solve one of the equations for "t" and substitute it into the other. Consider our example:
To eliminate "t", we solve one of the equations for "t" and substitute it into the other. Consider our example:
- Given: \( x = t - 1 \).
- Solving for "t": \( t = x + 1 \).
- Substituting into \( y = 2t - 1 \) gives \( y = 2(x + 1) - 1 \).
- This simplifies to the linear equation: \( y = 2x + 1 \).
Sketching Graphs
Sketching graphs from parametric equations involves finding critical points and understanding the curve's direction and range. Once we convert parametric equations into a familiar form such as "y = mx + b", our job of sketching becomes straightforward. Let's break this down:
- The line equation from our exercise is \( y = 2x + 1 \) which demonstrates a straight line.
- We need to focus on the given range of "t", which in turn gives us the range of "x": \(-2 \leq x \leq 4\).
- For \( t = -1 \): \( (x, y) = (-2, -3) \)
- For \( t = 0 \): \( (x, y) = (-1, -1) \)
- For \( t = 2 \): \( (x, y) = (1, 3) \)
- For \( t = 5 \): \( (x, y) = (4, 9) \)
Linear Equations
Linear equations represent some of the simplest forms of relationships between variables, typically in the format \( y = mx + b \), where "m" is the slope and "b" is the y-intercept. They are fundamental in graph theory for depicting direct relationships.
In our exercise, after eliminating the parameter, we derived the linear equation \( y = 2x + 1 \). This equation has some key properties:
In our exercise, after eliminating the parameter, we derived the linear equation \( y = 2x + 1 \). This equation has some key properties:
- Slope (m): In this case, 2, which tells us the line rises by 2 units for every 1 unit it moves horizontally.
- Y-intercept (b): The line crosses the y-axis at \( y = 1 \), meaning when x is zero, y is one.