/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Find an equation of a sphere tha... [FREE SOLUTION] | 91Ó°ÊÓ

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Find an equation of a sphere that satisfies the given conditions. $$ \text { Center }(1,1,4) ; \text { tangent to the } x y \text { -plane } $$

Short Answer

Expert verified
The equation of the sphere is \((x-1)^2 + (y-1)^2 + (z-4)^2 = 16\).

Step by step solution

01

Understanding the Problem

We need to find the equation of a sphere. A sphere is defined by its center and radius. We are given the center of the sphere as (1, 1, 4) and told that the sphere is tangent to the xy-plane.
02

Sphere Equation Formula

The general equation for a sphere with center ext (h, k, l) and radius is: . Plug in the center (1, 1, 4) into this equation. The sphere equation becomes: .
03

Determine Sphere's Radius

Since the sphere is tangent to the xy-plane, the distance from the center of the sphere to the xy-plane is equal to the radius of the sphere. The perpendicular distance from the center (1, 1, 4) to the xy-plane is the z-coordinate of the center, which is . Therefore, the radius of the sphere is 4.
04

Forming the Equation

Substitute the center (1, 1, 4) and the radius 4 into the sphere equation to form the specific equation: .
05

Final Sphere Equation

The equation of the sphere with center (1, 1, 4) and radius 4 is . This is the equation that defines the sphere based on the given conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Center of the Sphere
The center of a sphere is a crucial component when defining its equation. In this specific exercise, we are given the center at coordinates \((1, 1, 4)\). This means that the sphere is positioned in three-dimensional space with its center at the point where:
  • The x-coordinate is 1
  • The y-coordinate is 1
  • The z-coordinate is 4
The center's coordinates directly influence the structure and position of the sphere's equation.The equation of a sphere is generally represented as: \[(x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\]where - \(h, k, l\) are the coordinates of the center, and - \(r\) is the radius. Substituting in the center coordinates from our given problem (1, 1, 4), we start forming the sphere's equation.
Radius of the Sphere
The radius of a sphere represents the distance from the center to any point on its surface. In our exercise, the sphere is tangent to the \(xy\)-plane.This tangency condition provides vital information about the sphere's radius.Tangent to the \(xy\)-plane means the shortest distance between the center of the sphere and the \(xy\)-plane is equal to the radius.In this case, the z-coordinate of the center determines this distance.Thus, for our sphere with the center at \((1, 1, 4)\), the radius \(r\) is the z-coordinate value, i.e., \(r = 4\). Hence, we already know the formula for calculating the sphere's radius based on the height above the \(xy\)-plane. Now, integrate this radius back into the sphere's equation, which helps in finalizing its definition.
Tangent to the Plane
When a sphere is tangent to a particular plane, it touches the plane at precisely one point. For this exercise, the sphere is tangent to the \(xy\)-plane.This condition simplifies our calculations considerably.
  • The tangency means that the perpendicular distance between the sphere's center and the plane is exactly equal to the sphere's radius.
  • This relationship is especially significant as it allows us to set the radius as the z-coordinate from the center \((1, 1, 4)\), which is \(4\).
Using this information, we can ascertain the complete sphere equation:\[(x - 1)^2 + (y - 1)^2 + (z - 4)^2 = 4^2\]This tangency ensures that only the specified radius fits perfectly in contact with the plane, comprehensively determining the sphere's geometry.

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