Chapter 5: Problem 7
Sketch the given vector. Find the magnitude and the smallest positive direction angle of each vector. $$ -10 \mathbf{i}+10 \mathbf{j} $$
Short Answer
Expert verified
Magnitude is \(10\sqrt{2}\), direction angle is \(135^\circ\).
Step by step solution
01
Sketch the Vector
The vector \(-10 \mathbf{i} + 10 \mathbf{j}\) can be represented in a Cartesian coordinate system where \(-10 \mathbf{i}\) is the horizontal component (x-axis) and \(10 \mathbf{j}\) is the vertical component (y-axis). To sketch this vector, start at the origin (0, 0), move 10 units left due to \(-10 \mathbf{i}\), and then 10 units up due to \(10 \mathbf{j}\). Draw an arrow from the origin to the point (-10, 10).
02
Calculate the Magnitude of the Vector
The magnitude of a vector \(\mathbf{v} = a \mathbf{i} + b \mathbf{j}\) is calculated using the formula \(\|\mathbf{v}\| = \sqrt{a^2 + b^2}\). For \(-10 \mathbf{i} + 10 \mathbf{j}\), the magnitude is \(\sqrt{(-10)^2 + (10)^2} = \sqrt{100 + 100} = \sqrt{200}\). Simplifying further gives \(\sqrt{200} = 10\sqrt{2}\).
03
Find the Smallest Positive Direction Angle
The direction angle \(\theta\) of a vector can be found by calculating the inverse tangent of the ratio of its y-component to its x-component: \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\). For this vector, \(\theta = \tan^{-1}\left(\frac{10}{-10}\right) = \tan^{-1}(-1)\). This angle typically gives \(-45^\circ\); however, since the vector is in the second quadrant (negative x, positive y), the smallest positive direction angle is \(180^\circ - 45^\circ = 135^\circ\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of a Vector
The magnitude of a vector in vector mathematics refers to its length or size. Imagine a vector as an arrow that describes a movement from one point to another in a coordinate system. The magnitude tells us how long this arrow is.
Given a vector \(-10 \mathbf{i} + 10 \mathbf{j}\), its magnitude can be calculated using the Pythagorean theorem. This is because the vector can be visualized as the hypotenuse of a right triangle formed by its horizontal and vertical components.
We use the formula:
Understanding vector magnitude is essential as it helps in determining the strength or intensity of the vector. It is always a non-negative value and provides an insight into the vector's impact in various applications like physics, engineering, and more.
Given a vector \(-10 \mathbf{i} + 10 \mathbf{j}\), its magnitude can be calculated using the Pythagorean theorem. This is because the vector can be visualized as the hypotenuse of a right triangle formed by its horizontal and vertical components.
We use the formula:
- \(\|\mathbf{v}\| = \sqrt{a^2 + b^2}\)
Understanding vector magnitude is essential as it helps in determining the strength or intensity of the vector. It is always a non-negative value and provides an insight into the vector's impact in various applications like physics, engineering, and more.
Direction Angle of a Vector
The direction angle of a vector is the angle a vector makes with the positive x-axis of the Cartesian coordinate system, measured counterclockwise. This angle gives us information about the vector's orientation in the plane.
To find this angle for a vector \(-10 \mathbf{i} + 10 \mathbf{j}\), we use the tangent function which relates angles to the ratio of the opposite side to the adjacent side in a right triangle.
The formula used is:
Since plotting \(-10 \mathbf{i} + 10 \mathbf{j}\) places the vector in the second quadrant (negative x, positive y), the direction angle is adjusted from \(-45^\circ\) to \(135^\circ\), as angles in the second quadrant are obtained by subtracting the acute angle from \(180^\circ\).
Direction angles help in translating vector components into a more intuitive directional description, crucial for understanding trajectories and navigational paths.
To find this angle for a vector \(-10 \mathbf{i} + 10 \mathbf{j}\), we use the tangent function which relates angles to the ratio of the opposite side to the adjacent side in a right triangle.
The formula used is:
- \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\)
Since plotting \(-10 \mathbf{i} + 10 \mathbf{j}\) places the vector in the second quadrant (negative x, positive y), the direction angle is adjusted from \(-45^\circ\) to \(135^\circ\), as angles in the second quadrant are obtained by subtracting the acute angle from \(180^\circ\).
Direction angles help in translating vector components into a more intuitive directional description, crucial for understanding trajectories and navigational paths.
Cartesian Coordinate System
The Cartesian coordinate system is a two-dimensional plane defined by a horizontal line (x-axis) and a vertical line (y-axis). Points in this system are identified by pairs of numbers \(x, y\) that signify their positions along these axes.
Vectors like \(-10 \mathbf{i} + 10 \mathbf{j}\) are plotted in this system by moving from the origin (0, 0) according to their components:
The Cartesian coordinate system is vital because it allows for the visual representation and analysis of mathematical concepts and vector operations. It simplifies complex problems into a manageable format by providing a clear view of how vectors behave and interact with each other within a defined space. Understanding this coordinate system is fundamental for exploring geometry, physics, and engineering problems where spatial relationships are involved.
Vectors like \(-10 \mathbf{i} + 10 \mathbf{j}\) are plotted in this system by moving from the origin (0, 0) according to their components:
- Move left or right parallel to the x-axis for the horizontal component (\(-10 \mathbf{i}\))
- Move up or down parallel to the y-axis for the vertical component (\(10 \mathbf{j}\))
The Cartesian coordinate system is vital because it allows for the visual representation and analysis of mathematical concepts and vector operations. It simplifies complex problems into a manageable format by providing a clear view of how vectors behave and interact with each other within a defined space. Understanding this coordinate system is fundamental for exploring geometry, physics, and engineering problems where spatial relationships are involved.