/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Sketch the given vector. Find th... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the given vector. Find the magnitude and the smallest positive direction angle of each vector. $$ -10 \mathbf{i}+10 \mathbf{j} $$

Short Answer

Expert verified
Magnitude is \(10\sqrt{2}\), direction angle is \(135^\circ\).

Step by step solution

01

Sketch the Vector

The vector \(-10 \mathbf{i} + 10 \mathbf{j}\) can be represented in a Cartesian coordinate system where \(-10 \mathbf{i}\) is the horizontal component (x-axis) and \(10 \mathbf{j}\) is the vertical component (y-axis). To sketch this vector, start at the origin (0, 0), move 10 units left due to \(-10 \mathbf{i}\), and then 10 units up due to \(10 \mathbf{j}\). Draw an arrow from the origin to the point (-10, 10).
02

Calculate the Magnitude of the Vector

The magnitude of a vector \(\mathbf{v} = a \mathbf{i} + b \mathbf{j}\) is calculated using the formula \(\|\mathbf{v}\| = \sqrt{a^2 + b^2}\). For \(-10 \mathbf{i} + 10 \mathbf{j}\), the magnitude is \(\sqrt{(-10)^2 + (10)^2} = \sqrt{100 + 100} = \sqrt{200}\). Simplifying further gives \(\sqrt{200} = 10\sqrt{2}\).
03

Find the Smallest Positive Direction Angle

The direction angle \(\theta\) of a vector can be found by calculating the inverse tangent of the ratio of its y-component to its x-component: \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\). For this vector, \(\theta = \tan^{-1}\left(\frac{10}{-10}\right) = \tan^{-1}(-1)\). This angle typically gives \(-45^\circ\); however, since the vector is in the second quadrant (negative x, positive y), the smallest positive direction angle is \(180^\circ - 45^\circ = 135^\circ\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnitude of a Vector
The magnitude of a vector in vector mathematics refers to its length or size. Imagine a vector as an arrow that describes a movement from one point to another in a coordinate system. The magnitude tells us how long this arrow is.

Given a vector \(-10 \mathbf{i} + 10 \mathbf{j}\), its magnitude can be calculated using the Pythagorean theorem. This is because the vector can be visualized as the hypotenuse of a right triangle formed by its horizontal and vertical components.

We use the formula:
  • \(\|\mathbf{v}\| = \sqrt{a^2 + b^2}\)
Here, \(a = -10\) and \(b = 10\). So, the magnitude is \(\sqrt{(-10)^2 + (10)^2} = \sqrt{200}\), which simplifies to \(10\sqrt{2}\).

Understanding vector magnitude is essential as it helps in determining the strength or intensity of the vector. It is always a non-negative value and provides an insight into the vector's impact in various applications like physics, engineering, and more.
Direction Angle of a Vector
The direction angle of a vector is the angle a vector makes with the positive x-axis of the Cartesian coordinate system, measured counterclockwise. This angle gives us information about the vector's orientation in the plane.

To find this angle for a vector \(-10 \mathbf{i} + 10 \mathbf{j}\), we use the tangent function which relates angles to the ratio of the opposite side to the adjacent side in a right triangle.

The formula used is:
  • \(\theta = \tan^{-1}\left(\frac{b}{a}\right)\)
Here, \(a = -10\) and \(b = 10\), giving us \(\theta = \tan^{-1}\left(\frac{10}{-10}\right) = \tan^{-1}(-1)\).

Since plotting \(-10 \mathbf{i} + 10 \mathbf{j}\) places the vector in the second quadrant (negative x, positive y), the direction angle is adjusted from \(-45^\circ\) to \(135^\circ\), as angles in the second quadrant are obtained by subtracting the acute angle from \(180^\circ\).

Direction angles help in translating vector components into a more intuitive directional description, crucial for understanding trajectories and navigational paths.
Cartesian Coordinate System
The Cartesian coordinate system is a two-dimensional plane defined by a horizontal line (x-axis) and a vertical line (y-axis). Points in this system are identified by pairs of numbers \(x, y\) that signify their positions along these axes.

Vectors like \(-10 \mathbf{i} + 10 \mathbf{j}\) are plotted in this system by moving from the origin (0, 0) according to their components:
  • Move left or right parallel to the x-axis for the horizontal component (\(-10 \mathbf{i}\))
  • Move up or down parallel to the y-axis for the vertical component (\(10 \mathbf{j}\))
This places the tail of the vector at the origin and the head at the calculated endpoint, \(-10, 10\).

The Cartesian coordinate system is vital because it allows for the visual representation and analysis of mathematical concepts and vector operations. It simplifies complex problems into a manageable format by providing a clear view of how vectors behave and interact with each other within a defined space. Understanding this coordinate system is fundamental for exploring geometry, physics, and engineering problems where spatial relationships are involved.

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