Chapter 4: Problem 71
If \(P\left(x_{1}\right)\) and \(P\left(x_{2}\right)\) are points in quadrant II on the terminal side of the angles \(x_{1}\) and \(x_{2}\), respectively, with \(\cos x_{1}=-\frac{1}{3}\) and \(\sin x_{2}=\frac{2}{3}\), find (a) \(\sin \left(x_{1}+x_{2}\right),(b) \cos \left(x_{1}+x_{2}\right),(\mathbf{c}) \sin \left(x_{1}-x_{2}\right)\), and (d) \(\cos \left(x_{1}-x_{2}\right)\).
Short Answer
Step by step solution
Understanding the Problem
Identify Known Values
Calculate \(\sin x_{1}\) from \(\cos x_{1}\)
Calculate \(\cos x_{2}\) from \(\sin x_{2}\)
Applying Sum Formulas
Find \(\sin(x_1 + x_2)\)
Find \(\cos(x_1 + x_2)\)
Applying Difference Formulas
Find \(\sin(x_1 - x_2)\)
Find \(\cos(x_1 - x_2)\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sum and Difference Formulas
- The formula for \(\sin(a + b)\) is \(\sin a \cos b + \cos a \sin b\).
- The formula for \(\cos(a + b)\) is \(\cos a \cos b - \sin a \sin b\).
- The formula for \(\sin(a - b)\) is \(\sin a \cos b - \cos a \sin b\).
- The formula for \(\cos(a - b)\) is \(\cos a \cos b + \sin a \sin b\).
Pythagorean Identity
- \(\sin^2 x = 1 - \cos^2 x = 1 - \left(-\frac{1}{3}\right)^2 = \frac{8}{9}\)
- \(\sin x = \sqrt{\frac{8}{9}} = \frac{2\sqrt{2}}{3}\)
Quadrant II Trigonometric Values
Trigonometric Calculations
- For \( \sin(x_1 + x_2) \), use \( \sin x_1 \cos x_2 + \cos x_1 \sin x_2 \).
- For \( \cos(x_1 + x_2) \), use \( \cos x_1 \cos x_2 - \sin x_1 \sin x_2 \).
- For \( \sin(x_1 - x_2) \), use \( \sin x_1 \cos x_2 - \cos x_1 \sin x_2 \).
- For \( \cos(x_1 - x_2) \), use \( \cos x_1 \cos x_2 + \sin x_1 \sin x_2 \).