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Find the amplitude, period, and phase shift of the given function. Sketch at least one cycle of the graph. $$ y=-2 \cos \left(2 x-\frac{\pi}{6}\right) $$

Short Answer

Expert verified
Amplitude: 2, Period: \(\pi\), Phase shift: \(\frac{\pi}{12}\) to the right.

Step by step solution

01

Identify the Form of the Cosine Function

The given function is in the form \( y = a \cos(bx - c) + d \). Here, \( a = -2 \), \( b = 2 \), \( c = \frac{\pi}{6} \), and \( d = 0 \). This will help us identify amplitude, period, and phase shift.
02

Determine the Amplitude

The amplitude of a cosine function \( y = a \cos(bx - c) \) is \( |a| \). Therefore, the amplitude for the function \( y = -2 \cos(2x - \frac{\pi}{6}) \) is \( |-2| = 2 \).
03

Calculate the Period

The period of a cosine function is calculated as \( \frac{2\pi}{b} \). Here, \( b = 2 \), so the period is \( \frac{2\pi}{2} = \pi \).
04

Find the Phase Shift

The phase shift of the function \( y = a \cos(bx - c) \) is given by \( \frac{c}{b} \). In this case, the phase shift is \( \frac{\frac{\pi}{6}}{2} = \frac{\pi}{12} \). Since the expression is \( bx - c \), the phase shift is to the right by \( \frac{\pi}{12} \).
05

Sketch One Cycle of the Graph

Start by plotting one cycle of cosine, which ranges from \( x = 0 \) to \( x = \pi \). Apply the amplitude (which inverts and scales the graph according to \( -2 \)), then shift the starting point to \( x = \frac{\pi}{12} \) to account for the phase shift. The graph should touch the y-axis around \( (\frac{\pi}{12}, -2) \), return to \( y = 0 \) at \( x = \frac{\pi}{2} + \frac{\pi}{12} \), rise to \( (\frac{\pi}{12} + \pi, 2) \), and conclude the cycle at \( x = \pi + \frac{\pi}{12} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude
When we talk about the amplitude of a trigonometric function, we're referring to the "height" of the wave, which is essentially the maximum distance it goes from its equilibrium position (the center line of the wave graph).

For the cosine function given in this exercise, the formula is \( y = -2 \cos(2x - \frac{\pi}{6}) \). The amplitude is found by taking the absolute value of the coefficient in front of the cosine function, which is "\( a \)" in the formula \( y = a \cos(bx - c) + d \).
  • Here, \( a = -2 \) so the amplitude is \( |-2| = 2 \).
  • Amplitude is always positive, as it represents distance.
This means that the graph of our function will oscillate 2 units above and below the central axis (which is \( y = 0 \) since \( d = 0 \)). The negative sign in front of the "2" indicates that our function starts by going downwards rather than upwards.
Period
The period of a trigonometric function tells us how long it takes for the function to complete one full cycle.

In the general cosine function \( y = a \cos(bx - c) \), the period is calculated by the formula \( \frac{2\pi}{b} \).
  • For this problem, \( b = 2 \), which makes the period \( \frac{2\pi}{2} = \pi \).
  • This indicates that the wave repeats every \( \pi \) units.
Understanding the period is crucial because it tells you how frequently the wave pattern repeats itself over the x-axis. So, for \( y = -2 \cos(2x - \frac{\pi}{6}) \), you can expect one complete cycle of the wave from \( x = 0 \) to \( x = \pi \).
Phase Shift
Phase shift describes how the graph of the trigonometric function is slid horizontally from its usual position.

The formula to calculate the phase shift for the function \( y = a \cos(bx-c) \) is \( \frac{c}{b} \).
  • In our equation, \( c = \frac{\pi}{6} \) and \( b = 2 \).
  • This results in a phase shift of \( \frac{\frac{\pi}{6}}{2} = \frac{\pi}{12} \).
Since the formula \( bx - c \) suggests the shift is to the right, the graph is slid to the right by \( \frac{\pi}{12} \) units. This phase shift adjusts where the cycle of the cosine wave begins on the x-axis.
Cosine Function
The cosine function is a fundamental trigonometric function that describes a wave-like pattern. It is periodic, meaning it repeats its values in a regular cycle.

The general form of a cosine function is \( y = a \cos(bx-c) + d \). Here, each variable component influences the graph in different ways:
  • "\( a \)" affects the amplitude.
  • "\( b \)" determines the period.
  • "\( c \)" impacts the phase shift.
  • "\( d \)" adjusts the vertical shift, though it is zero in our case.
In the equation \( y = -2 \cos(2x - \frac{\pi}{6}) \), the graph typically starts at the peak, but given a negative sign in front of \( a \), it begins at a trough (negative peak). The cosine function is essential for modeling cyclical patterns and can be found in various scientific contexts, from sound waves to light waves, making it a vital part of trigonometry study.

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