/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Use the given information to fin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the given information to find (a) \(\cos 2 x,(b) \sin 2 x\), and \((c) \tan 2 x\). $$ \tan x=\frac{1}{2}, \quad \pi

Short Answer

Expert verified
(a) \(\cos 2x = \frac{3}{5}\); (b) \(\sin 2x = \frac{4}{5}\); (c) \(\tan 2x = \frac{4}{3}\).

Step by step solution

01

Determine the quadrant and angle restrictions

Given the range \(\pi < x < 3\pi/2\), we know \(x\) is in the third quadrant. In this quadrant, the cosine and sine functions are negative, and tangent is positive since \( \tan x = \frac{1}{2} \). Identifying this helps in proceeding with calculations correctly.
02

Use the identity for tangent to find sine and cosine

The identity for tangent is \( \tan x = \frac{\sin x}{\cos x} \). Since \( \tan x = \frac{1}{2} \), we set \( \frac{\sin x}{\cos x} = \frac{1}{2} \), or \( \sin x = \frac{1}{2} \cos x \).
03

Use Pythagorean identity to find \(\sin x\) and \(\cos x\) separately

Use the identity \( \sin^2 x + \cos^2 x = 1 \). Substituting \( \sin x = \frac{1}{2} \cos x \), we have:\[\left(\frac{1}{2} \cos x\right)^2 + \cos^2 x = 1\]Simplify to solve for \( \cos^2 x \). This leads to:\[\frac{1}{4} \cos^2 x + \cos^2 x = 1 \\frac{5}{4} \cos^2 x = 1 \\cos^2 x = \frac{4}{5}\]Since \(x\) is in the third quadrant, \(\cos x = -\sqrt{\frac{4}{5}} = -\frac{2}{\sqrt{5}} \). Thus, \(\sin x = \frac{1}{2} \left(-\frac{2}{\sqrt{5}}\right) = -\frac{1}{\sqrt{5}} \).
04

Calculate \(\cos 2x\) using double angle identity

Use the double angle formula for cosine: \[\cos 2x = \cos^2 x - \sin^2 x\]Substitute the values found:\[\cos 2x = \left(-\frac{2}{\sqrt{5}}\right)^2 - \left(-\frac{1}{\sqrt{5}}\right)^2 = \frac{4}{5} - \frac{1}{5} = \frac{3}{5}\]Hence, \(\cos 2x = \frac{3}{5}\).
05

Calculate \(\sin 2x\) using double angle identity

Use the double angle formula for sine:\[\sin 2x = 2 \sin x \cos x\]Substitute the values found:\[\sin 2x = 2 \times \left(-\frac{1}{\sqrt{5}}\right) \times \left(-\frac{2}{\sqrt{5}}\right) \\sin 2x = \frac{4}{5}\]Thus, \(\sin 2x = \frac{4}{5}\).
06

Calculate \(\tan 2x\) using the identity

Using the identity \( \tan 2x = \frac{\sin 2x}{\cos 2x} \), substitute the values found:\[\tan 2x = \frac{\frac{4}{5}}{\frac{3}{5}} = \frac{4}{3}\]Therefore, \(\tan 2x = \frac{4}{3}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Double Angle Identities
Double angle identities are a set of trigonometric expressions that are particularly useful for simplifying calculations involving angles that are twice another angle. These identities allow us to determine the values of trigonometric functions for twice the angle. There are specific formulas for sine, cosine, and tangent, such as:
  • For cosine: \(\cos 2x = \cos^2 x - \sin^2 x\) or \(\cos 2x = 2 \cos^2 x - 1\)
  • For sine: \(\sin 2x = 2 \sin x \cos x\)
  • For tangent: \(\tan 2x = \frac{2 \tan x}{1 - \tan^2 x}\)
In the given problem, using these double angle identities helps in correctly finding the trigonometric functions for \(2x\). By employing these identities step by step, it becomes straightforward to compute \(\cos 2x\), \(\sin 2x\), and \(\tan 2x\). Each identity simplifies the calculations by turning them into algebraic expressions based on known functions.
Trigonometric Functions
Trigonometric functions are essential in mathematics, especially when dealing with angles and modeling cycles. These functions include sine, cosine, and tangent, each with unique properties. They are often used to express relations between the angles and sides of triangles. Each function helps to resolve different aspects of a problem:
  • The sine function \(\sin x\) represents the ratio of the opposite side to the hypotenuse in a right triangle.
  • The cosine function \(\cos x\) represents the ratio of the adjacent side to the hypotenuse.
  • The tangent function \(\tan x\) is defined as the ratio of the sine to the cosine: \(\tan x = \frac{\sin x}{\cos x}\).
Understanding these trigonometric functions and how they relate is key in applying formulas like double angle identities in problems such as the one described.
Quadrant Analysis
Quadrant analysis is a crucial step in assessing the properties of trigonometric functions. The Cartesian coordinate system divides the plane into four quadrants, each influencing the sign of trigonometric values differently:
  • In the first quadrant, all functions \(\sin x\), \(\cos x\), and \(\tan x\) are positive.
  • In the second quadrant, \(\sin x\) is positive, while \(\cos x\) and \(\tan x\) are negative.
  • In the third quadrant, both \(\tan x\) and \(\sin x\) are negative, therefore, their quotient \(\tan x\) is positive.
  • In the fourth quadrant, \(\cos x\) is positive, while \(\tan x\) and \(\sin x\) are negative.
In the problem, the given range for \(x\) is \(\pi < x < 3\pi/2\), indicating that \(x\) is in the third quadrant. This informs us that \(\cos x\) and \(\sin x\) will be negative, while \(\tan x\) will be positive, guiding us in properly assessing the calculated values of the trigonometric functions for \(2x\). Quadrant analysis ensures no error in the signs of the function values, helping in delivering accurate results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the period, \(x\) -intercepts, and the vertical asymptotes of the given function. Sketch at least one cycle of the graph. $$ y=\frac{1}{4} \cot \left(x-\frac{\pi}{2}\right) $$

Hours of Daylight The number \(H\) of daylight hours per day in various locations in the world can be modeled by a function of the form $$ H(t)=A \sin B(t-C)+D $$ where the variable \(t\) represents the number of days in a year corresponding to a specific calendar date (for example, February 1 corresponds to \(t=32\) In this problem we construct a model for Los Angeles, CA for the year 2017 (not a leap year) using data obtained from the U.S. Naval Observatory, Washington, D.C. (a) Find the amplitude \(A\) if 14.43 is the maximum number of daylight hours at the summer solstice and if 9.88 is the minimum number of daylight hours at the winter solstice. (b) Find \(B\) if the function \(H(t)\) is to have the period 365 days. (c) For Los Angeles in the year 2017 , we choose \(C\) \(=79 .\) Explain the significance of this number. [Hint: \(C\) has the same units as \(t\).] (d) Find \(D\) if the number of daylight hours at the vernal equinox for 2017 is 12.14 and occurs on March 20 (e) What does the model \(H(t)\) predict to be the number of daylight hours on January 1 ? On June 21 ? On August 1 ? On December 21 ? (f) Using a graphing utility to obtain the graph of \(H(t)\) on the interval [0,365] .

Find the indicated value without the use of a calculator. $$ \tan \frac{23 \pi}{4} $$

Write an equation of the function whose graph is described in words. The graph of \(y=\cos x\) is vertically stretched up by a factor of 3 and shifted down by 5 units. One cycle of \(y=\cos x\) on \([0,2 \pi]\) is compressed to [0 \(\pi / 3]\) and then the compressed cycle is shifted horizontally \(\pi / 4\) units to the left.

Use the given information to find the values of the remaining five trigonometric functions. $$ \sec x=-5, \pi / 2

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.