Chapter 4: Problem 3
Given that \(\sin t=-\frac{2}{3}\) and that \(P(t)\) is a point in the third quadrant, find \(\cos t\).
Short Answer
Expert verified
\( \cos t = -\frac{\sqrt{5}}{3} \).
Step by step solution
01
Understanding Quadrantal Signs
In the third quadrant, both sine and cosine values are negative. Since we are given that \( \sin t = -\frac{2}{3} \), \( \cos t \) must also be negative.
02
Use Pythagorean Identity
Recall the Pythagorean identity: \( \sin^2 t + \cos^2 t = 1 \). Substitute \( \sin t = -\frac{2}{3} \) into the identity:\(\left(-\frac{2}{3}\right)^2 + \cos^2 t = 1.\)
03
Calculate \( \sin^2 t \)
Calculate \( \sin^2 t \) by squaring \( \sin t = -\frac{2}{3} \):\(\sin^2 t = \left(-\frac{2}{3}\right)^2 = \frac{4}{9}.\)
04
Solve for \( \cos^2 t \)
Substitute \( \sin^2 t = \frac{4}{9} \) into the Pythagorean identity:\(\frac{4}{9} + \cos^2 t = 1.\)Subtract \( \frac{4}{9} \) from both sides to obtain:\(\cos^2 t = 1 - \frac{4}{9} = \frac{5}{9}.\)
05
Find \( \cos t \)
Take the square root of both sides to solve for \( \cos t \):\(\cos t = -\sqrt{\frac{5}{9}} = -\frac{\sqrt{5}}{3}.\)We choose the negative root because \( P(t) \) is in the third quadrant, where cosine is negative.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pythagorean Identity
The Pythagorean identity is a fundamental relation in trigonometry that connects the sine and cosine functions. It states that for any angle \( t \), the following equation holds:\[\sin^2 t + \cos^2 t = 1\]This identity is derived from the Pythagorean theorem, which relates the sides of a right triangle. Understanding this identity allows for the calculation of one trigonometric function if the other is known. For example, in the exercise, knowing \( \sin t = -\frac{2}{3} \) lets us find \( \cos t \) by rearranging the identity:
- First, calculate \( \sin^2 t \) as \( \left(-\frac{2}{3}\right)^2 = \frac{4}{9} \).
- Then substitute into the identity: \( \frac{4}{9} + \cos^2 t = 1 \).
- Solving for \( \cos^2 t \), we get \( \cos^2 t = \frac{5}{9} \).
Quadrants in Trigonometry
In trigonometry, the coordinate plane is divided into four quadrants, each affecting the signs of trigonometric functions. These quadrants are:
- 1st Quadrant: Sine, cosine, and tangent are all positive.
- 2nd Quadrant: Sine is positive, cosine and tangent are negative.
- 3rd Quadrant: Sine and cosine are negative, tangent is positive.
- 4th Quadrant: Cosine is positive, sine and tangent are negative.
Sign of Trigonometric Functions
The sign of trigonometric functions depends greatly on the quadrant in which the angle lies. Each quadrant imposes a rule on whether the sine, cosine, and tangent of angles are positive or negative. Let's review some key points:
- Sine: Positive in the 1st and 2nd quadrants, negative in the 3rd and 4th quadrants.
- Cosine: Positive in the 1st and 4th quadrants, negative in the 2nd and 3rd quadrants.
- Tangent: Positive in the 1st and 3rd quadrants, negative in the 2nd and 4th quadrants.
- \( \sin t \) is negative, as initially given.
- \( \cos t \) must also be negative, confirmed by choosing the correct root when applying the Pythagorean identity.