Chapter 3: Problem 22
Find all real zeros of the given polynomial function \(f\). Then factor \(f(x)\) using only real numbers. $$ f(x)=6 x^{3}+23 x^{2}+3 x-14 $$
Short Answer
Expert verified
The real zeros are 1, -\frac{4}{3}, and -4. The factorization is \((x - 1)(3x + 4)(2x + 8)\).
Step by step solution
01
Use the Rational Root Theorem
The Rational Root Theorem suggests potential rational zeros are all combinations of the factors of the constant term (-14) divided by factors of the leading coefficient (6). Therefore, the possible rational roots are \(\pm 1, \pm 2, \pm 7, \pm 14, \pm \frac{1}{2}, \pm \frac{7}{2}, \pm \frac{1}{3}, \pm \frac{2}{3}, \pm \frac{7}{3}, \pm \frac{14}{3}, \pm \frac{1}{6}, \pm \frac{7}{6}\).
02
Test Rational Roots
Check these potential roots by plugging them into the polynomial and finding which ones yield a remainder of zero when divided into the polynomial using synthetic division or direct substitution. After testing, we find that \( x = 1 \) is a root.
03
Perform Synthetic Division
Perform synthetic division with \( x = 1 \) on \( f(x) \). Dividing \( 6x^3 + 23x^2 + 3x - 14 \) by \( x - 1 \) gives a quotient of \( 6x^2 + 29x + 32 \) with a remainder of 0, confirming \( x = 1 \) is a root.
04
Factor the Quadratic
Factor the quadratic polynomial \( 6x^2 + 29x + 32 \). Use either the AC method or quadratic formula. By applying the quadratic formula, \( x = \frac{-29 \pm \sqrt{(29)^2-4 \cdot 6 \cdot 32}}{2 \cdot 6} \), and solving, find the quadratic factors to be \( (3x + 4)(2x + 8) \).
05
Write the Complete Factorization
With roots \( x = 1, \ x = -\frac{4}{3}, \text{ and } x = -4 \), the complete factorization of the polynomial \( f(x) \) over the real numbers is \((x - 1)(3x + 4)(2x + 8)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Function
A polynomial function is an expression made of variables and coefficients that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. For example, the polynomial function given in the exercise is
When analyzing a polynomial function, we are interested in finding its roots. Roots are simply the values of \( x \) that make the function equal to zero. This means solving the equation \( f(x) = 0 \). By finding the roots, we can also express the polynomial as a product of simpler factors.
- \( f(x) = 6x^3 + 23x^2 + 3x - 14 \).
When analyzing a polynomial function, we are interested in finding its roots. Roots are simply the values of \( x \) that make the function equal to zero. This means solving the equation \( f(x) = 0 \). By finding the roots, we can also express the polynomial as a product of simpler factors.
Synthetic Division
Synthetic division is a simplified method of dividing a polynomial by a linear factor of the form \( x - c \). It is particularly useful when applying the Rational Root Theorem to find potential roots of a polynomial. In synthetic division, you only need to write down the coefficients of the polynomial and the suspected root. Here’s a brief overview of the process:
- Write down the coefficients of \( f(x) = 6x^3 + 23x^2 + 3x - 14 \).
- Choose \( c = 1 \), since \( x = 1 \) is a root.
- Perform synthetic division, using these coefficients: \( 6, 23, 3, -14 \).
Quadratic Formula
The quadratic formula is a powerful tool used to find the roots of a quadratic equation, which is an equation of the form \( ax^2 + bx + c = 0 \). The formula is expressed as:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]In the exercise, after using synthetic division, the polynomial \( 6x^2 + 29x + 32 \) is left to be solved. This equation is a quadratic, so the quadratic formula is perfectly suited to solve for its roots.
Applying the formula, we correctly identified the roots:
Applying the formula, we correctly identified the roots:
- \( x = -\frac{4}{3} \)
- \( x = -4 \)
Polynomial Factorization
Polynomial factorization is the process of breaking down a polynomial into a product of simpler polynomials. The goal is to express the original polynomial function as a product of factors and identify its roots. For the exercise's polynomial \( f(x) = 6x^3 + 23x^2 + 3x - 14 \), we discovered that its real roots are \( x = 1 \), \( x = -\frac{4}{3} \), and \( x = -4 \). Through factorization, the original polynomial can be expressed as:
- \((x - 1)(3x + 4)(2x + 8)\)