Chapter 2: Problem 7
Find two functions defined implicitly by the given equation. Graph each function. $$ (y-1)\left(y-x^{3}\right)=0 $$
Short Answer
Expert verified
Two functions are \(y=1\) and \(y=x^3\).
Step by step solution
01
Analyze the Given Equation
The given equation is \((y-1)(y-x^3)=0\). This is a product of two factors equal to zero, meaning at least one of the factors must be zero for the equation to hold.
02
Solve for Function 1: First Factor
Set the first factor to zero: \(y-1=0\). Solving this equation gives \(y=1\). This represents the horizontal line function where \(y\) is constantly 1 for all \(x\).
03
Solve for Function 2: Second Factor
Set the second factor to zero: \(y-x^3=0\). Solving this equation gives \(y=x^3\). This represents the cubic function where \(y\) varies with \(x\) raised to the third power.
04
Graph Each Function
Graph the functions found: \(y=1\) is a horizontal line across the graph at \(y=1\). \(y=x^3\) is a cubic curve that passes through the origin and is symmetrical about the origin, appearing s-like.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cubic Function
A cubic function is a type of polynomial equation represented by the general form \( y = ax^3 + bx^2 + cx + d \), where \( a \), \( b \), \( c \), and \( d \) are constants, and \( a eq 0 \). It is characterized by its highest degree being three. This means that the cube of the variable \( x \) is included in the equation, making its graph a curve that appears s-shaped or serpentine.The specific cubic function identified in our exercise is \( y = x^3 \). In this case, the graph takes a very distinctive shape:
- It passes through the origin (0,0).
- The graph is symmetric about the origin, a property referred to as being an odd function.
- For positive \( x \), \( y \) increases rapidly as \( x^3 \) grows.
- For negative \( x \), \( y \) decreases, reflecting through (0,0) in a similar but inverse manner.
Horizontal Line
A horizontal line in a graph represents a function where the output (or \( y \) value) remains constant for all inputs (\( x \) values). The general form of a horizontal line is \( y = k \), where \( k \) is a constant. This means no matter what \( x \) value you choose, \( y \) always equals \( k \).In the given exercise, the equation \( y = 1 \) represents such a horizontal line:
- This indicates that the value of \( y \) is consistently 1, regardless of the \( x \) value.
- The line extends infinitely in both the positive and negative directions along the \( x \)-axis.
Graphing Implicit Functions
Graphing implicit functions involves understanding equations that define the relationship between \( x \) and \( y \) indirectly. Instead of being isolated as \( y = f(x) \), these functions are often present in forms like \( F(x, y) = 0 \). Such is the case in the exercise with the equation \((y-1)(y-x^3)=0\).Here’s how you graph these functions:
- Identify potential solutions: Since at least one factor must be zero in our equation, solve for \( y = 1 \) and \( y = x^3 \).
- Graph each solution: For the function \( y = 1 \), draw a horizontal line at \( y = 1 \). For \( y = x^3 \), plot the cubic curve passing through (0,0) with its characteristic serpentine shape.
- Consider intersections and overlaps: Both solutions are graphed on the same coordinate system. Points where they might intersect or overlap should be noted, especially for complex implicit equations beyond linear or cubic simplicity.