Chapter 2: Problem 38
The given function \(f\) is one-to-one. Find \(f^{-1}\). Proceed as in part (b) of Example 4 and find the domain and range of \(f^{-1}\). Then find the range of \(f\). $$ f(x)=10-\frac{1}{5 x} $$
Short Answer
Expert verified
The inverse is \( f^{-1}(x) = \frac{1}{5(10-x)} \), domain is \((10, \infty)\), range is \((-\infty, 0) \cup (0, \infty)\); range of \( f \) is \( (-\infty, 10) \cup (10, \infty) \).
Step by step solution
01
Verify the Function is One-to-One
Since it is given that function \( f(x) = 10 - \frac{1}{5x} \) is one-to-one, this means there is a unique \( y \) for each \( x \). This is important because only one-to-one functions have inverses.
02
Swap Variables
In finding the inverse, we switch \( x \) and \( f(x) \). Write the equation as \( x = 10 - \frac{1}{5y} \) where \( y = f^{-1}(x) \).
03
Solve for y
Rearrange \( x = 10 - \frac{1}{5y} \) to solve for \( y \). Add \( \frac{1}{5y} \) to both sides to get \( \frac{1}{5y} = 10 - x \), then multiply both sides by \( 5y \) to get \( 1 = 5y(10-x) \). Solve for \( y \) to get \( y = \frac{1}{5(10-x)} \).
04
Write the Inverse Function
The inverse function is \( f^{-1}(x) = \frac{1}{5(10-x)} \).
05
Find the Domain of the Inverse
The domain of \( f^{-1}(x) \) is the range of the original function \( f(x) \). Since \( f(x) = 10 - \frac{1}{5x} \), it takes inputs from all real numbers except \( x = 0 \). Solve \( 10 - \frac{1}{5x} = y \), which implies \( y eq 10 \), hence the range of \( f \) is \((-\infty, 10) \cup (10, \infty)\). So, the domain of \( f^{-1} \) is \((10, \infty)\).
06
Find the Range of the Inverse
The range of \( f^{-1}(x) \) is the domain of the original function \( f(x) \), which is all real numbers except \( x = 0 \). Thus, the range of \( f^{-1} \) is \((-\infty, 0) \cup (0, \infty)\).
07
Determine the Range of the Function
The range of \( f \) is \( (-\infty, 10) \cup (10, \infty) \) as derived in Step 5.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
One-to-One Function
A one-to-one function is a special type of function where every element in the domain corresponds to a unique element in the range. This means that no two different inputs (or "x" values) produce the same output (or "y" value).
- In mathematical terms, for a function to be one-to-one, if \(f(a) = f(b)\), then it must follow that \(a = b\).
- One-to-one functions are essential for finding inverses. If a function is not one-to-one, we cannot uniquely determine an inverse function.
Domain and Range
The domain and range of a function describe the set of allowable inputs and attainable outputs, respectively. This is a fundamental aspect of understanding functions.
- The domain of a function is the set of all possible input values. For \(f(x) = 10 - \frac{1}{5x}\), the domain includes all real numbers except zero, since division by zero is undefined.
- The range of a function is the set of all possible output values. For the function given, it can approach, but not actually reach, 10, leading to a range of \((-fty, 10) \cup (10, \infty)\).
Solving Equations
Solving equations is a fundamental part of finding inverse functions. The process usually involves algebraic manipulation to isolate the variable of interest. Here’s how you do it, step by step:1. **Switch Variables**: When finding the inverse, swap the roles of \(x\) and \(f(x)\). If \(f(x) = y\), write the equation as \(f(y) = x\).2. **Isolate \(y\)**: Use algebraic steps to solve for \(y\). This might involve adding, subtracting, multiplying, dividing, or even factoring, depending on the function.For example, in the given exercise:- Start with \(x = 10 - \frac{1}{5y}\).- Add \(\frac{1}{5y}\) to both sides to get \(\frac{1}{5y} = 10 - x\).- Finally, solve for \(y\) to get \(y = \frac{1}{5(10-x)}\).This manipulation helps us express \(y\) in terms of \(x\), taking us a step closer to identifying the inverse function.
Function Notation
Function notation is a way of writing functions that allows clear communication of the input-output relationship. It uses symbols like \(f(x)\) to represent the output of the function with respect to a given input \(x\).
- Pay attention to the "\(f^{-1}(x)\)" notation, which specifically signifies the inverse of the function \(f\).
- The inverse function \(f^{-1}(x)\) reverses the effect of the original function \(f(x)\), mapping outputs back to their original inputs.