/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 In Problems \(9-34\), sketch the... [FREE SOLUTION] | 91Ó°ÊÓ

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In Problems \(9-34\), sketch the graph of the given piece wise-defined function. Find any \(x\) - and \(y\) intercepts of the graph. Give any numbers at which the function is discontinuous. $$ y=|| x|-2| $$

Short Answer

Expert verified
The graph has x-intercepts at x = 2, -2, a y-intercept at y = 2, and is continuous.

Step by step solution

01

Understand the Function

The given function is a piecewise function of the form \[ y = ||x| - 2| \] This means you need to evaluate the expression for both positive and negative values of \(x\), considering the nested absolute values.
02

Break Down Absolute Values

We need to separately consider the expressions inside the absolute values:1. \(|x| = x\) when \(x \geq 0\) and \(|x| = -x\) when \(x < 0\).2. \(|x|-2 = x-2\) when \(x \geq 2\), \(|x| - 2 = 2-x\) for \(-2 \leq x < 2\), and \(|x| - 2 = -x-2\) when \(x < -2\).3. \(||x|-2| = |x - 2|\) when \(x \geq 2\), \(||x|-2| = 2-x\) when \(-2 \leq x < 2\), and \(||x|-2| = |2+x|\) when \(x < -2\).
03

Analyze Different Intervals

Analyze the function in different intervals:- For \(x \,\geq \ 2\), \[ y = |x-2| = x - 2 \]- For \(-2 \leq x < 2\), \[ y = 2 - x \]- For \(x < -2\), \[ y = |-x-2| = -x - 2 \]
04

Plot Each Interval

Now, sketch the graph by plotting each part:- For \(x \geq 2\), the line \(y = x-2\) starts from the point \((2, 0)\).- For \(-2 \leq x < 2\), plot the decreasing line \(y = 2 - x\) starting from \((0, 2)\) to \((2, 0)\).- For \(x < -2\), plot the line \(y = -x - 2\) which increases starting from \((-2, 0)\) upwards.
05

Identify Intercepts

- The x-intercepts are where the graph crosses the x-axis. This happens at \(x = 2\) and \(x = -2\).- The y-intercept is where the graph crosses the y-axis, at \(y = 2\) when \(x = 0\).
06

Check for Discontinuities

This function is continuous for all real values of \(x\). The absolute value function generally does not create discontinuities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absolute Value Functions
Absolute value functions involve an expression within the absolute value symbols \(|\cdot|\). They transform any negative value inside to its positive counterpart, essentially measuring the 'distance' from zero on a number line. When dealing with absolute value functions that are nested, like in our exercise \(||x|-2|\), understanding the layers of absolute values becomes essential.

In such cases, we evaluate the expression inside the outer absolute value first, followed by applying the outer absolute value. When nested, these functions can significantly affect the shape of a graph by flattening curves and removing all negative outputs, reflecting them as positives.
  • Inside absolute value \(|x|\): If \(x \geq 0\), then \(|x| = x\); if \(x < 0\), then \(|x| = -x\).
  • Adding the next layer: \(||x|-2|\), which creates a piecewise approach, showing the effect of each step on the resultant graph.
Always break down each step carefully to ensure accurate representation of the function's behavior.
Graphing Functions
Graphing functions require the transformation of equation expressions into their visual line representations on a coordinate plane. With piecewise functions, it means sketching multiple "pieces" of lines or curves that together form the overall graph. For the function \(||x|-2|\), it's crucial to recognize the distinct segments defined by our computation:
  • For \(x \geq 2\), where \(|x-2| = x-2\), graph begins as an increasing line from \((2, 0)\).
  • For \(-2 \leq x < 2\), the equation simplifies to \(y = 2 - x\), resulting in a decreasing line segment.
  • And for \(x < -2\), the equation becomes \(|2+x| = -x-2\), an increasing line starts from another section.
Each segment aligns precisely, showing how the transition from one part of the function to the next articulates on the graph visually. Understanding these transitions is key in painting a complete picture of the function's behavior.
Function Intercepts
Function intercepts are critical points on a graph where the function crosses the axes. The x-intercept occurs where the graph touches or crosses the x-axis, which means the function value \(y\) is zero. Similarly, the y-intercept is where the graph intersects the y-axis, with \(x = 0\).
  • For the function \(||x|-2|\), the x-intercepts are at \(x = 2\) and \(x = -2\), given these satisfy the equation \(y = 0\).
  • The y-intercept is at \((0, 2)\) because plugging \(x = 0\) into the equation \(||0|-2|\) results in \(y = 2\).
Always calculate intercepts directly, as they offer crucial insight into the graph's orientation and alterations around key points in the coordinate plane. This step helps identify the function's initial and end points on each axis.
Discontinuities in Graphs
Discontinuities in graphs are points where the function does not smoothly transition from one part to the next. They appear as breaks, jumps, or holes. However, piecewise functions like our \(||x|-2|\) might seem to have such potential due to its segmented nature but are continuous for all real numbers in this case.
  • Despite the function having different expressions over various intervals, they share endpoints smoothly, ensuring continuity.
  • Each piece of the function connects seamlessly to the next on the graph, forming a continuous, unbroken line across the range.
This continuity comes from how absolute values reshape the graph layers, avoiding cuts or breaks typical of other piecewise-defined functions that lack smooth transitions.

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Most popular questions from this chapter

Suppose \(f\) is a continuous function that is increasing (or decreasing) for all \(x\) in its domain. Explain why \(f\) is necessarily one-to-one.

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