Chapter 2: Problem 21
Use the sign-chart method to find the domain of the given function \(f\). $$ f(x)=\sqrt{25-x^{2}} $$
Short Answer
Expert verified
The domain is \([-5, 5]\).
Step by step solution
01
Understand the Function
The function given is \( f(x) = \sqrt{25 - x^2} \). It contains a square root, which implies that the expression inside the square root, \(25 - x^2\), must be non-negative for \(f(x)\) to be defined with real numbers.
02
Set the Expression Non-negative
To ensure the expression inside the square root is non-negative, solve the inequality \( 25 - x^2 \geq 0 \). This will determine the values of \(x\) for which the function is defined.
03
Solve the Inequality
Rewrite the inequality as \( 25 \geq x^2 \) or \( x^2 \leq 25 \). Taking the square root of both sides gives \( -5 \leq x \leq 5 \). These are the values \(x\) can take while keeping \(f(x)\) defined.
04
Create the Sign-Chart
The critical points for the sign chart are at \(x = -5 \) and \(x = 5\). Test intervals on the number line: \((-\infty, -5)\), \((-5, 5)\), and \((5, \infty)\). Since \(25 - x^2\) changes from positive to negative at \(x = -5\) and from negative to positive at \(x = 5\), it is positive within \(-5, 5\).
05
Determine the Domain
The domain consists of all values of \(x\) where \(25 - x^2\) is non-negative. The function \(f(x)\) is defined for \(x\) on the interval \([-5, 5]\). This means \(x\) can be any value from \(-5\) to \(5\), inclusive, where the expression inside the square root remains non-negative.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
The domain of a function is the complete set of possible values of the independent variable that make the function work without any issues. For instance, if we look at the function \( f(x) = \sqrt{25 - x^2} \), the inner expression \( 25 - x^2 \) must be non-negative, otherwise, the square root becomes undefined for real number operations.
Hence, not every value of \( x \) will work. To find the domain, we solve for values of \( x \) such that \( 25 - x^2 \geq 0 \). This process involves isolating the variable \( x \) until we have a clear inequality that describes valid \( x \) values. This gives us the range of \( x \) values for which the original function \( f(x) \) is defined, in this case, the interval \([-5, 5]\).
Key points to remember:
Hence, not every value of \( x \) will work. To find the domain, we solve for values of \( x \) such that \( 25 - x^2 \geq 0 \). This process involves isolating the variable \( x \) until we have a clear inequality that describes valid \( x \) values. This gives us the range of \( x \) values for which the original function \( f(x) \) is defined, in this case, the interval \([-5, 5]\).
Key points to remember:
- Always check under a square root or in a denominator for problematic values.
- Solve inequalities or equations that arise from these conditions.
- The result provides the domain, which may be one interval or a combination of intervals.
Inequality Solving
Inequality solving is a method used to find the set of values for a variable that satisfies an inequality. In our example, we need to determine where \( 25 - x^2 \geq 0 \). Inequalities can usually be solved by manipulating them much like equations:
First, ensure the inequality sign is correct for your original statement. Then, rearrange and simplify as needed. In this example, we rearrange to \( 25 \geq x^2 \) (or \( x^2 \leq 25 \)).
Next, take the square root of both sides to find \( -5 \leq x \leq 5 \). These bounds show where the inequality holds true. Intervals obtained from inequalities are critical for determining the eventual domain of the function.
Solutions to inequalities:
First, ensure the inequality sign is correct for your original statement. Then, rearrange and simplify as needed. In this example, we rearrange to \( 25 \geq x^2 \) (or \( x^2 \leq 25 \)).
Next, take the square root of both sides to find \( -5 \leq x \leq 5 \). These bounds show where the inequality holds true. Intervals obtained from inequalities are critical for determining the eventual domain of the function.
Solutions to inequalities:
- Solve them step-by-step like equations, respecting the inequality signs.
- Create intervals based on where the inequality holds true or is solved.
- Consider these intervals when examining domains or ranges of functions.
Square Root Function
A square root function involves an expression that requires a non-negative quantity under the square root symbol. The expression \( f(x) = \sqrt{25 - x^2} \) is only defined when \( 25 - x^2 \) is zero or positive because square roots of negative numbers do not yield real results (excluding complex numbers).
When working with square roots:
When working with square roots:
- Set up conditions inside the root to ensure they are non-negative.
- Solve these conditions to find valid inputs.
- Understand that the square root function is only defined for non-negative inputs.
- Square root functions often result in a half-parabolic graph limited to one side of the x-axis.
Critical Points
Critical points in this context are values in the domain where the expression related to a function changes behavior, such as changing sign or hitting zero. In the function \( f(x) = \sqrt{25 - x^2} \), critical points appear wherever the expression \( 25 - x^2 \) equals zero.
For this particular function, these critical points are at \( x = -5 \) and \( x = 5 \). They are crucial because:
For this particular function, these critical points are at \( x = -5 \) and \( x = 5 \). They are crucial because:
- They represent points where the expression inside the square root reaches zero.
- Critical points help set bounds for the domain since outside of these points, the expression could become negative.
- They act as breaks in the intervals on a sign chart, illustrating where \( 25 - x^2 \) changes from positive to negative.
- Identify where the expression hits zero.
- Test intervals around these points if necessary.
- Use these points to define the boundaries of valid input ranges.