Chapter 2: Problem 12
Fill in the table where \(g\) is an odd function. $$ \begin{array}{|c|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline f(x) & -2 & -3 & 0 & -1 & -4 \\ \hline g(x) & 9 & 7 & -6 & -5 & 13 \\ \hline(g \circ f)(x) & & & & & \\ \hline \end{array} $$
Short Answer
Expert verified
The completed table for \((g \circ f)(x)\) is: 6, 5, 0, -7, -13.
Step by step solution
01
Understand Odd Functions
An odd function has the property \(g(-x) = -g(x)\). This will be essential for determining the values of \((g \circ f)(x)\).
02
Calculate \(f(0)\) and \(g(f(0))\)
Since \(f(0) = -2\), we then calculate \(g(-2)\). Using the odd function property, \(g(-2) = -g(2) = 6\).
03
Calculate \(f(1)\) and \(g(f(1))\)
\(f(1) = -3\), so we find \(g(-3)\). Since \(g\) is odd, \(g(-3) = -g(3) = 5\).
04
Calculate \(f(2)\) and \(g(f(2))\)
\(f(2) = 0\). Note that \(g(0)\) is undefined in the table but generally, \(g(0)=0\) for odd functions. Therefore, \(g(0) = 0\).
05
Calculate \(f(3)\) and \(g(f(3))\)
\(f(3) = -1\), hence \(g(-1) = -g(1) = -7\).
06
Calculate \(f(4)\) and \(g(f(4))\)
\(f(4) = -4\), so \(g(-4) = -g(4) = -13\).
07
Fill in the Table
Use the calculated values from the previous steps to fill in the blank row, \((g \circ f)(x)\): 6, 5, 0, -7, -13.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Composition of Functions
The composition of functions is a fundamental concept in mathematics that combines two functions to create a new one. Here's how it works: if you have a function \( f(x) \) and another function \( g(x) \), the composition of these functions, denoted as \( (g \circ f)(x) \), means you first apply \( f \) to \( x \), and then apply \( g \) to the result of \( f(x) \). It can be thought of as substituting one function into another.
This is formulated as \( (g \circ f)(x) = g(f(x)) \). Essentially, you're taking the output from \( f(x) \) and using it as the input for \( g(x) \).
This is formulated as \( (g \circ f)(x) = g(f(x)) \). Essentially, you're taking the output from \( f(x) \) and using it as the input for \( g(x) \).
- Begin by evaluating the inner function \( f(x) \).
- Then, take the result of \( f(x) \) and use it as the input to \( g(x) \).
- The result is your \( (g \circ f)(x) \), which represents the composite function.
Function Properties
Understanding the properties of functions, such as whether a function is odd, is vital to working with them effectively. An odd function is defined by the property \( g(-x) = -g(x) \). This means that the function has rotational symmetry about the origin.
- For an odd function, the graph will appear the same if rotated 180 degrees about the origin.
- This implies that for any input \( x \), the output at \( -x \) is the negative of the output of \( x \).
- Begin by identifying the algebraic property that defines the function, in this case, the odd property.
- Use the given values of the function, and apply the property to explore and find the new values.
- For instance, if \( g(2) = -6 \), we know \( g(-2) = 6 \) without recalculating directly, thanks to its odd nature.
Precalculus Concepts
Precalculus serves as a bridge between algebra and calculus, introducing concepts that are necessary for advanced mathematical study. Some of these include:
- Understanding Functions: Precalculus deepens the understanding of functions, focusing on types like linear, quadratic, polynomial, and rational functions.
- Analyzing Function Behavior: Learn to analyze how functions behave with transformations, compositions, and inversions. Composition, as seen with \( (g \circ f)(x) \), is one critical aspect of function behavior.
- Function Properties: Grasping properties such as whether functions are even or odd helps in graphing and understanding symmetry.